Week

I just updated to TeX Live 2026. Now when I compile the following, I get ! LaTeX Error: Command \proof already defined. The problem disappears if I remove the \DocumentMetadata line: \DocumentMetadata{pdfstandard=UA-2} \documentclass{article} \usepackage{amsmath} \usepackage{ntheorem} \theoremstyle{nonumberplain} \newtheorem{proof}{Proof} \begin{document} You want proof? \end{document}

I want to define two macros, let's call them \coalesce and \coalescegroup. \coalescegroup is only ever used within \coalesce (names are inspired by the Postgres command). \coalesce prints its input if and only if every instance of \coalescegroup within that input prints something non-blank (where blankness is tested by \tl_if_blank:nTF or a variant). Otherwise it discards its input. \coalescegroup divides its input at every instance of some delimiter -- say \coalesceor, and then prints the first division which is not blank (by the same test). If all are blank, it prints nothing. The motivation is templating in class files. I maintain class files for things like handouts and syllabi, where I often want to do things like print 'my email is ', but only if my email is defined. Usually that would be something like \ifblank{\email}{}{My email is: \email} but with coalesce it can be \coalesce{My email is: \coalescegroup{\email}}, which to me makes much more sense. I also like the idea of setting up active characters for these things within coalesce, so that the last example could be written \coalesce{My email is: <\email>}, but that's a separate issue. How can I do this? Below is a MWE of what I've tried so far. I feel like it's close, but not quite there. My idea was to define \coalesceor to evaluate to itself, then define \coalescegroup to exhaustively expand its input, split it on \coalesceor (which will survive the expansion, because it expands to itself), then map over the result and print the first non-blank element, or the token \__coalesce_stop if they're all blank. Then \coalesce uses the same trick: define \__coalesce_stop to expand to itself, \coalesce then just expands its input, checks to see if the resulting token list includes \__coalesce_stop, and prints it all just if it doesn't. I think the basic idea is probably OK, but I can't get the expl3 details right. \documentclass{article} \ExplSyntaxOn % First attempt at coalescegroup % Define a boolean for 'already done' \bool_new:N \__coalesce_coalescegroup_bool % Processor for arguments \cs_new:Npn \__coalesce_coalescegroup_step #1 { \bool_if:NF \__coalesce_coalescegroup_bool \tl_if_blank:nF #1 % If the group isn't blank, then ... % ... we will (eventually) print this arg. {\tl_set:Nn \tl_tmpa_tl {#1} % ... and set the boolean. \bool_set_true:N \__coalesce_coalescegroup_bool } } % Disjunction token \cs_new:Npn \coalesceor { \exp_not:N \coalesceor } \NewDocumentCommand{\coalescegroup}{ m }{ \bool_set_false:N \__coalesce_coalescegroup_bool % Set the scratch list a to be empty. \tl_set:Nn \tl_tmpa_tl {\__coalesce_stop} \tl_set:Nn \tl_tmpb_tl {\exp_args:Ne {\SplitList{\coalesceor}} { #1 }} \ProcessList \tl_tmpb_tl { \__coalesce_coalescegroup_step } % Print the output \tl_tmpa_tl } % Second attempt \NewDocumentCommand{\newcoalescegroup}{ >{\SplitList{\coalesceor}} m }{ \tl_new:N \coalescegroup_output_tl \tl_set:Nn \coalescegroup_output_tl \__coalesce_stop \tl_set:Nn \tl_tmpa_tl {\exp_args:ne { #1 }} \tl_map_inline:Nn \tl_tmpa_tl { % If the token is non-empty ... \tl_if_blank:nF #1 { % ... then write it to output var \coalescegroup_output_tl \tl_set:Nn \tl_tmpa_tell #1 % ... and break. \tl_map_break: } } % Leave result in the input stream \coalescegroup_output_tl } % Blocker token \cs_new:Npn \__coalesce_stop { \exp_not:N \__coalesce_stop } \NewDocumentCommand{\coalesce}{ m }{ % Print nothing if the blocker cs is found. \exp_args:Ne \tl_if_in:nnTF { #1 } \__coalesce_stop {} { #1 } } \ExplSyntaxOff % Testing values \def\blank{} \def\something{something} \begin{document} \section{First attempt} % Should print nothing, prints `foo bar' \coalesce{foo \coalescegroup{\blank} bar} % Should print nothing (because the second coalesce group fails), % prints `foo something bar baz' \coalesce{foo \coalescegroup{\something} bar \coalescegroup{\blank} baz} % Should print `foo something bar', and does! \coalesce{foo \coalescegroup{\blank \coalesceor \something} bar} % Should print `foo literal bar', and does! \coalesce{foo \coalescegroup{\blank \coalesceor literal} bar}\ \section{Second attempt} % Should print nothing, prints `foo bar' \coalesce{foo \newcoalescegroup{\blank} bar} % These all produce Error: Control sequence \coalescegroup_output_tl % already defined: % % \coalesce{foo \newcoalescegroup{\something} bar \newcoalescegroup{\blank} baz} % \coalesce{foo \newcoalescegroup{\blank \coalesceor \something} bar} % \coalesce{foo \newcoalescegroup{\blank \coalesceor literal} bar} \end{document} TIA.

I know that modern 8bit TeX implementations (TeXLive) may enable both MLTeX and encTeX extensions. My question is thus both technical and historical. I am enabling all three extensions (with eTeX) for some custom Plain pdfTeX macros, but I'd like to understand the processing order, and thus the interaction, amongst these extensions in terms of reencoding and hyphenation. So, assume I have an hyphenation pattern including with 1n defined in the format, that I have a pdfTeX with all three extensions enabled, and I reencode and substitute ñ, as follows, to enable UTF-8 input: \mubyte ^^D1 ^^C3 ^^91 \endmubyte % Ñ \mubyte ^^F1 ^^C3 ^^B1 \endmubyte % ñ \charsubdef ^^D1 = '176 ^^4E % Ñ \charsubdef ^^F1 = '176 ^^6E % ñ My actual question is this: in this case, it is clear to me that the hyacc-cm macros, to enable hyphenation in the remaining part of a composite word (say: "pi-ña-ta"), are unnecessary to enforce hyphenation even in Computer Modern fonts, if I define the \chars for Latin1 and compatible encodings as follows: \catcode^^D1=\active \catcode^^F1=\active \def^^D1={\~N} \def^^F1={\~n} I ran some experiments to check whether this was true, rather successfully, but I cannot understand exactly why. I haven't seen (maybe haven't searched enough for) any explanation of the interaction between MLTeX and encTeX that explains this behavior. Some references to some documentation are surely welcome.

Two aligned environments inside two equation environments (obviously, two tags), now I want to align the 4 = signs. I know I can place the middle text inside the \shortintertext or \intertext provided by the mathtools package, but how to keep only 2 numbered tags keep in the middle of each aligned group vertically? \documentclass{article} \usepackage{mathtools} \begin{document} some text \begin{equation}\label{eq:eta_quantum} \begin{aligned} abc & = defghij\\ & = \int f(x) dx, \end{aligned} \end{equation} some text \begin{equation}\label{eq:eta_classical} \begin{aligned} defghi & = defghij\\ & = \int f(x) dx, \end{aligned} \end{equation} \end{document}

I have come across an interesting difference in how a PDF produced by TikZ is rendered by different PDF viewers. The following MWE isolates the issue: \documentclass{article} \usepackage{tikz} \usetikzlibrary{patterns,fadings} \begin{document} \begin{tikzpicture} % Pattern only \fill[draw,pattern=north west lines] (0,0) rectangle (3,.4); % Fading only \fill[draw,path fading=east] (0,-1) rectangle (3,-.6); % Pattern + fading \fill[draw,pattern=north west lines,path fading=east] (0,-2) rectangle (3,-1.6); \end{tikzpicture} \end{document} Left: Adobe Acrobat. Right: WinEdtPDF. The same PDF file is shown in both viewers. In WinEdtPDF the first two rectangles are rendered correctly. The problem appears only in the third one, where pattern=north west lines and path fading=east are used together: the hatching is not rendered correctly. Thus, pattern=north west lines works by itself, and path fading=east works by itself. The rendering difference appears only when the two TikZ mechanisms are combined. The same PDF is rendered correctly in Adobe Acrobat, Microsoft Edge, and Firefox. The same defect as in WinEdtPDF is also visible in Google Drive's PDF preview. I initially reported this to the WinEdt developer. Alex Simonic explained that WinEdtPDF uses PDFium for rendering and that the behavior observed there is a limitation of PDFium rather than of WinEdtPDF itself: https://github.com/WinEdt-Team/WinEdt-Support/discussions/131#discussioncomment-18627725 So my question is about the TikZ/PDF side of this behavior: what does TikZ write into the PDF when a pattern and path fading are combined, and what is special about this construction that makes different PDF rendering engines handle it differently?

I want to draw a simple arrow with its tail towards the C-H bond and its arrowhead pointing to the plus charge. Here is what I have so far: \documentclass[12pt]{article} \special{papersize=3in,5in} \usepackage{chemfig} \begin{document} \schemestart \chemfig{(-[:90]H)(-[:150])(-[:210])(-[:330]{\charge{330:3pt=$\scriptstyle \oplus$}{}}) } \arrow{->} \chemfig{{\charge{180:3pt=$\scriptstyle \oplus$}{}}(-[:0])(-[:120])(-[:240])} \schemestop \end{document} Also, for some reason, I can't add images

Mathtools package admits width and height adjusts with PDFLaTeX, but with LuaLaTeX width and height is not adjustable. How to adjust or use native mathtools? \documentclass{article} \usepackage[spanish,es-notilde]{babel} \usepackage{amsmath,amssymb,mathtools} % amssymb, en LuaLaTeX, debe cargarse antes que unicode-math \usepackage{fontspec} \usepackage{unicode-math} \setmainfont{TeX Gyre Pagella} \setmathfont{TeX Gyre Pagella Math} \usepackage{xcolor} \begin{document} \[ B(x)\underbracket[0.5pt]{A(z)}_{\text{Esto es una prueba}}C(w) B(x)\underbracket{A(z)}_{\text{Esto es una prueba}}C(w) \] \[ B(x)\overbracket[0.5pt]{A(z)}^{\text{\footnotesize Esto es una prueba}}C(w) B(x)\overbracket{A(z)}^{\text{\footnotesize Esto es una prueba}}C(w) \] \end{document}

I need to show the structure of the products and reactants in a chemical equation. However, the arrow is not horizontally aligned to the center of the chemical figures. Here is the commands: \documentclass[12pt]{article} \special{papersize=3in,5in} \usepackage{chemmacros} \usepackage{chemfig} \usepackage[version=4] {mhchem} \begin{document} \begin{reaction*} \chemfig{(-[:210])(-[:330]OH)} ->[O] \chemfig{(-[:210])(=[:330]O)} \end{reaction*} \end{document}

Is there a remote possibility to have, -\infty and +\infty, below the real line using only the package nl-interval? \documentclass{article} \usepackage{nl-interval} \begin{document} \begin{tikzpicture} \nlAxisX{-2}{5} \nlnuminf[pattern=north west lines]{1.5}[+3]{c}[.2] \end{tikzpicture} \begin{tikzpicture} \nlAxisX{-2}{5} \nlinfnum[pattern=north west lines]{1}[-5]{o}[.2] \end{tikzpicture} \begin{tikzpicture} \nlAxisX{-2}{5} \nlnumnum{-1}{o}{3}{c}[.2] \end{tikzpicture} \end{document}

This source compiles just fine with the line \DocumentMetadata{tagging=off} commented out, as shown. Why, if I uncomment that line, do I get a "TeX capacity exceeded" at line 15, and how can this be fixed? \NeedsTeXFormat{LaTeX2e}[2026-06-01] % !TEX program = lualatex %\DocumentMetadata{tagging=off} \documentclass{book} \usepackage{fontspec} \usepackage{lua-unicode-math} \usepackage[thmtools-compat]{keytheorems} \newkeytheoremstyle{thmstyle}{} \AtBeginDocument{\newkeytheorem{theorem}[name=Theorem,style=thmstyle,numberwithin=chapter]} \usepackage{hyperref} \begin{document} \chapter{A chapter} \section{The section} \begin{theorem}[A key theorem] Some theorem text \end{theorem} \end{document}

Consider the following example: \documentclass{article} \usepackage{lipsum} \usepackage{enumitem} \begin{document} \begin{description}[style=nextline] \item[First item] \lipsum[11] \item[Second item] \begin{itemize} \item first subitem \item second subitem \end{itemize} \end{description} \end{document} Why itemize list in above example doesn't start in new line as other normal text do? Is this a bug? Well, I can manage this behaviour by adding \mbox{} after description label.

Using Latex Overleaf, I want to create a \subsubsubsection with \paragraph and \subsubsubsubsection with \subparagraph in \documentclass{amsart}. However, there are two problems: The \subsubsubsection returns an error sign If I add an * to the \subsubsubsection and \subsubsubsubsection (e.g., \subsubsubsection*), it won't disappear from the table of contents. \documentclass[11pt]{amsart} \newcommand{\subsubsubsection}{\paragraph} \newcommand{\subsubsubsubsection}{\subparagraph} \setcounter{secnumdepth}{5} \setcounter{tocdepth}{5} \title[Title]{Title} \author[Arbuja]{Arbuja Krishnan} \address{None, Unaffiliated, United States} \begin{document} \maketitle \tableofcontents \section{adhfk} \subsection{aksad} \subsubsection{fsajk} \subsubsubsection{agrg} \subsubsubsubsection{sjaf} \subsubsection{aehkfg} \subsubsubsubsection*{asfkdh} %We want this invisible from the table of contents%) \subsubsubsubsection*{asdgj} %We want this invisible from the table of contents%) \end{document} Question: How do I fix the problems above the code?

This is an extension of Replacing a Circle of Asterisks with Tikz Colored Stars Consider the code: \documentclass{book} \usepackage{tikz} \usetikzlibrary{shapes.geometric} \definecolor{thisblue}{RGB}{10,49,97} %\definecolor{thisred}{RGB}{179,25,66} \begin{document} \thispagestyle{empty} \pagecolor{thisblue} \noindent {\LARGE\bfseries{\textcolor{white}{Twelve even-spaced stars:}}} \vspace{10pt} \begin{center} \begin{tikzpicture} \foreach \k in {0,30,...,330} \node[ shape=star, star points=5, star point ratio=2.5, minimum size=0.8cm, fill=white, draw=white ] at (\k:3.5cm) {}; \end{tikzpicture} \end{center} \vspace{40pt} \noindent {\LARGE\bfseries{\textcolor{white}{Supposed to be thirteen even-spaced stars:}}} \vspace{10pt} \begin{center} \begin{tikzpicture} \foreach \k in {0,27.69,55.38,...,332.28} \node[ shape=star, star points=5, star point ratio=2.5, minimum size=0.8cm, fill=white, draw=white ] at (\k:3.5cm) {}; \end{tikzpicture} \end{center} \end{document} which produces: The first problem (regarding the second set of stars) is that there are only twelve stars (not thirteen). The second problem should be (the way I thought I have estimated it) should be roughly according to the thirteen (original colonies) represented as stars in the original (Betsy Ross) flag (See: Betsy Ross Flag): QUESTION: What am I doing wrong? How may I replicate the star-distribution on Betsy Ross' flag? (Incidentally, I still do not understand how my code did not display thirteen stars for the second figure.) Thank you.

How to adjust the opacity of the solution background in exam class? \documentclass[12pt]{exam} \usepackage[dvipsnames,x11names,svgnames]{xcolor} \shadedsolutions \colorlet{SolutionColor}{cyan!33} \usepackage{tikz} \usepackage{watermark} %-------------------------------- \watermark{ \begin{tikzpicture}[remember picture,overlay] \node [scale=1.1824,rotate=45,anchor=base,shift={(0em,6em)}] at (current page.center) [text width=1.64\linewidth,rounded corners,align=center] {{\color{pink} \parbox[][][m]{32cm}{ \LARGE{ {\center \hspace{6em}XXXXXXXXXXXXXX YYYYYYYYYYYYYYYY ZZZZZZZZZZZZZZZZ .......}}} }}; \end{tikzpicture} } \printanswers \begin{document} \begin{questions} \question $2+4=$ \begin{solution} $2+4=6$ \end{solution} \question $5+6$ \end{questions} \end{document}

If we run TeX on this example1.tex \hfuzz=\maxdimen \hsize=0pt \hyphenchar\font=`^^ff \hskip0pt error \bye in log file we get Missing character: There is no ^^ff in font cmr10! But if we change \language in example2.tex, this error message is not produced. Why? \language 1 \hfuzz=\maxdimen \hsize=0pt \hyphenchar\font=`^^ff \hskip0pt error \bye EDIT Let us load patterns. Create this my.tex: \input plain \language 1 \patterns {z4zy} \dump Then run tex -ini my to create my.fmt. Then run the example with new format: tex -fmt my example2 The warning in log file still does not appear. Why?

It is needed to implement \zleftrepeat command with \noindent\kern-1.6cm to avoid the offset, but it is not working even though it uses \alaligne before call the command. The basic code is as follow: \documentclass[12pt]{article} % ========== FORMATO DE PÁGINA: A4 VERTICAL ========== \usepackage[a4paper,portrait,left=0.4cm,right=0.2cm,top=0.2cm,bottom=0.2cm]{geometry} \pagestyle{empty} % ========== PAQUETES ========== \usepackage{tikz} \usetikzlibrary{quotes} \usetikzlibrary{shapes} \usetikzlibrary{fit,positioning} \usetikzlibrary{arrows.meta} \usetikzlibrary{decorations} \usepackage{amsmath} \usepackage{xcolor} \usetikzlibrary{calc} \usepackage{musicography} \usepackage{musixtex} \input musixlyr \input musixjt \xdefinecolor{red-undar}{RGB}{179,35,79} \begin{document} \begin{music} % ========== CONFIGURACIÓN GLOBAL ========== \parindent0mm% \staffbotmarg8\Interligne \font\B=phvb8t at 12pt \font\A=phvb8t at 10pt \A% \setsongraise1{6mm} \setstaffs1{1} \setlines{1}{5} \setclef{1}{\treble} \setclefsymbol{1}{\empty}% \generalmeter{\meterfrac34}% %\nobarnumbers% \systemnumbers% \def\raisebarno{5\internote}% % acerca el número al pentagrama \def\shiftbarno{-5pt}% % posición horizontal \def\writebarno{\eightrm\the\barno\barnoadd}% quita el recuadro, usa texto simple \nostartrule % ancho de sistema = ancho del texto de la página A4 (sin sobreancho) % ========== SISTEMA 1 (6 compases) ========== \startpiece \Notes\usf m\ibl1i0\qb1j\nbbl1\qb1j\tbl1\qb1j\usf m\ibl2i0\qb2{j}\tbl2\qb2{j}\Qqbbl jjjj\en\bar% \Notes\usf m\ibl1i0\qb1j\nbbl1\qb1j\tbl1\qb1j\usf m\ibl2i0\qb2{j}\tbl2\qb2{j}\Qqbbl jjjj\en\bar% \Notes\usf m\ibl1i0\qb1j\nbbl1\qb1j\tbl1\qb1j\usf m\ibl2i0\qb2{j}\tbl2\qb2{j}\Qqbbl jjjj\en\bar% \Notes\usf m\ibl1i0\qb1j\nbbl1\qb1j\tbl1\qb1j\usf m\ibl2i0\qb2{j}\tbl2\qb2{j}\Qqbbl jjjj\en\bar% \alaligne\noindent\kern-1.6cm\zleftrepeat% \Notes\ccharnote{-5}{\hspace{-0.7cm}\p}\usf p\ql j\Dqbu fj\qu f\en\bar% \Notes\usf p\ql j\Dqbu fj\Dqbu ff\en\bar% \Notes\usf p\ql j\Dqbu fj\qu f\en\bar% \Notes\usf p\ql j\Dqbu fj\Dqbu ff\en\bar% \Notes\usf p\ql j\Dqbu fj\qu f\en\bar% \Notes\usf p\ql j\Dqbu fj\Dqbu ff\en\bar% \Notes\usf p\ql j\Dqbu fj\qu f\en\bar% \Notes\usf p\ql j\Dqbu fj\Dqbu ff\en\bar% \Notes\usf p\ql j\Dqbu fj\qu f\en\bar% \NOtes\stdstemfalse\smallnotesize\islurd{1}{j}\grcu j\en% \Notes\tslur{1}{j}\ql j\qp\qp\en\rightrepeat% \Notes\ccharnote{-19}{\hspace{0.3cm}\mf}\usf m\ibl0i0\qb0j\triolet l\nbbl0\qb0{jj}\tql0j\usf m\ibl1i0\qb1{j}\tbl1\qb1{j}\Qqbbl jjjj\en\bar% \NOtes\stdstemfalse\smallnotesize\islurd{1}{j}\grcu j\en% \Notes\tslur{1}{j}\ql j\qp\qp\en\bar% \NOtes\stdstemfalse\smallnotesize\islurd{1}{j}\grcu j\en% \Notes\tslur{1}{j}\fermataup{k}\ql j\qp\qp\en\setdoubleBAR% \nolyr% \lyricsoff% \endpiece% \end{music} \end{document} The current output is as follow: The desired output is as follow:

If we run TeX on this file \hfuzz=\maxdimen \hsize=0pt \hyphenchar\font=`^^ff \hskip0pt error \bye in log file we get Missing character: There is no ^^ff in font cmr10! But if we load rm-lmr10 font, this error message is not produced. Why? \font\F=rm-lmr10 \F \hfuzz=\maxdimen \hsize=0pt \hyphenchar\font=`^^ff \hskip0pt error \bye Which part of rm-lmr10 makes TeX not to print this message? Is this proper behavior?

Is it possible to set shape border rotate to a new default for a particular shape? For example, say I want to define a shape (which I'll call trapezoid in the MWE) that is essentially a trapezium but it is rotated by 180° by default. For example, \documentclass{standalone} \usepackage{tikz} \usetikzlibrary{shapes.geometric} \pgfdeclareshape{trapezoid}{% \nodeparts{text}% \inheritsavedanchors[from=trapezium]% \inheritbackgroundpath[from=trapezium]% \inheritanchorborder[from=trapezium]% \inheritanchor[from=trapezium]{text}% \inheritanchor[from=trapezium]{center}% \inheritanchor[from=trapezium]{north}% \inheritanchor[from=trapezium]{south}% \inheritanchor[from=trapezium]{east}% \inheritanchor[from=trapezium]{west}% \inheritanchor[from=trapezium]{north west}% \inheritanchor[from=trapezium]{north east}% \inheritanchor[from=trapezium]{south west}% \inheritanchor[from=trapezium]{south east}% \behindbackgroundpath{% \pgfpathmoveto{\lowerleftpoint}% \pgfpathlineto{\upperrightpoint}% }% }% \begin{document} \begin{tikzpicture} \node [draw,trapezium,minimum size=1cm] {}; \node [draw=blue,trapezoid,minimum size=1cm,name=s] at (0,-1.25) {}; \node [draw=orange,trapezoid,minimum size=1cm,shape border rotate=180] at (0,-2.5) {}; % \foreach \anchor/\placement/\color in {north/above/orange,south/below/teal, % east/right/red,west/left/green,50/above/violet} % \draw [color=\color,shift=(s.\anchor)] plot [mark=x] coordinates {(0,0)}; \end{tikzpicture} \end{document} but both the blue and the orange shapes should be the same. Alternatively, the blue one could be narrow-end-on-top, and the orange one rotates 180° more and looks like the black one. Options I have considered: Define a new shape and a new set of keys to go with it that are very similar to trapezium except upside-down (this is the worst option) Define trapezoid as a style that calls another shape (say, decorated trapezium or some such) whose only real purpose is to set another default value of shape border rotate Create an anchor that reads another key (say, trapezoid rotate) that determines what the user wants the new angle to be, then sets shape border rotate to something based on that. I am hoping there is another way, something like issuing \changepgfinitialvalue inside the shape definition so that the initial value changes for that shape (and only that shape). Is there? Clarification: what I want is a shape (I used trapezium here, but it could be something else) that looks similar to an existing one, but has extra things drawn on it, an appendage of some sort, etc., but the base shape is rotated with respect to the original. If there is a way to do this so that the user who calls, say, shape=trapezoid instead of just trapezoid without reverting the orientation, that would be my preference. In other words, inherit everything from a shape, build on it with \beforebackgroundpath, \foregroundpath, and such, and change the default orientation.

My goal is to achieve this: Best that a can do now is: \begin{tabular}{c c c c c} &\Text{Calça Azul} & \text{Calça Preta} & \text{Sapato Azul} & \text{Sapato Preto} \\ \text{Camisa branca} & & & & \\ \text{Camisa vermelha} & & & & \end{tabular} How to get something more close to the goal?

I am preparing some physics exercises about pressure, and I would like to illustrate a rectangular box that can be placed on each of its three different faces. In this way, the same box would have three different base areas, while its dimensions remain unchanged. For example, my box has dimensions: 23 cm, 24 cm, 46 cm I would like to create the three possible orientations of the box with TikZ, so that in each drawing a different face is touching the ground. At the moment, I have this code for one orientation: \documentclass{article} \usepackage[margin=0.5in]{geometry} \usepackage{tikz} \begin{document} \begin{center} \begin{tikzpicture}[x=0.027cm,y=-0.027cm,line width=0.35pt,draw=black!75] \draw (77,123)--(77,199)--(146,231)--(281,163)--(281,110); \draw (146,156)--(146,231); \draw (212,55)--(212,122); \draw (77,123)--(60,84)--(126,117)--(146,156)--cycle; \draw (77,123)--(51,96)--(186,27)--(212,55)--(109,109); \draw (212,55)--(232,16)--(301,48)--(281,87)--cycle; \draw (146,156)--(281,87)--(319,91)--(184,160)--cycle; \draw[<->] (66,126)--(66,198); \draw[<->] (72,210)--(141,242); \draw[<->] (151,242)--(286,173); \node[rotate=-90,inner sep=0pt,font=\small] at (57,160) {23 cm}; \node[rotate=-25,inner sep=0pt,font=\small] at (101,233) {24 cm}; \node[rotate=27,inner sep=0pt,font=\small] at (227,213) {46 cm}; \end{tikzpicture} \end{center} \end{document} Is there a relatively simple way to modify this code (or to define a reusable TikZ command) so that I can obtain the other two orientations of the same box, with the 23 cm, 24 cm, and 46 cm dimensions exchanged accordingly? Ideally, I would like to be able to write something like \boxorientation{23}{24}{46} and obtain the corresponding drawing, or otherwise have a convenient way to generate the three possible orientations. The purpose is to use the drawings in physics exercises about pressure, where the students have to calculate the pressure exerted by the box when it rests on each of its three possible bases.

First, consider the code which produces the colored star: \documentclass{article} \usepackage{tikz} \usetikzlibrary{shapes.geometric} \begin{document} \begin{center} \begin{tikzpicture} \node[ shape=star, star points=5, star point ratio=2.5, minimum size=0.8cm, fill=red, draw=red ] {}; \end{tikzpicture} \end{center} \end{document} which produces: Now, consider the code which produces the tikz circle of asterisks: \documentclass{book} \usepackage{tikz} \usetikzlibrary{shapes.geometric} % Required for the star shape \usetikzlibrary{calc} \definecolor{oldgloryblue}{RGB}{10,49,97} \begin{document} \thispagestyle{empty} \begin{center} \begin{tikzpicture} \foreach \k in {0,30,...,360} \node at ($(0,0)+(\k:2)$){*}; \end{tikzpicture} \end{center} \end{document} and which produces However, when I replace the asterisk by `shape=star, star points=5, star point ratio=2.5, minimum size=0.8cm, fill=red, draw=red` I encounter many problems. QUESTION: How may I produce the circular image of `red stars' instead of the circular images of asterisks? Thank you.

I use the tasks environment from the tasks package to make exercises and solutions. If the solutions are long, there is a lot of free space since it seems that individual \tasks do not allow page breaks inside of them. Instead. the \task will start on the next page. I could just use the enumerate environment for these solutions, but some solutions are rather short, so I use the task envornment for these, to have multiple tasks side by side, going from left to right and not from top to bottom first. To have my code consistent, I would like to have the longer solutions in the task environment also. Can \tasks somehow be set up such that they can span over multiple pages? MWE: \documentclass{scrartcl} \usepackage{tasks} \usepackage{lipsum} \begin{document} \begin{tasks} \task \lipsum[1-2] \task \lipsum[1-3] \end{tasks} \end{document}

I'm trying to arrange a collection of nodes using \graph, which will be used to define a series of spath3 knot strands. However, the default cartesian placement strategy doesn't work very well for my purposes, as node chains that I intend to "tee off" from other nodes are placed at a constant width. It's possible to get what I want with the following code, but it's obviously rather fragile: \documentclass{article} \usepackage{tikz} \usetikzlibrary{graphs} \begin{document} \begin{tikzpicture} \graph[nodes={draw, as={}}]{ a -> b -> c, {[placement/width=1, placement/depth=1, grow down] b -> d -> f -> g}, {[placement/width=2, placement/depth=2, grow right] f -> p}, }; \end{tikzpicture} \end{document} How can I achieve the same effect by specifying the node rather than the width and depth?

There is a highly popular post from 2014 showcasing Nice scientific pictures show off but a lot has changed with LaTeX over the last 12 years. What is your best science picture to show off now that wasn't possible 12 years ago? Constraints for each answer: The Picture & Code: Show off a beautiful scientific illustration that utilizes features, packages, or engine capabilities (e.g., LuaLaTeX memory handling, modern pgfplots limits, Luametafun) that remove barriers which routinely stopped typical users from doing this 12 years ago (such as hard memory crashes, lack of default ecosystem support, or prohibitive manual workarounds). The Evolution: You must explicitly explain what technological progress or package developmentover the last decade made this picture possible today. AI usage is allowed, but must be acknowledged per community guidelines.

I want to add some tagged section headings within frames with ltx-talk. It seems like using the exisiting section templates would be a neat way of doing this. But I am having trouble getting the section tagging structure to close correctly at the end of the frame. I can't find a way to inject sockets to close things without redefining internal ltx-talk macros. And so far, I haven't closed things correctly in all situations even if I do redefine. This seems to work in most cases I try, but seems risky: \cs_set_protected:Npn \__talk_frame_process:nn #1#2 { \__talk_decode_parse:n {#1} \bool_if:NT \l__talk_decode_mode_bool { \__talk_frame_process_aux:nn {#1} { #2 \par \UseTaggingSocket{sec/end}{6} \UseTaggingSocket{sec/end}{5} } } } What is a good way of doing this? MWE %! TeX Program = lualatex \DocumentMetadata{ , lang = en , pdfstandard = ua-2 , tagging = on } \documentclass{ltx-talk} \tagpdfsetup { , role/new-tag = frame-heading/H5 , role/new-tag = frame-subheading/H6 } \AssignStructureRole{sec/5/title}{frame-heading} \NewStructureName{sec/6} \AssignStructureRole{sec/6}{Sect} \NewStructureName{sec/6/title} \AssignStructureRole{sec/6/title}{frame-subheading} \NewStructureName{sec/6/number} \AssignStructureRole{sec/6/number}{section-number} \DeclareInstance{heading}{frame-heading}{display} { , name = frame-heading , level = 5 , before-vspace = \medskipamount , after-vspace = \smallskipamount , heading-decls = \Large\bfseries , headformat-instance = frame-heading } \DeclareInstance{heading}{frame-subheading}{display} { , name = frame-subheading , level = 6 , before-vspace = \medskipamount , after-vspace = \smallskipamount , heading-decls = \large\bfseries , headformat-instance = frame-subheading } \DeclareInstanceCopy{headformat}{frame-heading}{std} \DeclareInstanceCopy{headformat}{frame-subheading}{std} \ExplSyntaxOn \NewDocumentCommand \frameheading { D <> { all } m } { \__talk_if_overlay:nT {#1} { \ParseLaTeXeHeading{frame-heading}{\BooleanTrue}{}{#2} } } \NewDocumentCommand \framesubheading { D <> { all } m } { \__talk_if_overlay:nT {#1} { \ParseLaTeXeHeading{frame-subheading}{\BooleanTrue}{}{#2} } } \ExplSyntaxOff \begin{document} \begin{frame} Filler text. \frameheading{A Heading} Filler text. \framesubheading{A Subheading} Filler text. \end{frame} \begin{frame} \frametitle{A Frame Title} Filler text. \frameheading{A Frame Heading} Filler text. \framesubheading{A Frame Subheading} Filler text. \end{frame} \section{A Section Heading} \begin{frame} \frametitle{A Frame Title} Filler text. \frameheading{A Frame Heading} Filler text. \framesubheading{A Frame Subheading} Filler text. \end{frame} \end{document}

I am writing my Mid-Sem Report to be submitted to my University and they have fixed a particular style of document to be used. I am attaching my code which I am writing. \documentclass[a4paper,12pt]{article} \usepackage{amsmath,amssymb,graphicx,tikz,amsthm} \usetikzlibrary{arrows,matrix} \usepackage[utf8]{inputenc} \usepackage{titlesec} \titlelabel{\thetitle.\quad} \usepackage{setspace} \usepackage{indentfirst} \newtheorem{theorem}{Theorem}[section] \newtheorem{lemma}[theorem]{Lemma} \newtheorem{Proposition}[theorem]{Proposition} \newtheorem{definition}{Definition}[section] \newtheorem{corollary}[theorem]{Corollary} \newtheorem{Con}[theorem]{Conjecture} \newtheorem{Prob}[theorem]{Problem} \newtheorem{Fact}[theorem]{Fact} \newtheorem{Remark}[theorem]{Remark} \newtheorem{Def}[theorem]{Definition} \newtheorem{Example}[theorem]{Example} \newtheorem{Question}[theorem]{Question} \newtheorem{Problem}[theorem]{Problem} %\newtheorem{proof}[theorem]{Proof} \renewcommand{\baselinestretch}{1.1} \usepackage{pifont,txfonts,geometry,hyperref} \newcommand{\bcomma}{,\allowbreak} \newcommand{\R}{\mathbb{R}} \newcommand{\ds}{\displaystyle} %%%%%%%%% Set page size and margins here %%%%%%%%%%%%%%% \setlength{\topmargin}{-0.5in} \setlength{\topskip}{0.275in} % between header and text \setlength{\textheight}{9in} % height of main text \setlength{\textwidth}{6.25in} % width of text \setlength{\oddsidemargin}{0.1in} % odd page left margin \setlength{\evensidemargin}{0.1in} % even page left margin %\theoremstyle{definition} %\newtheorem{definition}{Definition} \renewcommand{\theenumi}{\rm(\alph{enumi})} \renewcommand{\labelenumi}{\theenumi} %CAN REFER ITEMS WITH THE ABOVE TWO LINES \renewcommand{\theenumii}{\rm(\roman{enumii})} \renewcommand{\labelenumii}{\theenumii} \begin{document} %%%%%%%%%%%%%%%%%%%%%% Title page %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% \thispagestyle{empty} \begin{center} \LARGE\textbf{Midterm Report} \end{center} \vspace{1cm} \noindent \textbf{Name: Arghya Das} \vspace{3mm}\\ \noindent \textbf{Roll No: MSI22022} \vspace{3mm}\\ \noindent \textbf{Name of the Supervisor: Prof. Milan Nath} \vspace{2em} \hrule \vspace{1em} \section*{Title: A study on algebraic connectivity and spectral integral variations of graphs.} \section*{Abstract:} Write your abstract within 200 words. \section{Introduction} Throughout this document, all graphs are assumed to be finite and simple, unless otherwise mentioned. Let $G$ be a graph with vertex set $V(G)=\{1,2,\dots,n\}$ and edge set $E(G)=\{e_1, e_2,\dots,e_m\}$. We use the notation $i\sim j$ to mean that the vertices $i$ and $j$ are adjacent. The\textbf{\textit{ adjacency matrix}} of $G$, denoted by $A(G)$, is defined as $A(G)=[a_{ij}]_{n\times n}$, where \\ \\ \indent \indent \indent \indent \indent \indent \indent \indent \indent \indent $a_{ij}=\begin{cases} 1, & \text{if } i \sim j\\ 0, & \text{otherwise.} \end{cases}$ \\ \\ The \textit{\textbf{Laplacian matrix}} of $G$, denoted by $L(G)$, is defined as $L(G) := D(G)-A(G)$, where $D(G)$ is the diagonal matrix with degrees of the vertices of $G$ as diagonal entries. It is well-known that $L(G)$ is symmetric and positive semidefiniite and rank of $L(G)$ is $n-k$ where $k=k(G)$ is the number of connected components in $G$. Since $L(G)$ is symmetric and positive semidefinite so all the eigenvalues of $L(G)$ are real and non-negative. Moreover, $0$ is the smallest eigenvalue of $L(G)$ as for $v=(1 \ \ 1\ \dots \ 1)^T \in \R^n$, \ \ $L(G)v=0v$. \par Suppose that $0=\lambda_1\leq \lambda_2 \leq \cdots$ \section{Preliminaries} \section{Work done} Maximum 03 pages \section{Further study} Maximum 01 page \begin{thebibliography}{33} \bibitem{F1} Castelaz, A.~Commutivity degree of finite groups.~Thesis,~Department of Mathematics,~ Wake Forest University,~North Carolina,~5-8, 2010. \bibitem{C1} Cerf, V.,~Fernandez, E.,~Gostelow, K.,~and~Volausky, S.~ Formal control and low properties of a model of computation. Report ENG 7178, Computer Science Department, University of California, Los Angles, CA,~pp. 81, 1997. \bibitem{E2} Dutta, P.~and~Nath, R.K.~Autocommuting probability of a finite group.~{\em Communications in Algebra},~46(3):961-969, 2018. \end{thebibliography} \end{document} However I didn't like the lambda produced here and I want it changed while rest of the fonts and symbols of the document remain untouched (as I can't change the fonts and symbols very much). I want this lambda to use specifically: I have gone through many Tex exchange answers and AI answers but none of them work. Some of these are: How to make italic greek letter \lambda \usepackage{amsmath,amssymb} \usepackage{unicode-math} \setmathfont{Latin Modern Math} \setmathfont[range=\lambda]{TeX Gyre Termes Math} \DeclareSymbolFont{newtxletters}{OML}{ntxmi}{m}{it} \DeclareMathSymbol{\newtxlambda}{\mathord}{newtxletters}{"15} But either they throw an error or produces the same lambda as in produced before. So any help would be appreciated.

The title says it all. Here an MWE, where the first (regular) tabular is the one I try to replicate using tabularray. (The last table is just to confirm that the S colspec in the second table is used in the merged cells as well.) \documentclass[border=5pt,varwidth]{standalone} \usepackage[table]{xcolor} \usepackage{booktabs} \usepackage{tabularray} \UseTblrLibrary{ booktabs, siunitx, } \SetTblrInner{rowsep=0pt} \usepackage{siunitx} \begin{document} \bgroup \newcommand*{\mc}[1]{\multicolumn{2}{c}{\cellcolor{black!10}\tablenum[table-format=3.2]{#1}}} \begin{tabular}{*{2}{S[table-format=5]}} \toprule Min & Max \\ \midrule 1 & 10 \\ 11111 & 22222 \\ \midrule \mc{0.12} \\ \mc{12.3} \\ \mc{123} \\ \mc{5} \\ \mc{0.8} \\ \bottomrule \end{tabular} \egroup \quad \bgroup \begin{booktabs}{ colspec={*{2}{S[table-format=5]}}, row{1}={guard}, cell{4-Z}{1}={c=2}{ % the `S` column specifier or `colspec` seem to be ignored ... S[table-format=3.2\unit{\percent}], % colspec={S[table-format=3.2\unit{\percent}]}, % ... when a color is given. Otherwise an error is raised % that the `S` or `colspec` are interpreted as a color black!10, % % using "usual" colspec values work as expected ... % (the `S` column specifier of the non-merged column/cells seems % to be still used/applied here) l, % c, % r, }, } \toprule Min & Max \\ \midrule 1 & 10 \\ 11111 & 22222 \\ \midrule 0.12 & 0.12 \\ 12.3 & 12.3 \\ 123 & 123 \\ 5 & 5 \\ 0.8 & 0.8 \\ \bottomrule \end{booktabs} \egroup \quad \bgroup \begin{booktabs}{ colspec={ll}, row{1}={guard}, cell{4-Z}{1}={c=2}{ % the `S` column specifier or `colspec` seem to be ignored ... % S[table-format=3.2\unit{\percent}], colspec={S[table-format=3.2\unit{\percent}]}, % ... when a color is given. Otherwise an error is raised % that the `S` or `colspec` are interpreted as a color black!10, % % using "usual" colspec values work as expected ... % l, c, % r, }, } \toprule Min & Max \\ \midrule 1 & 10 \\ 11111 & 22222 \\ \midrule 0.12 & 0.12 \\ 12.3 & 12.3 \\ 123 & 123 \\ 5 & 5 \\ 0.8 & 0.8 \\ \bottomrule \end{booktabs} \egroup \end{document}

I would like to use forloop (or multido or another alternative if suggested) so that I can generate a series of short coding quizzes where each quiz uses verbatim (or fancyvrb or listings or another alternative). But when I try to do this: \documentclass{article} \usepackage{forloop} \newcounter{x} \begin{document} \forloop{x}{1}{\value{x} < 7}{% \begin{verbatim} def f(x): return x + 1 \end{verbatim} } \end{document} I get an error: File ended while scanning use of \@xverbatim The same basic problem has occurred when I have tried using multido rather than forloop; likewise fancyvrb or listings instead of verbatim. Is there anyway around this limitation?

Consider the code: \documentclass[12pt]{book} \usepackage{tabularx,lipsum} \begin{document} \thispagestyle{empty} \begin{tabularx}{\linewidth}{c>{\arraybackslash}X} \emph{Heading:} \emph{(to go on second line)} \hskip 15pt & \lipsum[13] \end{tabularx} \end{document} which produces QUESTION: How may I place Heading: (on the second line) over two lines: Heading and (on the second line)? (\vspace{5pt} or \vspace*{5pt} neither seem to work; and, \\[5pt] gives me an overflow message.) Thank you.

I'm having issues with a specific bibliographic entry. While all other citation call-outs in the document work fine, one shows up as sacco˙neurite˙2020 instead of as "(Sacco et al., 2020)" when I use \cite{sacco_neurite_2020}. Here, sacco_neurite_2020 is the correct key that is in Zotero and also in references.bib. The full entry in references.bib is the following: @article{sacco_neurite_2020, chapter = {Adult Brain}, title = {Neurite {Orientation} {Dispersion} and {Density} {Imaging} for {Assessing} {Acute} {Inflammation} and {Lesion} {Evolution} in {MS}}, volume = {41}, copyright = {© 2020 by American Journal of Neuroradiology. Indicates open access to non-subscribers at www.ajnr.org}, issn = {0195-6108, 1936-959X}, url = {https://www.ajnr.org/content/41/12/2219}, doi = {10.3174/ajnr.A6862}, abstract = {...}, language = {en}, number = {12}, urldate = {2026-07-04}, journal = {American Journal of Neuroradiology}, publisher = {American Journal of Neuroradiology}, author = {Sacco, S. and Caverzasi, E. and Papinutto, N. and Cordano, C. and Bischof, A. and Gundel, T. and Cheng, S. and Asteggiano, C. and Kirkish, G. and Mallott, J. and Stern, W. A. and Bastianello, S. and Bove, R. M. and Gelfand, J. M. and Goodin, D. S. and Green, A. J. and Waubant, E. and Wilson, M. R. and Zamvil, S. S. and Cree, B. A. and Hauser, S. L. and R. G. Henry and and University of California, San Francisco MS-EPIC Team}, month = dec, year = {2020}, pages = {2219--2226}, } In the preamble, I have: \usepackage[ backend=biber, style=apa, natbib=true, url=false, doi=false, eprint=false ]{biblatex} Does anyone have an idea what could be wrong? Thank you.