Week

I am using the package metre. It has the environment \metra{} used for typesetting latin (and greek) metre notation. This environment has almost all the special characters I need, except one: I need a character that looks somewhat like a fermata 𝄐 but preferrably in the same style as the other metrical symbols. This could, I believe, be achieved by simply taking the character breve that is produced by \documentclass{article} \usepackage[en]{metre} \begin{document} \metra{\a\m\b\bm} \end{document} and have it flipped upside down and a dot put underneath. In a book, this is what it looks like: It's the last symbol of each of the lines in the box. Does anyone know how this could be achieved? I even tried contacting the package's creator but his email address does not seem to exist anymore. My MWE produces the symbols in this picture (the ones inside the brackets): Thanks in advance!

Example: \documentclass[a4paper]{article} \overfullrule=10mm \usepackage{tabularx} \begin{document} \maketitle This document is for experimenting around \texttt{tabularx}. \begin{tabularx}{\linewidth}{|XX}%p{5cm} \begin{minipage}{\linewidth} \begin{tabularx}{\linewidth}{|X}% long text to be \newline long text to be \newline long text to be \newline long text to be \newline long text to be \newline % \the\hsize % \the\linewidth % \the\textwidth long text to be \end{tabularx} \end{minipage} & %\begin{tabularx}{0.25\linewidth}{|X}% 2nd %\end{tabularx} \end{tabularx} \end{document} results in: ! Extra }, or forgotten \endgroup. \TX@trial ...er \tabular \the \toks@ \endtabular } \TX@ckpt \TX@typeout@ {\@s... l.80 \end{tabularx} ! Extra }, or forgotten \endgroup. \TX@endtabularx ...\csname endtabular*\endcsname } \global \TX@ftn \expandaft... l.80 \end{tabularx} ! Extra }, or forgotten \endgroup. \TX@endtabularx ... }\the \TX@ftn \ifnum 0=`{\fi } \expandafter \expandafter ... l.80 \end{tabularx} ! Extra }, or forgotten \endgroup. \@endpbox ...trutbox \par \color@endgroup \egroup \hfil l.80 \end{tabularx} ! Missing \endgroup inserted. <inserted text> \endgroup l.80 \end{tabularx} ... If I replace the inner tabularx by tabular (dropping \linewidth and changing X) it works. I would even like to use without minipage, but that it does not work with minipage, it means that minipage encapsulation is not very strict. I will have a look I think I remember an example where nested tabularx worked.

(Sorry again for the vague title of this question (which is a follow-up of another question of mine), I can't think of a more appropriate one.) Suppose I'd like to augment the key set of keytheorems with a Title key which isn't exactly an alias of its title (or its alias name) key but which makes uppercase the first character of its value before passing it to keytheorems' title (or name). In the following MCE, I rely for this on an auxiliary token list which, unfortunately, is not limited to the definition of each defined theorem: only the last value it took is used each time one of the defined theorems is used, so instead of: Abc 1. Foo. Xyz 1. Baz. I get: Xyz 1. Foo. Xyz 1. Baz. How can I work around this problem? \documentclass{article} \usepackage{keytheorems} \ExplSyntaxOn \keys_define:nn { keytheorems/thm } { Title .code:n = { \tl_set:Nn \l_tmpa_tl {\text_titlecase_first:n{#1}} \keys_set:nn { keytheorems/thm } { name=\l_tmpa_tl} } } \NewDocumentCommand{\mynewtheorem}{O{} m} { \newkeytheorem{#2}[#1] } \ExplSyntaxOff \mynewtheorem[Title=abc]{foo} \mynewtheorem[Title=xyz]{baz} \begin{document} \begin{foo} Foo. \end{foo} \begin{baz} Baz. \end{baz} \end{document}

I'd like to draw crystal structures using TikZ-3Dplot'''. I saw that solutions exist with Asymptote, but for some reason, I can't install it (and I admit I had trouble understanding how the package works). I started with TikZ 3D Plot, which seems to work. I just have one question: I can't keep some lines horizontal, which I find unsightly (I've tried several angle values ​​in the command \tdplotsetmaincoords, but without success). \documentclass{standalone} \usepackage{tikz,tikz-3dplot} \usepackage{xcolor} \begin{document} \tdplotsetmaincoords{75}{10} \begin{tikzpicture}[tdplot_main_coords, scale = 5] % ---- Tracé des traits du réseau ---- \draw[thin] (0,0,0) -- (1,0,0) -- (1,1,0) -- (0,1,0) -- (0,0,0); \draw[thin] (0,0,1) -- (1,0,1) -- (1,1,1) -- (0,1,1) -- (0,0,1); \draw[thin] (0,0,0) -- (0,0,1); \draw[thin] (1,0,0) -- (1,0,1); \draw[thin] (1,1,0) -- (1,1,1); \draw[thin] (0,1,0) -- (0,1,1); \tdplottransformmainscreen{0}{0}{0} \shadedraw[tdplot_screen_coords, ball color = blue] (\tdplotresx,\tdplotresy) circle (0.10); \end{tikzpicture} \end{document}

I have the following code to add background for the document: \documentclass{article} \usepackage{lipsum} \usepackage{geometry} \usepackage{graphicx} \usepackage{tikz,tikzpagenodes} \usetikzlibrary{calc,fadings} \AddToHook{shipout/background}{ \begin{tikzpicture}[remember picture,overlay] \node[ % path fading=north, inner sep=0pt,outer sep=0pt, anchor=south,opacity=.3, ] at (current page.south) {\includegraphics[width=\paperwidth]{bg.png}}; % \path[path picture={ % \node[inner sep=0pt,outer sep=0pt,anchor=south,scope fading=south] at (current page.south) {\includegraphics[width=\paperwidth]{bg.png}}; % }]; \coordinate (L) at ($(current page.north west)!.5! (current page text area.north west)$); \coordinate (R) at ($(current page.south east)!.5! (current page text area.south east)$); \fill[white,opacity=.5] (L) rectangle (R); \end{tikzpicture} } \begin{document} \lipsum[1-6] \end{document} It produced: However, the intersection border's color transformation is too sharp! I want the image could smoothly fade to white, with multiple opacity, I have consulted this link, but it doesn't work. The bg.png could be accessed as below(maybe example-image is okay, but its background is pure gray, I would prefer to show that on bg.png):

Similar to this question: similar question I don't know, why the 'resume*=series' approach does not work here. \documentclass{scrartcl} \usepackage{enumitem} \begin{document} text text text texttext text text text\\ text text text texttext text text text \begin{enumerate}[leftmargin=*] \item asdfg \item afhaf \begin{enumerate}[series=_test] \item adslfa \item adsfadsf \end{enumerate} \end{enumerate} text text text texttext text text text\\ text text text texttext text text text \begin{enumerate}[resume*=_test] \item adfa \end{enumerate} \end{document}

As a physicist, I often need to typeset tensor indices where it matters whether the subscript is to the left or to the right of the superscript. My usual solution is to use {t_A}^B, which puts the superscript B to the right of the subscript A, compared to t_A^B which puts the superscript B vertically aligned with the subscript A. However, I recently noticed that if I use \bar{t} or \tilde{t} instead of t above, the output no longer differs whether I enclose the (xxx)_A part with braces or not. But, \overline{t} still behaves as I expect. Then I tried \widetilde{t}, which still ignores the braces. Is this a bug or a feature? If it's a feature, how should I classify which commands ignore the braces and which do not? In particular, is there a "tilde" command that behaves like \overline that can put the superscript to the right of the subscript? Minimal working example: \documentclass{article} \begin{document} \begin{equation} \begin{array}{lllll} t_A^B & \tilde{t}_A^B & \widetilde{t}_A^B & \bar{t}_A^B & \overline{t}_A^B \\ {t_A}^B & {\tilde{t}_A}^B & {\widetilde{t}_A}^B & {\bar{t}_A}^B & {\overline{t}_A}^B \end{array} \end{equation} \end{document} Output:

In the braket package I have noticed a spacing issue with mathematical operators; plus and minus symbols after | will be treated as binary operators, even if they represent an ordinary operator. For example $\braket{+45|+45}$ will have no spacing for the first + symbol (treated as class 0), but will have the operator spacing for the second + symbol (treated as class 2). \documentclass{article} \usepackage{braket} \begin{document} How can we fix spacing in $\braket{+45|+45}$ without invoking \verb+\!+ \end{document} I would like to have a solution that does not involve inline spacing fixes. I am confident that the command can be redefined in a way that would resolve this issue.

Description As the successor of my prevoius not-supported l3draw attempt, I try with plain-tikz: \documentclass[tikz,border=5pt]{standalone} \usepackage{mathpazo} \usepackage{amsmath} \usetikzlibrary{arrows.meta} \begin{document} \begin{tikzpicture}[line cap=round] \clip (-.5,-.5) rectangle (4.5,4.5); \begin{scope}[ x={(1.5cm,0.5cm)}, y={(0.5cm,2cm)}, ] \fill[orange!10] (-2,-2) rectangle (5,5); \draw[orange] (-2,-2) grid (5,5); \draw[orange,ultra thick,-Stealth] (0,0) -- +(1,0) node[below] {$\mathbf{b_1}$}; \draw[orange,ultra thick,-Stealth] (0,0) -- +(0,1) node[below left] {$\mathbf{b_2}$}; \draw[black,ultra thick,-Stealth] (0,0) -- +(1,1) node[right] {$\mathbf{x}$}; \end{scope} \end{tikzpicture} \begin{tikzpicture}[line cap=round] \clip (-.5,-.5) rectangle (4.5,4.5); \begin{scope}[x={(1.5cm,0.5cm)}, y={(0.5cm,2cm)}] \fill[orange!10] (-2,-2) rectangle (5,5); % \draw[orange] (-2,-2) grid (5,5); \foreach \i in {-2,-1,...,5} {\draw[orange] (\i,-2) -- ++(0,7) (-2,\i) -- ++(7,0);} \draw[orange,ultra thick,-Stealth] (0,0) -- +(1,0) node[below] {$\mathbf{b_1}$}; \draw[orange,ultra thick,-Stealth] (0,0) -- +(0,1) node[below left] {$\mathbf{b_2}$}; \draw[black,ultra thick,-Stealth] (0,0) -- +(1,1) node[right] {$\mathbf{x}$}; \end{scope} \end{tikzpicture} \begin{tikzpicture}[line cap=round] \clip (-.5,-.5) rectangle (4.5,4.5); \begin{scope}[ transform canvas={cm={1.5, 0.5, 0.5, 2, (0,0)}} ] \fill[orange!10] (-2,-2) rectangle (5,5); \draw[orange] (-2,-2) grid (5,5); \draw[orange,ultra thick,-Stealth] (0,0) -- +(1,0) node[below] {$\mathbf{b_1}$}; \draw[orange,ultra thick,-Stealth] (0,0) -- +(0,1) node[below left] {$\mathbf{b_2}$}; \draw[black,ultra thick,-Stealth] (0,0) -- +(1,1) node[right] {$\mathbf{x}$}; \end{scope} \end{tikzpicture} \end{document} Here, I have three proposals: FIRST: the grid doesn't transform by x={(1.5cm,0.5cm)}, y={(0.5cm,2cm)}. SECOND: the manual \foreach gives what I want, but I don't think manually mimic what feature grid do is the best practice. THIRD: with transform canvas, it affected the grid, but all on the canvas, the text and arrow are both sheared, that is not I want. Question: Is there better approach without manually plot the grid? I would make good use of feature grid in my case as possible.

I want to mimic the following figure with l3draw, the \draw_transform_matrix:nnnn feature to apply transformation matrix. Here below is my attempt: \documentclass[border=5pt]{standalone} \usepackage{l3draw} \usepackage{amsmath} \begin{document} \ExplSyntaxOn \draw_begin: \color_set:nnn { orange } {RGB} {255, 128, 0} \draw_scope_begin: \draw_transform_matrix:nnnn { 2.5 } { 0.5 } { 0.5 } { 3 } \draw_set_cap_round: \draw_path_rectangle_corners:nn { -5mm , -5mm } { 35mm , 35mm } \color_fill:n { orange!15 } \draw_path_use_clear:n { fill } \draw_path_grid:nnnn { 1cm } { 1cm } { -5mm , -5mm } { 35mm , 35mm } \color_stroke:n { orange } \draw_path_use_clear:n { stroke, fill } \draw_set_linewidth:n { .1cm } \draw_path_moveto:n { 0cm, 0cm } \draw_path_lineto:n { 0cm, 1cm } \draw_path_use_clear:n { stroke } \draw_path_moveto:n { 0cm, 0cm } \draw_path_lineto:n { 1cm, 0cm } \draw_path_use_clear:n { stroke } \color_stroke:n { black } \draw_path_moveto:n { 0cm, 0cm } \draw_path_lineto:n { 2cm, 2cm } \draw_path_use_clear:n { stroke } \draw_scope_end: \draw_end: \ExplSyntaxOff \end{document} My question is: Is that possible to plot the image of "arrow" in l3draw's code framework? In 2026, when to choose l3draw? (I found that there are only 17 posts on this site was tagged l3draw since now) By reading the post on this site, l3draw is more used to constuct symbols(without arrow), or apply some transformations with l3box.... (Notes: I don't think my second question is a quite different one, in my state now, it's quite natural to ask if some features didn't provide by l3draw, while I have written the code shown above) Edited: Since Joseph has commented that: Currently arrows are not implemented, partly as I've not had a need to do it - the priority is really to get the code stable ATM I still wonder what kind of plotting requirement is suitable to play with l3draw in the current state(2026.02)?

How should one write the term-by-term "grading" under the equation, as in the following pictures? There should be various ways to achieve this. But at least, I would like to know how to do this in the usual situation, and with tikz-cd. Here is an example code of the above two equations: \documentclass{article} \usepackage{mathtools,amssymb,tikz-cd} \def\A{\mathbb{A}} \begin{document} Situation 1 (2 places): \[ H_X \colon [X \times \A^1] \to [X] \] Situation 2 (3 places): \[ [U \cap V] \xrightarrow{[j']-[i']} [U] \oplus [V] \xrightarrow{[i]+[j]} [X] \] Situation 2' (with \texttt{tikz-cd}): \[ \begin{tikzcd}[column sep=large] {[U \cap V]} & {[U] \oplus [V]} & {[X]} \arrow["{[j']-[i']}", from=1-1, to=1-2] \arrow["{[i]+[j]}", from=1-2, to=1-3] \end{tikzcd} \] \end{document}

I need to draw a pulley system as in the figure. How can I do that? Specific information about the figure: A block of mass Mo is on a horizontal surface and attached by a string to a hanging block, also of mass Mo , as shown in the figure. Friction between the block and the horizontal surface is negligible. The masses of the string and pulley are negligible, and the pulley can rotate with negligible friction around its axle.

I defined a Tikz macro and I want to use it so the item of an inline itemize is passed as its argument. So far, my solution is this: \documentclass{article} \usepackage[inline]{enumitem} \usepackage{tikz} \newcommand\itemvalue[1]{ \tikz[baseline=(o.base)] { \node[ inner xsep=0pt, inner ysep = 1pt, outer xsep=2pt, outer ysep=2pt ] (o) at (0,0) {\textcolor{blue!80!black}{\fontsize{10}{16}\textbf{#1}}}; \draw[color=gray!50, thick] ([xshift=(-1.3)]o.south west) -- ([xshift=(1.3)]o.south east); } } \begin{document} \let\olditem\item \renewcommand\item[1]{\olditem\itemvalue{#1}} \begin{itemize*}[label={}, labelsep=2em, parsep=2ex] \item {First} \item {Second} \item {Third} \end{itemize*} \end{document} The output looks like this: This is what I want but I was wondering if there was a way of redefining \item so it reads the full word (not only its first letter). If I remove the braces on each item, the output looks like this: This makes sense as far as I can tell how \item works, but I'd like a workaround that doesn't use braces on each item. Thanks!

I have used the sample code from latexdraw that draws a torus. I am trying to draw a filled circle and a dashed circle where they should be wrap around the torus instead of being drawn uniformly at z=0. I am looking for a TikZ solution. The closest I have seen is this solution but it is too difficult for me to decipher. Any help would be appreciated! \documentclass[margin=4pt]{standalone} \usepackage{tikz} \usepackage{pgfplots} \usepackage{tikz-3dplot} \usepgfplotslibrary{colormaps} \pgfplotsset{ compat=newest, colormap={manifoldmap}{color=(lightgray) color=(white) color=(lightgray)} } \begin{document} \begin{tikzpicture} \def\R{2.75} % Major radius (distance from torus centre to tube centre) \def\offset{0.5} % Radial displacement from the torus centre circle \def\thetaB{2.5} % Angular position (in radians) for highlighted point \begin{axis}[ width=12cm, axis equal image, hide axis, z buffer=sort, view={125}{35}, clip=false ] % Parametric torus equations: % x = (R + cos(x)) cos(y) % y = (R + cos(x)) sin(y) % z = sin(x) \addplot3[ surf, shader = faceted interp, samples = 30, samples y = 40, domain = 0:2*pi, domain y = 0:2*pi, colormap name = manifoldmap, thin, opacity=0.75 ] ( {(\R + cos(deg(x))) * cos(deg(y))}, {(\R + cos(deg(x))) * sin(deg(y))}, {sin(deg(x))} ); \begin{scope}[canvas is xy plane at z=0, transform shape] \coordinate (p) at ({(\R + \offset) * cos(deg(\thetaB))}, {(\R + \offset) * sin(deg(\thetaB))}); \draw[fill=red, draw=none] (p) circle (4pt); \draw[blue, dashed, thick] (p) circle (16pt); \end{scope} \end{axis} \end{tikzpicture} \end{document}

Let me provide some background for my question: I am compiling a latex project, which involves a main tex file and more than 100 other tex files with no figures (except for a few simple diagrams) or pictures. The resulting pdf file has more than 600 pages. Initially, I was using pdflatex and newtxtext for font. However, recently I am more inclined to use NewComputerModern, in particular I like the slightly thicker font. As we know, to use NewComputerModern, we must either use xelatex or luatex. I chose xelatex because it seems to be slightly faster than using luatex, but it is slower than pdflatex. So I ended up spending more time for compilation, especially when I am editing the tex files for the pages of the end of the pdf file. The packages I am using are: amsfonts, amsmath, amscd, amssymb, euscript, amsthm, fancyhdr, pgf, tikz, pgfplots, caption, subcaption, enumitem, thmtools, color, centernot, mathtools, afterpage, amsbsy, systeme, sectsty, multirow, float, tikz-cd, etoolbox, microtype, mathrsfs, fontspec, fncychap, xy, appendix My question is: is there any way to use NewComputerModern and get faster compilation? I want to minimize the time for compilation while keep looking at NewComputerModern rather than newtxtext. I considered using pdflatex and newtxtext during editing, and xelatex and NewComputerModern right before finish editing. But I think we should be able to do better than this.

What I want to typeset is something as below inline: Here below is my (ugly) attempt: \documentclass{article} \usepackage{lipsum} \usepackage{chemfig} \usepackage[version=4]{mhchem} \usepackage{extarrows} % https://tex.stackexchange.com/a/267541/322482 \makeatletter \DeclareRobustCommand{\textsupsub}[2]{{% \m@th\ensuremath{% ^{\mbox{\fontsize\sf@size\z@#1}}% _{\mbox{\fontsize\sf@size\z@#2}}% }% }} \makeatother \begin{document} \lipsum[2][1-6] HCHO + SO\textsupsub{2--}{3} + H\textsuperscript{+} $\xlongequal{\phantom{xxx}}$ \chemfig[atom sep=2em]{HO-[:30]-[:-30]S(=[:-120]O)(=[:60]O)-[:-30]O\rlap{${}^-$}} \lipsum[3][1-5] \ce{HCHO + SO_3^2- + H^+} $\xlongequal{\phantom{xxx}}$ \chemfig[atom sep=2em]{HO-[:30]-[:-30]S(=[:-120]O)(=[:60]O)-[:-30]O\rlap{${}^-$}} \lipsum[2] \end{document} which combined with: text mode's formula abruptly \xlongequal with abrupt \phantom chemfig which is not properly coordinated in length I wonder is that mechem or chemfig that could typeset this chemical equation in a uniform package framework, instead of composed of multiple isolated parts.

When I write M'(t) or H''(t) to denote derivatives, I get an unpleasantly large space between the "prime" symbol and the parenthesis. I'm wondering if I perhaps have a corrupted font. Or do people think the output is good and as expected, and my tastes are weird? Second question: what's the best way to fix this? \documentclass{article} \begin{document} $$ \mathbf{M}'(t) = \mathbf{H}''(t) $$ \end{document}

For my homework I would like to make the hand in exercises in bold text, and the practice exercises in normal text. Currently, I have: \documentclass[12pt]{exam} \usepackage{enumitem} \begin{document} \begin{enumerate}[label=Exercise \arabic*.] \item \item \end{enumerate} \end{document} Which results in . But I would like to be able to say something like this: \begin{enumerate}[label=Exercise \arabic*.] \item* \item \end{enumerate} to give . Is there a way to edit the enumerate environment to achieve this in this simple manner?

I calc values of the Standard normal table (with 5-digit accuracy). So I wrote a calculation with numerica.sty (using approximate values ​​of the error function). This works so far; if I put in a concrete value like ... [..., x=0.61]. But I would like to have this as a macro, say \sn{<#1>}, for example \sn{0.61} → 0.72907. I tried to put the whole thing into a newcommand, but this seems to be not that easy. I'd like to implement this inside pdflatex, using a package (not Lua, Mathematica, etc.). I've implemented it here using the numerica package because it worked without problems (including the use of the help-variable h, see MWE). However, I'm not sure if numerica is the best choice. The xintexpr package seems promising, but I'm currently unclear on its syntax. In any case: if anyone knows of a better implementation using a different package (e.g., xint.sty), it would be nice too. \documentclass[margin=10mm, varwidth]{standalone} \usepackage{numerica} \begin{document} \section{Test with \texttt{numerica}} \xdef\x{0.61} sn(\x) = \eval*{% 0.5 (2-h \exp( -0.5 x^2 -1.26551223 +1.00002368 h +0.37409196 h^2 +0.09678418 h^3 -0.18628806 h^4 +0.27886807 h^5 -1.13520398 h^6 +1.48851587* h^7 -0.82215223 h^8 +0.17087277 h^9)) }[h=1/(1+0.25*\sqrt{2}*x), x=0.61% cannot use \x here 🙁 ][5] \section{Test with \texttt{xint}} ... ? .... \end{document}

Is it possible to configure \diagbox[*]{*}{*} so that the elements to the right or below are aligned? \documentclass[margin=5pt, varwidth]{standalone} \usepackage{diagbox} \begin{document} \begin{tabular}{c | c | *{3}{c}} \hline a & \diagbox{$b$}{$c$} & 0.1 & 0.2 & 0.3 \\ \hline 2 & 0 & 0.1 & 0.2 & 0.3 \\ 2 & 1 & 2.1 & 2.2 & 2.3 \\ 2 & 2 & 4.1 & 4.2 & 4.3 \\ \end{tabular} \end{document}

Objective: The spiral construction is shown gradually. Each iteration is on a separate frame. \documentclass{beamer} \usepackage{tikz} \usetikzlibrary{calc} \begin{document} \begin{frame}{step by step spiral construction} \begin{tikzpicture} \draw (0,0) foreach \a in {1,...,120} { \only<\a->{ -- ++({10*\a}:{pow(0.99,\a)}) } }; \end{tikzpicture} \end{frame} \end{document} Error: No file test.nav. ! Package tikz Error: Giving up on this path. Did you forget a semicolon?. See the tikz package documentation for explanation. Type H <return> for immediate help. ... l.16 \end{frame} ?

I would like to fill the plot area with the rainbow colors. The wavelength of the colors corresponds to the wavelength of the x-axis. I have the MWE example below. It works fine uless for the line \fill[mycol!30] (axis cs: \wl/1000, 1.402) rectangle (axis cs: \wl/1000+0.001, 1.998); How can I fix it, please? \documentclass[tikz, border=1mm]{standalone} \usepackage{pgfplots} \pgfplotsset{compat=1.5} \usepackage{color} \begin{document} \begin{tikzpicture} \small \begin{axis}[% width = 70mm, height = 50mm, % grid = both, xmin = 0.41, xmax = 0.73, % xtick = \empty, % xtick distance = 100, ymin = 1.4, ymax = 2.0, ytick distance = 0.2, xlabel = Wavelength ($\mu$m), ylabel = Refractive index, ] %--> FILL PLOT AREA \foreach \wl in {410,...,729}{ \definecolor{tmpcol}{wave}{\wl} \colorlet{mycol}[rgb]{tmpcol} \fill[mycol!30] (axis cs: \wl/1000, 1.402) rectangle (axis cs: \wl/1000+0.001, 1.998); } %--> Borosilicate glass BK7 \addplot[thick, domain=0.41:0.73] {1.5046 + 0.00420/x^2}; \node at (axis cs: 0.7, 1.57) [above]{BK7}; %--> Barium crown glass BaK4 \addplot[thick, domain=0.41:0.73] {1.5690 + 0.00531/x^2}; \node at (axis cs: 0.7, 1.52) [below]{BaK4}; %--> Dense flint glass SF10 \addplot[thick, domain=0.41:0.73] {1.7280 + 0.01342/x^2}; \node at (axis cs: 0.7, 1.745) [above]{SF10}; \end{axis} \end{tikzpicture} \end{document}

MWE: \documentclass[12pt]{book} \usepackage{trajan} \begin{document} \thispagestyle{empty} \LARGE \noindent\trjnfamily{HOW TO MAKE TRAJAN TEXT BOLD?}\\[20pt] \noindent\textbf{\trjnfamily{BUT THIS DOESN'T WORK}} \end{document} The output: Using pdflatex, I would like to make text bold using the trajan font; however, \textbf and \bfseries seem not to work. Is there a way to do this?

I am having a bug with Unicode math, where fractions in exponents do not behave well if there are multiple fonts loaded. Here is a MWE demonstration (LuaLatex 2025, replicated locally and on Overleaf): \documentclass{article} \usepackage{unicode-math} \setmathfont{NewComputerModernMath}[version=NCMM] \setmathfont{XITS Math}[range = {}, version = XITS] % edit: the `version = XITS` is not required to replicate the bug \mathversion{NCMM} \begin{document} $a^\frac{3}{2}$ | $\lim$ | $a^\frac{3}{2}$ \end{document} This results in the following output: From testing, all exponents after the \lim seem to be fixed, though on my larger documents this disgrace of a workaround seems to have no effect. Interestingly, it has something to do with the \mathversion, because \documentclass{article} \usepackage{unicode-math} \setmathfont{NewComputerModernMath} \setmathfont{XITS Math}[range = {}] \begin{document} $a^\frac{3}{2}$ | $\lim$ | $a^\frac{3}{2}$ \end{document} Produces two bugged exponents: For context, if I remove the \setmathfont{XITS Math}... line or compile either MWE in XeLaTeX, there is no sizing bug with the exponents. I am not experienced with the internals of Unicode math, this range thing was to solve an issue with \mathcal (see here). Any temporary workaround would be appreciated.

I've got a problem with datatool. I already know a little about datatool, but couldn't find any answer in the documentation. The problem is the following: I read a csv file and want to sort the database by a column, which contains numbers (integers in fact, but it could be also real ones). The following mwe illustrates the problem: \documentclass{scrarticle} \begin{filecontents*}{data.csv} A, 20, 15 B, 21, 3 C, 6, 0 \end{filecontents*} \usepackage{datatool} \newcommand{\diff}{} \begin{document} \section*{initial csv} \DTLloaddb[noheader]{data}{data.csv} \DTLdisplaydb{data} \section*{sorted by Column2 (descending)} \DTLsort{Column2=descending}{data} \DTLdisplaydb{data} \section*{add Column4 as difference of C2 and C3} \DTLaddcolumn{data}{Column4} \DTLforeach{data}{ \x=Column2, \y=Column3 }{ \DTLgsub{\diff}{\x}{\y} \DTLappendtorow{Column4}{\diff} } \DTLdisplaydb{data} \section*{Sorted by Column4 (descending)} \DTLsort{Column4=descending}{data} \DTLdisplaydb{data} \end{document} Here the sorting by column 2 works just fine, but the sorting by column 4 doesn't. The logs give a warning, that there is no associated datatype for column 4, so datatool assumes a string and compares by letter. I couldn't find a way to add a datatype to that column (the docs say nothing, or I didn't find it). How can I add a datatype to the column?

Is there a way of getting the text starting from '1.3...' back to its position? This is how I coded it: \begin{wrapfigure}{l}{4cm} \begin{tikzpicture} \draw [thick ,->] (-2,0) -- (2,0); \draw [thick,->] (0,-2) -- (0,2); \draw [thick] (0,0) circle (1.5); \draw[thick,->] (0,0) -- (1.08,1.08); \draw (0.7,0.3) node {$r$}; \end{tikzpicture} \end{wrapfigure} \hspace{-5pt} Tomamos la parametrización de la circunferencia de centro $(0,0)$ y radio $r$ dada por $\alpha: t \in [0,2\pi] \mapsto (r\cos t, r \sin t)$. \\Se tiene que $\alpha'(t) = (-r\sin t,r\cos t)$, así, $$L(\alpha|_{[a,b]}) = \int_0^{2\pi} || \alpha'(t)|| dt = \int_0^{2\pi} \sqrt{(-r \sin t)^2 + (r \cos t)^2}dt = r \int _0^{2\pi}dt = 2\pi r,$$lo que coincide con la intuición. Cabe preguntarse ahora si la longitud depende de nuestra parametrización (que no debería). \subsection{Reparametrización de una curva.} \begin{defi}[]{} Supongamos que tenemos una curva parametrizada $\alpha:I \subset \R \to \R^n$. Se $f: I \subset \R \to I \subset \R$ un difeomorfismo (diferenciable, biyectiva y con inversa diferenciable). Decimos que $\beta:= \alpha \circ f$ es una \textbf{reparametrización } de $\alpha$. \end{defi} Note: the environment 'defi' is a newtcolorbox custom environment.

[cfr: The original question concerned cleveref together with hyperref. Further analysis shows the problem can be reproduced without cleveref.] When I use cleveref and hyperref packages together, the white space between the number label and the following Chinese character is missing, while the output is normal if loading cleveref alone. Here is a MWE which uses xelatex and is compiled in TeXstudio with texlive2024. \documentclass{ctexbook} \usepackage{mathtools} %\usepackage[hidelinks]{hyperref} \usepackage{cleveref} \crefname{figure}{图}{图} \begin{document} \begin{figure}[t] \centering This is a figure! \caption{Text figure.\label{fig}} \end{figure} 结果由\cref{fig}给出, which means the result is shown in Fig. 1. \end{document} The output when loading cleveref package alone is given by However, if loading hyperref package before (necessary condition when loading cleveref and hyperref together), the output is given by which can be seen that the white space is missing. I don't know how to handle this problem. Could someone do me a favor? Thanks a lottt! 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LaTeX Font Info: Overwriting math alphabet `\mathit' in version `normal' (Font) OT1/cmr/m/it --> TU/lmr/m/it on input line 7. LaTeX Font Info: Overwriting math alphabet `\mathbf' in version `normal' (Font) OT1/cmr/bx/n --> TU/lmr/b/n on input line 7. LaTeX Font Info: Overwriting math alphabet `\mathsf' in version `normal' (Font) OT1/cmss/m/n --> TU/lmss/m/n on input line 7. LaTeX Font Info: Overwriting math alphabet `\mathtt' in version `normal' (Font) OT1/cmtt/m/n --> TU/lmtt/m/n on input line 7. LaTeX Font Info: Overwriting symbol font `operators' in version `bold' (Font) TU/lmr/m/n --> TU/lmr/b/n on input line 7. LaTeX Font Info: Overwriting math alphabet `\mathit' in version `bold' (Font) OT1/cmr/bx/it --> TU/lmr/b/it on input line 7. LaTeX Font Info: Overwriting math alphabet `\mathsf' in version `bold' (Font) OT1/cmss/bx/n --> TU/lmss/b/n on input line 7. LaTeX Font Info: Overwriting math alphabet `\mathtt' in version `bold' (Font) OT1/cmtt/m/n --> TU/lmtt/b/n on input line 7. (c:/wswApps/texlive/2024/texmf-dist/tex/latex/graphics/graphicx.sty Package: graphicx 2021/09/16 v1.2d Enhanced LaTeX Graphics (DPC,SPQR) (c:/wswApps/texlive/2024/texmf-dist/tex/latex/graphics/graphics.sty Package: graphics 2022/03/10 v1.4e Standard LaTeX Graphics (DPC,SPQR) (c:/wswApps/texlive/2024/texmf-dist/tex/latex/graphics/trig.sty Package: trig 2021/08/11 v1.11 sin cos tan (DPC) ) (c:/wswApps/texlive/2024/texmf-dist/tex/latex/graphics-cfg/graphics.cfg File: graphics.cfg 2016/06/04 v1.11 sample graphics configuration ) Package graphics Info: Driver file: xetex.def on input line 107. (c:/wswApps/texlive/2024/texmf-dist/tex/latex/graphics-def/xetex.def File: xetex.def 2022/09/22 v5.0n Graphics/color driver for xetex )) \Gin@req@height=\dimen194 \Gin@req@width=\dimen195 ) [1 ] (./document.aux) *********** LaTeX2e <2023-11-01> patch level 1 L3 programming layer <2022/07/14> *********** ) Here is how much of TeX's memory you used: 10349 strings out of 474772 277375 string characters out of 5757709 1920842 words of memory out of 5000000 32429 multiletter control sequences out of 15000+600000 559831 words of font info for 53 fonts, out of 8000000 for 9000 1348 hyphenation exceptions out of 8191 93i,5n,97p,3268b,271s stack positions out of 10000i,1000n,20000p,200000b,200000s Output written on document.pdf (1 page). A shorter MWE without cleveref: \documentclass{ctexbook} % \usepackage{hyperref} %% Uncomment this line to reproduce \pagestyle{empty} \begin{document} \begin{figure}[h]\caption{caption\label{ref}}\end{figure} \clearpage \tracingoutput=1 \tracingonline=1 \showboxdepth=\maxdimen \showboxbreadth=\maxdimen \shipout\hbox{由\ref{ref}} \end{document} Correct output (with hyperrref commented out): \hbox(8.14693+1.65466)x19.31866 .\TU/FandolSong-Regular(0)/m/n/10.53937 由 .\glue 3.50961 plus 1.7548 minus 1.16986 .\TU/lmr/m/n/10.53937 1 .\kern -0.0002 .\kern 0.0002 .\hbox(0.0+0.0)x0.0 Incorrect output (with hyperrref enabled): \vbox(8.14693+1.65466)x15.80905 .\vbox(0.0+0.0)x0.0, glue set - 20.99626fil ..\kern 0.0 ..\kern 22.0 ..\kern -1.00374 ..\hbox(0.0+0.0)x0.0, glue set - 87.99626fil ...\kern 0.0 ...\kern 89.0 ...\kern -1.00374 ...\special{pdf:dest (page.2) [@thispage /XYZ @xpos @ypos null]} ...\penalty 10000 ...\glue 0.0 plus 1.0fil minus 1.0fil ..\glue 0.0 plus 1.0fil minus 1.0fil .\glue(\lineskip) 0.0 .\hbox(8.14693+1.65466)x15.80905 ..\TU/FandolSong-Regular(0)/m/n/10.53937 由 ..\kern -0.00017 ..\kern 0.00017 ..\special{pdf:bann<</Type/Annot/Subtype/Link/Border[0 0 1]/H/I/C[1 0 0]/A<</S/GoTo/D(figure.0.1)>>>>} ..\TU/lmr/m/n/10.53937 1 ..\kern -0.0002 ..\kern 0.0002 ..\special{pdf:eann}

I am writing a document where I keep having to write variables that fall between two numbers, say, 10 < x \leq 3 or in some cases even between two quantities such as 12.5 mg < x \leq 3.5 mg. I wrote a macro named \nestednumrange and \nestedqtyrange. Here is my minimal example: \documentclass{article} \usepackage{siunitx} \newcommand{\nestednumrange}[3]{% \ensuremath{\num{#1} #2 \num{#3}}% } \newcommand{\nestedqtyrange}[4]{% \ensuremath{\qty{#1}{#4} #2 \qty{#3}{#4}}% } \begin{document} \nestednumrange{3}{\leq x}{<2} \nestedqtyrange{3}{\leq c}{\leq 3}{\milli\gram} \end{document} I'm happy that is (somehow) works, but the output is a bit ugly, imho: How do I "center" the variable correctly? Should I perhaps add two more {}s specifically for the signs, so that they aren't linked to any element in the macro? Unfortunately, I don't know how to make the macro only accept operators like <, >, \leq, \geq, and =, and throw errors at others.

In many computer algebra systems, one can sum a sequence of numbers using the syntax sum(a(k), k, kStart, kEnd) for a sequence a(k) (of real and integer values) with the variable k. What's the best and fastest way to do this with LaTeX? For example, when you want to calculate thousands of values ​​for a table. I've developed a MWE using foreach and fpeval. \documentclass[margin=5pt, varwidth]{standalone} \usepackage{amsmath} \usepackage{tikz} \newcommand\Sum[4]{% \def\mysum{0}% \foreach #2 in {#3,...,#4}{% \def\psum{\fpeval{(#1)}}% \xdef\mysum{\fpeval{\mysum+\psum}}% }\mysum} \begin{document} Test 1: $\displaystyle\sum\limits_{k=1}^{100} k = \Sum{\k}{\k}{1}{100}$ \newcommand\binomial[2]{\fpeval{fact(#1)/(fact(#2)*fact(#1-#2))}} Test 2: $\displaystyle\sum\limits_{k=0}^{5} \dbinom{5}{k} = \Sum{ \binomial{5}{\k} }{\k}{0}{5} =2^5 = \fpeval{2^5}$ \end{document}

in developing a class I have come to use the so called templates documented in lttemplate. It is a expl3-Class therefore I looked at ways to define Template Types, Templates and Instances in expl3 Syntax but there are no such interfaces. Is there a particular reason why templates do not have a expl3 interface? Or was I not capable enough to find it?