Week

In an expl3 package a Lua module shall be used because Lua simplifies programming some functions. The Lua module shall call some expl3 functions from the package. But this does not work in all cases. In the following example only \MyDocumentCommandA works, not \MyDocumendCommandB. \begin{filecontents*}{mypackage.sty} \ProvidesExplPackage{mypackage}{2025-12-27}{1.0}{My package} \directlua { myluamodule = require ('myluamodule') } \cs_new:Npn \mypackage_command:n #1 { \int_to_Roman:n {#1} } \NewDocumentCommand \MyDocumentCommandA {m} { \directlua { myluamodule.functionA ( #1 ) } } \NewDocumentCommand \MyDocumentCommandB {m} { \directlua { myluamodule.functionB ( #1 ) } } \end{filecontents*} \begin{filecontents*}{myluamodule.lua} local myluamodule = {} myluamodule.functionA = function (nr) tex.sprint("bla blub ") tex.sprint("\\ExplSyntaxOn") tex.sprint("\\mypackage_command:n{"..nr.."}") tex.sprint("\\ExplSyntaxOff") end myluamodule.functionB = function (nr) tex.sprint("\\section{") myluamodule.functionA(nr) tex.sprint("}") end return myluamodule \end{filecontents*} \documentclass{article} \usepackage{mypackage} \begin{document} \MyDocumentCommandA{75} \MyDocumentCommandB{85} \end{document} The error message is: ! Undefined control sequence. <argument> bla blub \ExplSyntaxOn \mypackage _command:n{85}\ExplSyntaxOff l.43 \MyDocumentCommandB{85}

I have the following code: \documentclass{article} \usepackage{unicode-math} % \setmathfont{NewCMMath-Regular.otf} % normal \setmathfont{NewCMMath-Book.otf} % abnormal \begin{document} \[ \overrightarrow{e} \quad \overrightarrow{\pi} \quad \overrightarrow{\Pi} \] \end{document} Which gives: We noticed that if the arguments is too wide, the glitch appeared. While it's normal with NewCMMath-Regular.otf:

I would like to reproduce the following diagram in Yves André's book: However, it is unclear to me how to produce the multi-line node inside the diagram. Currently, what I could achieve is this: However, the alignment inside aligned is not working the way I expected. May I ask what is the correct way to do this? Thanks! Below is a MWE. \documentclass{article} \usepackage{mathtools,amssymb} \usepackage{tikz-cd} \begin{document} \[ \begin{tikzcd} {\{\,{\text{\( k \)-schémas étales finis}}\,\}} & {\begin{aligned} &\{\, \text{ensembles finis munis}\\ &\quad\text{d'une action continue de \( \mathrm{Gal}(\overline{k}/k) \)}\,\} \end{aligned}} \\ {AM(k)_{\mathbb{Q}}} & {\begin{aligned} &\{\, \text{\( \mathbb{Q} \)‑espaces vectoriels de dimension finie munis}\\ &\quad\text{d'une action linéaire continue de \( \mathrm{Gal}(\overline{k}/k) \)}\,\} \end{aligned}} \arrow["\sim", from=1-1, to=1-2] \arrow["{\mathfrak{h}}"', from=1-1, to=2-1] \arrow["{\mathfrak{l}}", from=1-2, to=2-2] \arrow["\sim", from=2-1, to=2-2] \end{tikzcd} \] \end{document}

I've seen examples in a couple manuals and the contextgarden wiki site for \setupheaders how text for middle, left, and right can be set with two statements--first the middle, and then the combined left/right for odd/even pages. My question is, In this facing-pages layout, how can the middle text be different for odd and even pages? Can the line \setupheadertexts[Center_Text] be made to distinguish odd/even? Thank you. \definepapersize [book] [width=8.16in,height=10.66in] \setuppapersize [book] [letter] \setuppagenumbering[alternative=doublesided,location=] \setuplayout [backspace=1in, width=4in, leftmargin=.5in, leftmargindistance=.5in, rightmargin=1in, rightmargindistance=1in] \setupheadertexts[Center_Text] \setupheadertexts[left_on_odd][Page \pagenumber][Page \pagenumber][rght_on_even] % \showframe \starttext % \showlayout[pt,in] \dorecurse {5} {\samplefile {knuth}\par} \stoptext I also tried the following lines (after reading this answer) but the middle text isn't really in the middle of the header. % \setupheadertexts[Center_Text] \setupheadertexts[left_on_odd\hfill Middle_Odd\hfill][Page \pagenumber][Page \pagenumber][\hfill Middle_Even\hfill rght_on_even]

I have seen some nice examples from the Millennial font package. However, I couldn't find it anywhere in the Internet. I've tried http://www.math.unl.edu/~shartke2/computer/latex/Millennial-20110819.tar.bz2 but Professor Stephen Hartke, the package's author leaved UNL in 2015 so, although some files are available from Internet Archive like the character's test, the page is gone and so the package there. Even on Reddit I couldn't get a valid link, so I'm humbling asking if anyone here hold a copy of it that you could share. I know it's old and there are modern alternatives to it but, for some of my purposes, this T1 package would come in handy.

All is in the title: I have a current document with (plain) numbered pages and I would like to interleave blank pages but only after current page 3, that is, put one blank page between every plain page, starting from page 3 (so keep my current pages 1, 2, 3 unchanged, then start interleaving blank pages). These blank pages should be either numbered or not numbered but keeping the numbering of the plain pages coherent (i.e., I don't want to go from plain page 4 to 6). I can not use newpage since of course, I don't exactly know where the page breaks might occur regarding the content. Thanks in advance for help !

About 15 years ago, I had created a drawing using GeoGebra that looks similar to the attached image. The source .ggb file from GeoGebra is available here, and I'm happy to share it with anyone interested. I was wondering if it's possible to replicate this drawing exactly using TikZ-PGF. I have the .ggb file and I'm wondering if there's a way to convert it or if TikZ can reproduce the same graphic. Additionally, I found a more recent package, named pst-sphericaltrochoid, which might be useful for generating spherical trochoid curves, and the package is documented in the PDF manual from December 25, 2025. Moreover, I would like to have this drawing animated in LaTeX. When export in tikz-pgf using Geogebra the output is not the expected result like the image (with animations). I never done a drawing with animate package or similar. \documentclass[10pt]{article} \usepackage{pgfplots} \pgfplotsset{compat=1.15} \usepackage{mathrsfs} \usetikzlibrary{arrows} \pagestyle{empty} \begin{document} \definecolor{ffwwqq}{rgb}{1,0.4,0} \definecolor{zzttqq}{rgb}{0.6,0.2,0} \definecolor{xdxdff}{rgb}{0.49019607843137253,0.49019607843137253,1} \begin{tikzpicture}[line cap=round,line join=round,>=triangle 45,x=1cm,y=1cm] \begin{axis}[ x=1cm,y=1cm, axis lines=middle, grid style=dashed, xmin=-24.649425971185988, xmax=51.05123247996474, ymin=-17.77843276444837, ymax=20.90166759086156, xtick={-20,-15,...,50}, ytick={-15,-10,...,20},] \clip(-24.649425971185988,-17.77843276444837) rectangle (51.05123247996474,20.90166759086156); \draw [line width=0.8pt] (0,0) circle (8cm); \draw [line width=0.8pt] (4.690951292494638,6.480353074597315) circle (2cm); \draw[line width=4pt] (-22.73456951795283,17.710240168806287) -- (-9.968859829731798,17.710240168806287); \draw[line width=4pt] (-22.73456951795283,15.157098231162069) -- (-9.968859829731798,15.157098231162069); \begin{scriptsize} \draw [fill=xdxdff] (4.690951292494638,6.480353074597315) circle (0.5pt); \draw[color=xdxdff] (4.137249375752443,7.338101047126645) node {$A$}; \draw [fill=black] (-17.202761986390385,17.710240168806287) circle (2.5pt); \draw[color=black] (-16.096400480077897,19.40169670249558) node {$k = 1.3$}; \draw [fill=zzttqq] (2.345168103332513,5.359058630909856) circle (1pt); \draw[color=zzttqq] (4.392563569516864,6.316844272068956) node {$Pianeta$}; \draw [fill=black] (-17.06092076763237,15.157098231162069) circle (2.5pt); \draw[color=black] (-16.479371770724526,16.848554764851364) node {$v = 5$}; \draw [color=ffwwqq] (0,0) circle (4.5pt); \draw[color=ffwwqq] (1.264964695902711,1.4658745905449386) node {$Sole$}; \end{scriptsize} \end{axis} \end{tikzpicture} \end{document} My idea is to animate the drawing using the animate package for my students of an high school, with the ability to modify parameters and see how the drawing changes in real time. Could I add interactive buttons to allow users to modify the parameters of the animation? If anyone has experience animating drawings in LaTeX, I'd be happy to receive suggestions on how to implement it. Also, how can I animate package this drawing and add interactive buttons to control the parameters?

I am trying to set the metadata in my ebook via the following cfg file, but it only works partially: \Preamble{xhtml} \Configure{OpfMetadata}{% \HCode{<dc:title xml:lang="de">My ebook</dc:title>} \HCode{<dc:creator>My name</dc:creator>} \HCode{<dc:language>en</dc:language>} \HCode{<dc:date>2025-25-12</dc:date>} \HCode{<dc:subject>Ebook</dc:subject>} \HCode{<dc:description>This is an ebook</dc:description>} \HCode{<dc:keywords>My keywords</dc:keywords>} \HCode{<dc:publisher>My publisher</dc:publisher>} \HCode{<dc:identifier>My identifier</dc:identifier>} } \begin{document} \EndPreamble The meta data looks fine for subject, description, keywords and publisher. However, for the title, Calibri only shows "Unnamed". For the author, it shows "Anonymous & My name" instead of only "My name", the date shows today's date and not the one I had selected, and it doesn't show an identifier. How can I ensure that all meta data is correctly displayed? Here is an MWE which I ran with the above cfg file. \documentclass{book} \usepackage{tex4ebook} \begin{document} \tableofcontents \part{Headline} This is an ebook. \end{document}

I'm trying with: \documentclass[]{article} \usepackage[numbers,super,sort&compress,comma]{natbib} \begin{document} Test\cite{ref1,ref2,ref3,ref4,ref5,ref6,ref7,ref8,ref9,ref10} \begin{thebibliography}{99} \bibitem{ref1} Entry 1 \bibitem{ref2} Entry 2 \bibitem{ref3} Entry 3 \bibitem{ref4} Entry 4 \bibitem{ref5} Entry 5 \bibitem{ref6} Entry 6 \bibitem{ref7} Entry 7 \bibitem{ref8} Entry 8 \bibitem{ref9} Entry 9 \bibitem{ref10} Entry 10 \end{thebibliography} \end{document} For HTML conversion, I'm trying with make4ht filename and the output was: If I remove the option super, then it works correctly: But I'm in need to use options numbers,super,sort&compress,comma, how can I meet this? Please advise.

I'm thinking about migrating several large documents from cleveref to zref-clever. I have read Migration from cleveref to zref-clever as well as the manual, but several questions remain. One of them is: How I can control whether references to equations include "equation" or "equations" before the label(s), independently of whether references to figures and tables include "figure" and "table"? (The reasoning is that equations are numbered with parentheses whereas figures and tables are numbered without parentheses. Thus, it is clear that "see (1)" means equation (1) whereas "see 1" would be ambiguous because it could mean either Figure 1 or Table 1.) My understanding is that I need to use the option noname when referring to each equation. To avoid having to type the option in each reference, I could define a new command: \documentclass{article} \usepackage{zref-clever} \newcommand{\zcrefeq}[1]{\zcref[noname]{#1}} \begin{document} \begin{equation}\label{eq:1} a = b \end{equation} \begin{figure}[h] \caption{Some figure.} \label{fig:1} \end{figure} We have \zcrefeq{eq:1} and \zcref{fig:1}. \zcref[S]{eq:1} is the first equation. \end{document} Is there a more elegant way of doing this by setting an overall option or a reference format option?

First of all "Merry Christmas" to everyone. I'm trying to get decimal output with luacas and don't get it. \documentclass[paper=a4,fontsize=12pt]{scrartcl} \usepackage{luacas} \begin{document} \directlua{ a=3 b=8 c=a/b tex.print('$',c,'$') } \end{document} The code above gives the expectet 0.375. Changing to \documentclass[paper=a4,fontsize=12pt]{scrartcl} \usepackage{luacas} \begin{document} \begin{CAS} a=3 b=8 c=Rational(a,b) \end{CAS} $\print{a}$ $\print{b}$ $\print{c}$ $\print{c.numerator}$ $\print{c.denominator}$ \end{document} gives 3, 8, the fraction 3 over 8, 3 and 8. In the manual there is the funtion :asnumber() given but \documentclass[paper=a4,fontsize=12pt]{scrartcl} \usepackage{luacas} \begin{document} \begin{CAS} a=3 b=8 c=Rational(a,b) d=c:asnumber() \end{CAS} $\print{a}$ $\print{b}$ $\print{c}$ $\print{c.numerator}$ $\print{c.denominator}$ $\print{d}$ \end{document} gives Lua-Error and the $\print{d}$ is ignored. I also tried something like d=Rational:asnumber(c) or used the funktions ZZ(), QQ() and RR() but without any success. Also $\print{c:asnumber()}$ fails. Trying to print the decimal with $\directlua{tex.print(string.format("\csstring\%.3f",c))}$ gives also a Lua error ('c' is a table but a number is expected by 'string.format()'). I'm not having any ideas how to solve it any more. Thank you for your help.

I'm writing a document with XeTeX that uses Calibri as its main font (this is non-negotiable). An issue with Calibri is that capital I and lowercase l look nearly identical. Is it possible to add a serifed I to the font somehow, so that they are clearly distinguished throughout the document? I know that this might not be an entirely LaTeX question and I might need to look into the TTF files I'm using, but I'm unsure how I would even set something up for this.

is it possible to make a stroke that transitions from thick to thin, like a Chinese brush or a calligraphy pen? Not like a bent hook that fakes the transition using elliptical pens, that one is cheating. I want a perfectly straight line, that starts out thick and transitions to thin. Is it possible to do such a "dynamic brush" effect"?

The TikZ tangent coordinate system appears to be inaccurate. The blue and red lines are expected to overlap, but they fail to do so. \documentclass{standalone} \usepackage{tikz} \usetikzlibrary{calc} \begin{document} \begin{tikzpicture} \draw [help lines,dotted,thick] (0,0) grid (10,10); \def\rA{.5} \def\rB{4} \coordinate (OA) at (1,1); \coordinate (OB) at (5,5); \path (OA) node (A) [draw,circle,minimum size=2*\rA cm] {A}; \path (OB) node (B) [draw,circle,minimum size=2*\rB cm] {B}; \path ($(A.center)!{\rA/(\rA - \rB)}!(B.center)$) coordinate (X) node [below left] {X}; \path (tangent cs:node=A,point={(X)},solution=1) coordinate (A1); \path (tangent cs:node=A,point={(X)},solution=2) coordinate (A2); \path (tangent cs:node=B,point={(X)},solution=1) coordinate (B1); \path (tangent cs:node=B,point={(X)},solution=2) coordinate (B2); \draw [blue] (X) -- (A1) -- ([turn]0:9cm); \draw [red] (X) -- (B1) -- ([turn]0:5cm); \draw [blue] (X) -- (A2) -- ([turn]0:9cm); \draw [red] (X) -- (B2) -- ([turn]0:5cm); \end{tikzpicture} \end{document} Corrected by adding outer sep=0pt: \documentclass{standalone} \usepackage{tikz} \usetikzlibrary{calc} \begin{document} \begin{tikzpicture} \draw [help lines,dotted,thick] (0,0) grid (10,10); \def\rA{.5} \def\rB{4} \coordinate (OA) at (1,1); \coordinate (OB) at (5,5); \path (OA) node (A) [draw,circle,minimum size=2*\rA cm,outer sep=0pt] {A}; %% \path (OB) node (B) [draw,circle,minimum size=2*\rB cm,outer sep=0pt] {B}; %% \path ($(A.center)!{\rA/(\rA - \rB)}!(B.center)$) coordinate (X) node [below left] {X}; \path (tangent cs:node=A,point={(X)},solution=1) coordinate (A1); \path (tangent cs:node=A,point={(X)},solution=2) coordinate (A2); \path (tangent cs:node=B,point={(X)},solution=1) coordinate (B1); \path (tangent cs:node=B,point={(X)},solution=2) coordinate (B2); \draw [blue] (X) -- (A1) -- ([turn]0:9cm); \draw [red] (X) -- (B1) -- ([turn]0:5cm); \draw [blue] (X) -- (A2) -- ([turn]0:9cm); \draw [red] (X) -- (B2) -- ([turn]0:5cm); \end{tikzpicture} \end{document}

I have defined a counter (firstcounter) and, in the first column, item numbers display as I'd expect. However, in the middle column with the same code (but a secondcounter to avoid interaction with the first list), I have changed \only<1-> to \only<1-4> and it breaks the numbering. The right hand column (with two separate counters, thirdcounter and fourthcounter), 'works' but unsatisfactorily; I feel I should not need an extra counter for each resumption of enumeration. Can someone explain to me what I'm doing wrong? \documentclass{beamer} \newcounter{firstcounter} \newcommand{\setfirst}{\setcounter{firstcounter}{\value{enumi}}} \newcommand{\contfirst}{\setcounter{enumi}{\value{firstcounter}}} \newcounter{secondcounter} \newcommand{\setsecond}{\setcounter{secondcounter}{\value{enumi}}} \newcommand{\contsecond}{\setcounter{enumi}{\value{secondcounter}}} \newcounter{thirdcounter} \newcommand{\setthird}{\setcounter{thirdcounter}{\value{enumi}}} \newcommand{\contthird}{\setcounter{enumi}{\value{thirdcounter}}} \newcounter{fourthcounter} \newcommand{\setfourth}{\setcounter{fourthcounter}{\value{enumi}}} \newcommand{\contfourth}{\setcounter{enumi}{\value{fourthcounter}}} \begin{document} \begin{frame} %left column \begin{minipage}{0.3\textwidth} \only<1->{ \begin{enumerate} \item 1st \item <2-> 2nd \item <3-> 3rd. \item <4-> 4th \setfirst \end{enumerate} } \only<5->{ \begin{enumerate} \contfirst \item 5th. \item <6-> 6th. \item <7-> 7th. \setfirst \end{enumerate} } \only<8->{ \begin{enumerate} \contfirst \item 8th. \item <9-> 9th. \item <10-> 10th. \end{enumerate} } \end{minipage} % middle column \begin{minipage}{0.3\textwidth} \only<1-4>{ \begin{enumerate} \item 1st \item <2-> 2nd \item <3-> 3rd. \item <4-> 4th \setsecond \end{enumerate} } \only<5->{ \begin{enumerate} \contsecond \item 5th. \item <6-> 6th. \item <7-> 7th. \setsecond \end{enumerate} } \only<8->{ \begin{enumerate} \contsecond \item 8th. \item <9-> 9th. \item <10-> 10th. \end{enumerate} } \end{minipage} % right column \begin{minipage}{0.3\textwidth} \only<1-4>{ \begin{enumerate} \item 1st \item <2-> 2nd \item <3-> 3rd. \item <4-> 4th \setthird \end{enumerate} } \only<5->{ \begin{enumerate} \contthird \item 5th. \item <6-> 6th. \item <7-> 7th. \setfourth \end{enumerate} } \only<8->{ \begin{enumerate} \contfourth \item 8th. \item <9-> 9th. \item <10-> 10th. \end{enumerate} } \end{minipage} \end{frame} \end{document} These are all the same lists and should have the same numbering.

The following M(not)WE fails because of the \Cdots used. Is there a quick fix of this bug? The log file indicates the error below if I uncomment the failing sub matrix command. Package nicematrix Error: Impossible delimiter. (nicematrix) It's impossible to draw the right delimiter of (nicematrix) your \SubMatrix because all the cells are empty (nicematrix) in that column. (nicematrix) This \SubMatrix will be ignored. Here is the LaTeX code. \documentclass[border=5pt, varwidth]{standalone} \usepackage{nicematrix} \begin{document} $\begin{NiceArray}{*{7}{c}}[cell-space-limits=3pt] & & & & & & \Vdots \\ & & & & & & a[k]_{mj} \\ & & & & & & \Vdots \\ & & & & & & a[k]_{m'j} \\ & & & & & & \Vdots \\ & & & & & & \phantom{X} \\ \Cdots & 1 & \Cdots & 0 & \Cdots & \hspace{12.5pt} & a[k+1]_{ij} % \CodeAfter \SubMatrix({1-7}{5-7})[slim] % \SubMatrix({7-1}{7-5}) % <-- This fails! \SubMatrix({7-7}{7-7})%[slim] \end{NiceArray}$ $\begin{NiceArray}{*{7}{c}}[cell-space-limits=3pt] & & & & & & \Vdots \\ & & & & & & a[k]_{mj} \\ & & & & & & \Vdots \\ & & & & & & a[k]_{m'j} \\ & & & & & & \Vdots \\ & & & & & & \phantom{X} \\ Cdots & 1 & Cdots & 0 & Cdots & \hspace{12.5pt} & a[k+1]_{ij} % \CodeAfter \SubMatrix({1-7}{5-7})[slim] \SubMatrix({7-1}{7-5}) \SubMatrix({7-7}{7-7})%[slim] \end{NiceArray}$ \end{document} PS: for those who are curious, this is just to demonstrate how to calculate the number of paths of known length using an adjacency matrix.

While using [spanish]babel with a KOMA-script class (I've tried with scrartcl and scrbook) I get the following error: LaTeX hooks: Generic hooks cannot be added to '\@startsection'. How can I fix this? Here is my MWE. \documentclass{scrartcl} \usepackage[spanish]{babel} \begin{document} Buenos días. \end{document}

For quite some span of time, I was sure to have solved that problem. I got the build time from the original PDF file, e.g. via pdfinfo. Then i made the next build with SOURCE_DATE_EPOCH using exactly that time. Also FORCE_SOURCE_DATE must be set. This worked with lualatex and PDF 1.7. Now, adding pdfa/A, tagging, PDF/UA and moving on to PDF2.0, it does not work any more. Some experiments show, the critical feature is tagging. It is a great feature and i dont want to do without it. I search for a way to keep reproducibility even if tagging is present. Well, in fact, reproducibility is no longer trustable, sometimes it works. I observe that sometimes the lengths of the files differ minimally. Visually, they are the same, also XMP data seems the same. But my old simple concept of bytewise equivalence is gone. I tried with uncompress as suggested by DavidCarlisle, << /Type /Namespace /NS (data:,AC8956-1B7-A6A9-1928-C381ECC1E1C) >> << /Type /Namespace /NS (data:,5F48FB81-AC9C-B85B-A0B9-890FA89F45CC) >> is the first difference. The next is in a sequence of xref 0 17537 0000000002 65535 f 0007003671 00000 n 0000000003 00000 f But i cannot interprete these... and remarkable that even the trailer IDs coincide. In my dark thougths I even read the PDF spec and found that the trailer ID may depend on the location of the PDF also... So maybe there is another problem I do face only if there are more developers compiling in different environments. Maybe latex compilers dont use location to create the trailer ID, do they? Any advice on a sound foundation for reproducibiliby also in the future? Future is >PDF1.7, and PDF/A, PDF/UA, including tagging.

Is there a reference on how to make tables better, or a more standard way of pre-contemplating them? I was trying to tabulate the elementary linear transformations, and noticed that my table was rather unaesthetic. My hope is that someone could guide me on how I could better pre-contemplate these tables, so that they don't come out looking like this: \documentclass[letterpaper]{book} \usepackage{nicematrix} \usepackage{booktabs} \usepackage{tikz} \usepackage{microtype} \usepackage{mathtools} \usepackage{unicode-math} \newcommand{\temp}{% \begin{tikzpicture} \draw (-1,-1) rectangle (1,1); \node at (0,0) {Blah.}; \end{tikzpicture}% } \begin{document} \begin{table} \centering \begin{tabular}{lll} \toprule Linear transformation & Example Matrix & Geometric effect \\ \midrule Scale & \({\begin{bNiceArray}{cc} t & 0 \\ 0 & 1 \end{bNiceArray}}\) & \temp \\ \midrule Shear & \({\begin{bNiceArray}{cc} 1 & t \\ 0 & 1 \end{bNiceArray}}\) & \temp \\ \midrule Swap & \({\begin{bNiceArray}{cc} 0 & 1 \\ 1 & 0 \end{bNiceArray}}\) & \temp \\ \bottomrule \end{tabular} \caption{The elementary matrices are blah blah blah.} \label{table:chap-elem-mat} \end{table} \end{document}

I try to use tikz to plot the following image ... \documentclass[border=0.2cm]{standalone} \usepackage{pgfplots} \usepgfplotslibrary{colormaps} \pgfplotsset{compat = newest} \begin{document} \begin{tikzpicture} \begin{axis}[ axis equal image, grid = both, minor tick num = 2, xlabel = {$x$}, ylabel = {$y$}, zlabel = {$z$}, major grid style = {draw = lightgray}, minor grid style = {draw = lightgray!25}, xmin = 0, xmax = 1, ymin = 0, ymax = 1, zmin = 0, zmax = 2, scale = 3, view = {60}{30}, samples = 30, samples y = 30, z buffer = sort, ] % Kjeglesektor \addplot3[ surf, shader = interp, opacity = 0.75, colormap/viridis, ] ({x},{y},{sqrt(3)*sqrt(x^2+y^2)}); \end{axis} \end{tikzpicture} \end{document} But I do not get similar image ... can you please help me?

I want to automatically transliterate titles and author names I'm citing if they're written in another script. For example, given an author named مَحْمُود, I would like to be able to cite them inline as "(مَحْمُود maḥmūd 2020)". Supposing this author wrote a paper titled أَبْجَد هَوَّز, I would like to be able to cite it inline as "أَبْجَد هَوَّز ʾabjad hawwaz (مَحْمُود maḥmūd 2020)". Ideally the compiled bibliography should show these transliterations as well. I've written a Lua module transliteration.lua that exports a function transliterate() such that, for example, transliterate('مَحْمُود') returns the string 'maḥmūd'. However, I can't figure out where or if it's even possible to call my transliteration.transliterate() function within my paper in order for it to correctly apply to biblatex citations. This seems to interact in a complex way with the need to compile multiple times in order to format references correctly. Is there a combination of control sequences and compilation steps that will net exactly the citation formats I've described above? Is there a low-level way to override how names and titles and such are generated such that I can continue to use the default \cite(s), \parencite(s), \autocite(s), \citeauthor, etc. commands without redefining my own? This differs from prior transliteration questions like Auto transliteration in that I don't wish to directly write text in the other script. A question that seemed related was biblatex: Use field value in tex document before compilation but I couldn't figure out how to apply it to my situation. Below is a non-functioning example that demonstrates a rudimentary (and incorrect) understanding of \latelua, \expandafter, \DeclareCiteCommand, etc. (For demonstration, this is generic string substitution without reference to a specific script except in the comment about babel.) I am compiling this with the VSCode Latex Workshop extension's latexmk (lualatex) recipe, which as of writing runs latexmk -synctex=1 -interaction=nonstopmode -file-line-error -lualatex -outdir=%OUTDIR% %DOC%. -- transliteration.lua local exports = {} exports.transliterate = function(text) text = text:gsub("bb", "cc") text = text:gsub("aa", "bb") return text .. ' (this parenthetical indicates that the translit function ran)' end return exports \documentclass{article} \usepackage{biblatex} \directlua{tr = require("transliteration.lua")} \begin{filecontents}[overwrite]{test.bib} @misc{test, author = "aa", title = "bb", year = 2020} \end{filecontents} \addbibresource{test.bib} \DeclareCiteCommand{\translitciteauthor}{}{\directlua{tex.print(tr.transliterate("\\printnames{author}"))}}{}{} \begin{document} 1 % runs function but does not transliterate % additionally, if including babel and using an RTL script, this throws a "missing number, treated as zero" \directlua{tex.print(tr.transliterate("\\citeauthor{test}"))} 2 % runs function but does not transliterate \directlua{tex.print(tr.transliterate("\\expandafter{\\citeauthor{test}}"))} 3 % does nothing \latelua{pdf.print(tr.transliterate("\\citeauthor{test}"))} 4 % runs function but does not transliterate \translitciteauthor{test} \end{document}

I have the following code, but I can’t manage to replicate the figure shown in the attached image. Could you help me with the code and provide the figure? Thank you very much. \documentclass[12pt]{article} % --- Márgenes (opcional) --- \usepackage[margin=2.2cm]{geometry} % --- Idioma y acentos --- \usepackage[utf8]{inputenc} \usepackage[T1]{fontenc} \usepackage[spanish]{babel} % --- Matemática y TikZ --- \usepackage{amsmath,amssymb} \usepackage{xcolor} \usepackage{tikz} \usetikzlibrary{arrows.meta,calc,3d} \pagestyle{empty} \begin{document} \begin{center} % --- TU FIGURA --- \begin{tikzpicture}[ scale=1.15, line cap=round, line join=round, x={(-0.95cm,-0.55cm)}, % Eje X: oblicuo hacia abajo-izquierda y={(1.15cm,0cm)}, % Eje Y: horizontal z={(0cm,1.15cm)} % Eje Z: vertical ] % Colores/estilos \definecolor{axisblue}{RGB}{20,90,130} \tikzset{ axis/.style={very thick, draw=axisblue, -Latex}, proj/.style={dashed, black, line width=0.8pt}, edge/.style={black, line width=0.9pt}, face/.style={draw=black, fill=gray!35, opacity=0.55}, topface/.style={draw=black, fill=gray!25, opacity=0.55}, frontface/.style={draw=black, fill=gray!45, opacity=0.55} } % Ejes \draw[axis] (0,0,0) -- (4.8,0,0) node[below left] {Eje X}; \draw[axis] (0,0,0) -- (0,5.4,0) node[right] {Eje Y}; \draw[axis] (0,0,0) -- (0,0,4.8) node[above] {Eje Z}; % Título \node[anchor=west] at (0.9,2.4,4.0) {\Large Gráfico de $g(x,y)=x$}; % -------- PRISMA 1: x in [0,1], y in [-1,1], altura 1 -------- \def\xa{0}\def\xb{1} \def\ya{-1}\def\yb{1} \def\hA{1} % Vértices base \coordinate (A1) at (\xa,\ya,0); \coordinate (B1) at (\xb,\ya,0); \coordinate (C1) at (\xb,\yb,0); \coordinate (D1) at (\xa,\yb,0); % Vértices top \coordinate (A1t) at (\xa,\ya,\hA); \coordinate (B1t) at (\xb,\ya,\hA); \coordinate (C1t) at (\xb,\yb,\hA); \coordinate (D1t) at (\xa,\yb,\hA); % Proyecciones (sombras) al plano z=0 \draw[proj] (A1) -- (A1t); \draw[proj] (B1) -- (B1t); \draw[proj] (C1) -- (C1t); \draw[proj] (D1) -- (D1t); % Caras visibles \filldraw[frontface] (A1) -- (B1) -- (B1t) -- (A1t) -- cycle; % cara "frontal" \filldraw[face] (B1) -- (C1) -- (C1t) -- (B1t) -- cycle; % cara derecha \filldraw[topface] (A1t) -- (B1t) -- (C1t) -- (D1t) -- cycle; % tapa % Aristas principales \draw[edge] (A1) -- (B1) -- (C1) -- (D1) -- cycle; \draw[edge] (A1t) -- (B1t) -- (C1t) -- (D1t) -- cycle; \draw[edge] (A1) -- (A1t); \draw[edge] (B1) -- (B1t); \draw[edge] (C1) -- (C1t); \draw[edge] (D1) -- (D1t); % Etiquetas \node at (\xa,\ya,\hA) [above left] {$1$}; \node at (0.55,0, -0.02) [below, yshift=-2pt] {$[0,1]\times(-1,1)$}; % -------- PRISMA 2: x in [2,3], y in [-1,1], altura 2 -------- \def\xc{2}\def\xd{3} \def\hB{2} \coordinate (A2) at (\xc,\ya,0); \coordinate (B2) at (\xd,\ya,0); \coordinate (C2) at (\xd,\yb,0); \coordinate (D2) at (\xc,\yb,0); \coordinate (A2t) at (\xc,\ya,\hB); \coordinate (B2t) at (\xd,\ya,\hB); \coordinate (C2t) at (\xd,\yb,\hB); \coordinate (D2t) at (\xc,\yb,\hB); % Proyecciones \draw[proj] (A2) -- (A2t); \draw[proj] (B2) -- (B2t); \draw[proj] (C2) -- (C2t); \draw[proj] (D2) -- (D2t); % Caras \filldraw[frontface] (A2) -- (B2) -- (B2t) -- (A2t) -- cycle; \filldraw[face] (B2) -- (C2) -- (C2t) -- (B2t) -- cycle; \filldraw[topface] (A2t) -- (B2t) -- (C2t) -- (D2t) -- cycle; % Aristas \draw[edge] (A2) -- (B2) -- (C2) -- (D2) -- cycle; \draw[edge] (A2t) -- (B2t) -- (C2t) -- (D2t) -- cycle; \draw[edge] (A2) -- (A2t); \draw[edge] (B2) -- (B2t); \draw[edge] (C2) -- (C2t); \draw[edge] (D2) -- (D2t); % Etiquetas \node at (\xc,\ya,\hB) [above left] {$2$}; \node at (2.55,0,-0.02) [below, yshift=-2pt] {$[2,3]\times(-1,1)$}; % Marcas -1 y 1 sobre eje Y (opcional) \node at (0,-1,0) [below] {$-1$}; \node at (0, 1,0) [below] {$1$}; \end{tikzpicture} \end{center} \end{document}

I was wondering why there's a different polarity used in EU vs american symbols for voltage sources. As one can see the eu version and the american version have oposite polarity, which make's it hard once you start mixing circuits with a EU base and american base. example: \documentclass[a4paper,11pt]{article} \usepackage{circuitikz} \usepackage{siunitx} %\sisetup{locale = DE} % komma als decimaalteken (optioneel) \begin{document} \begin{circuitikz}[american] \draw (0,0) to[V=10V] (2,0); \end{circuitikz} \begin{circuitikz}[european] \draw (0,0) to[V=10V] (2,0); \end{circuitikz} \begin{circuitikz} \draw (0,0) to[V=10V] (2,0); \end{circuitikz} \end{document} So I get a polarity swap between EU and american If a read the manual it should not invert (image/code 1 vs 3 )

I am making the following table using LaTeX. One way to do it is to make a separate row for the "Top Header" header. However, this results in space below that header and the "sub headers": \documentclass{article} \usepackage{booktabs} \begin{document} \begin{table} \centering \begin{tabular}{ll rr} \toprule (1) & (2) & (3) & (4) \\ \midrule & & \multicolumn{2}{c}{Top Header} \\ \cmidrule(lr){3-4} Main & Main & \\ Header 1 & Header 2 & Sub 1 & Sub 2 \\ \midrule 0.01 & 0.25 & 0.05 & 0.00 \\ 0.02 & 0.25 & 0.11 & 0.03 \\ 0.05 & 0.25 & 0.16 & 0.09 \\ \bottomrule \end{tabular} \end{table} \end{document} An alternative way is to include "Top Header" on the same line as the top line of the "Main Headers", but the use of \cmidrule creates awkward space for the two "Main Headers": \documentclass{article} \usepackage{booktabs} \begin{document} \begin{table} \centering \begin{tabular}{ll rr} \toprule (1) & (2) & (3) & (4) \\ \midrule Main & Main & \multicolumn{2}{c}{Top Header} \\ \cmidrule(lr){3-4} Header 1 & Header 2 & Sub 1 & Sub 2 \\ \midrule 0.01 & 0.25 & 0.05 & 0.00 \\ 0.02 & 0.25 & 0.11 & 0.03 \\ 0.05 & 0.25 & 0.16 & 0.09 \\ \bottomrule \end{tabular} \end{table} \end{document} A third way, with no \cmidrule gets the vertical spacing right, but I do want a to use \cmidrule to get a line under "Top Header": \documentclass{article} \usepackage{booktabs} \begin{document} \begin{table} \centering \begin{tabular}{ll rr} \toprule (1) & (2) & (3) & (4) \\ \midrule Main & Main & \multicolumn{2}{c}{Top Header} \\ Header 1 & Header 2 & Sub 1 & Sub 2 \\ \midrule 0.01 & 0.25 & 0.05 & 0.00 \\ 0.02 & 0.25 & 0.11 & 0.03 \\ 0.05 & 0.25 & 0.16 & 0.09 \\ \bottomrule \end{tabular} \end{table} \end{document} How can I get columns 1 and 2 to behave as in the first table, but columns 3 and 4 to behave as in the second table? In other words, I'd like the headers to take up two lines, as in the second table, and I'd like to use the \cmidrule command for columns 3 and 4, but I don't want the the extra space in between "Main" and "Header 1" and "Main" and "Header 2" that we see in the second table.

I found that the behaviour of the voltage/distance from node-key varies depending on the component, as can be seen in the mwe below. Is there a fix that I am missing? Also, when I set voltage/distance from node=0 there is still some distance to the actual center of the node (marked in red). I have no idea where this is coming from (maybe a TikZ-thing?). I thought, maybe the inner sep of the nodes was not being accounted for, but after some testing, I found that the distance differs from the standard inner sep of nodes. Does someone have an idea? \documentclass{standalone} \usepackage{tikz} \usepackage[straightvoltages]{circuitikz} \begin{document} \begin{tikzpicture} \draw (0,0) to[R,name=R,v=U,voltage/distance from node=0] (2,0); \draw (0,-1) to[open,name=v,v=U,voltage/distance from node=0] (2,-1); \draw (0,-1.25) to[open,v=U,voltage/distance from node=0,open voltage position = legacy] (2,-1.25); \draw[red] (0,0 |- R-Vfrom) -- (R-Vfrom) node[midway,below] {?}; \draw[red] (0,-1) -- (v-Vfrom) node[midway,below] {?}; \end{tikzpicture} \end{document}

What is the correct syntax for placing a voltage arrow precisely between the two input terminals? By the way: To make the whole look nicer, I wanted to increase the pin lengths, but I couldn't manage it. I probably didn't place the current arrow quite correctly either, syntax-wise. \documentclass[margin=5pt, multi=circuitikz]{standalone} \usepackage{circuitikz} \begin{document} \begin{circuitikz} \node [en amp, %Increase pin length: %circuitikz/amplifiers/pin length=<*>, does not work ] (amp1) {}; \node [ocirc] at (amp1.-) {}; \node [ocirc] at (amp1.+) {}; \node [ocirc] at (amp1.out) {}; % v-arrow \draw[blue] ([xshift=-2mm]amp1.-) -- ([xshift=-2mm]amp1.+) node[midway, left] {$U$} node[sloped, currarrow, pos=1, blue] {}; % i-arrow \path[] (amp1.out) to[short, f=$\color{red}I$, color=red] ([xshift=5mm]amp1.out); \end{circuitikz} \end{document}

MWE: \documentclass[12pt]{article} \textwidth=3.5in \begin{document} \thispagestyle{empty} \begin{equation} \left( \frac{A}{B} \right) \end{equation} \vspace{35pt} \noindent How to enclose text extending over multiple lines with parentheses (\emph{as if} it were a fraction)? \end{document} The output: I would like to enclose text which extends over two or more lines by an appropriately sized set of parentheses. I have tried using \left( and \right) as if I were in a mathematical environment, such as shown in in the fractional expression. However, this does not work when in a text environment. Using $...$ does not help either. How may I enclose the given text, which extends over two lines, entirely with one set of appropriately sized parentheses?

How do I choose the anchor so that the line starts exactly at the edge at a path-source to[american current source]? \documentclass[margin=5pt, multi=circuitikz]{standalone} \usepackage{circuitikz} \begin{document} \begin{circuitikz}[] %\ctikzset{bipoles/border margin=0.0}% no effect \draw[] (0,0) to[american current source, o-o, name=GS] (2,0); \draw[->] (GS.north east) -- +(45:1); \end{circuitikz} \end{document}

The motivation Pfaff, Johann Friedrich: Methodus generalis, aequationes differentiarum partialium, nec non aequationes differentiales vulgares, utrasque primi ordinis inter quotcunque variabiles, complete integrandi The Problem \documentclass[a4paper,10pt]{article} \usepackage{amsmath} \usepackage{mathtools} \usepackage{unicode-math} \setmainfont{STIX Two Text} \setmathfont{STIX Two Math} \newcommand{\tprime}{\char"2034} % ‴ \newcommand{\qprime}{\char"2057} % ⁗ \begin{document} Prime notation: $x^{\prime},x^{\dprime},x^{\tprime},x^{\qprime}$ \end{document} Obviously, the desired result would be for the triple prime to look like the double prime with one more prime, and to look like the quadruple prime with one less prime. This appears to be a feature of unicode since it appears in browsers, in Kate, in Emacs, (differently un-uniform) in xterm. Is there a way to produce a uniform set of prime, double prime, triple prime, quadruple prime using LuaLaTeX? Preferably with STIX Two. Post Script. I was unaware that $x'''$ would work. I learned to author LaTeX using LyX which is WYSIWYM not WYSIWYG. I rarely compiled what I was writing. My reality was what I saw in LyX.

I ask this question only out of curiousity's sake. I am not actually planning on defining a new command called \cmd because the usual \cs macro has superior syntax. (\cmd<command name, including backslash> and \cs{<command name, omitting backslash>} would print the name of a command.) When defining and testing \cmd, I found a strange error where \cmd\par would issue an error even if \cmd is \long (+m in \NewDocumentCommand). So I think that the argument should accept \par tokens. After some trial and error, I randomly changed \texttt to \ttfamily and the error went away. My question is: Why did this fix the error? I don't understand why \texttt wouldn't work correctly in this case. I provide a MWE below to demonstrate the issue: \documentclass{article} \ExplSyntaxOn \NewDocumentCommand \cmdtesti { +m } { \__module_cmd_test_i:N #1 } \cs_new_protected:Npn \__module_cmd_test_i:N #1 { \group_begin: \ttfamily \token_to_str:N #1 \@ % works correctly when #1 is \par \group_end: } \NewDocumentCommand \cmdtestii { +m } { \__module_cmd_test_ii:N #1 } \cs_new_protected:Npn \__module_cmd_test_ii:N #1 { \texttt { \token_to_str:N #1 \@ } % This gives an error if #1 is \par. } \ExplSyntaxOff \begin{document} \cmdtesti\command % no error \cmdtestii\command % no error \cmdtesti\par % no error % \cmdtestii\par % gives an error % \cmdtestii{\par} % gives an error \end{document}