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I need to show the structure of the products and reactants in a chemical equation. However, the arrow is not horizontally aligned to the center of the chemical figures. Here is the commands \documentclass[12pt]{article} \special{papersize=3in,5in} \usepackage{chemmacros} \usepackage{chemfig} \usepackage[version=4] {mhchem} \begin{document} \begin{reaction*} \chemfig{(-[:210])(-[:330]OH)} ->[O] \chemfig{(-[:210])(=[:330]O)} \end{reaction*} \end{document}

Is there a remote possibility to have, -\infty and +\infty, below the real line using only the package nl-interval? PS: Actually I am not able to add a screenshot. Peraphs the problem is in tex.se. \documentclass{article} \usepackage{nl-interval} \begin{document} \begin{tikzpicture} \nlAxisX{-2}{5} \nlnuminf[pattern=north west lines]{1.5}[+3]{c}[.2] \end{tikzpicture} \begin{tikzpicture} \nlAxisX{-2}{5} \nlinfnum[pattern=north west lines]{1}[-5]{o}[.2] \end{tikzpicture} \begin{tikzpicture} \nlAxisX{-2}{5} \nlnumnum{-1}{o}{3}{c}[.2] \end{tikzpicture} \end{document}

This source compiles just fine with the line \DocumentMetadata{tagging=off} commented out, as shown. Why, if I uncomment that line, do I get a "TeX capacity exceeded" at line 15, and how can this be fixed? \NeedsTeXFormat{LaTeX2e}[2026-06-01] % !TEX program = lualatex %\DocumentMetadata{tagging=off} \documentclass{book} \usepackage{fontspec} \usepackage{lua-unicode-math} \usepackage[thmtools-compat]{keytheorems} \newkeytheoremstyle{thmstyle}{} \AtBeginDocument{\newkeytheorem{theorem}[name=Theorem,style=thmstyle,numberwithin=chapter]} \usepackage{hyperref} \begin{document} \chapter{A chapter} \section{The section} \begin{theorem}[A key theorem] Some theorem text \end{theorem} \end{document}

I have been searching for the best way to convert a .tex file to .docx I have tried a lot, but have not found the most trustworthy. I'm not the most knowledgeable in that sector, being in the humanities area, but love using latex. The teachers and scientific journals all ask for doc files. I don't need the easiest way, but the one that needs the least corrections and adjustments after conversion . I have windows, so it need to be possible on it.

Consider the following example: \documentclass{article} \usepackage{lipsum} \usepackage{enumitem} \begin{document} \begin{description}[style=nextline] \item[First item] \lipsum[11] \item[Second item] \begin{itemize} \item first subitem \item second subitem \end{itemize} \end{description} \end{document} Why itemize list in above example doesn't start in new line as other normal text do? Is this a bug? Well, I can manage this behaviour by adding \mbox{} after description label.

Is there any way to tell LaTeX to place a figure as close as possible to where it is in the source text, but to prioritise having as little whitespace as possible? Currently I'm using the code below \begin{figure}[h] \centering \includegraphics[width=\textwidth]{image.png} \caption{} \end{figure} but if the figure is too big, it gets sent to the end of the document on a page by itself (even if the figure doesn't take up a whole page). Leaving the [h] out is slightly better, but still puts the figure on a page by itself with lots of whitespace if it's big enough. The answers to this question suggest using [H], but that then again generates a potentially large amount of whitespace. At the moment my solution is to figure out manually where the best figure placement is, then navigate to that position in the source code and use [H] to make sure the is placed there, but of course as soon as I change any of the earlier text this breaks.

Using Latex Overleaf, I want to create a \subsubsubsection with \paragraph and \subsubsubsubsection with \subparagraph in \documentclass{amsart}. However, there are two problems: The \subsubsubsection returns an error sign If I add an * to the \subsubsubsection and \subsubsubsubsection (e.g., \subsubsubsection*), it won't disappear from the table of contents. \documentclass[11pt]{amsart} \newcommand{\subsubsubsection}{\paragraph} \newcommand{\subsubsubsubsection}{\subparagraph} \setcounter{secnumdepth}{5} \setcounter{tocdepth}{5} \title[Title]{Title} \author[Arbuja]{Arbuja Krishnan} \address{None, Unaffiliated, United States} \begin{document} \maketitle \tableofcontents \section{adhfk} \subsection{aksad} \subsubsection{fsajk} \subsubsubsection{agrg} \subsubsubsubsection{sjaf} \subsubsection{aehkfg} \subsubsubsubsection*{asfkdh} %We want this invisible from the table of contents%) \subsubsubsubsection*{asdgj} %We want this invisible from the table of contents%) \end{document} Question: How do I fix the problems above the code?

This is an extension of Replacing a Circle of Asterisks with Tikz Colored Stars Consider the code: \documentclass{book} \usepackage{tikz} \usetikzlibrary{shapes.geometric} \definecolor{thisblue}{RGB}{10,49,97} %\definecolor{thisred}{RGB}{179,25,66} \begin{document} \thispagestyle{empty} \pagecolor{thisblue} \noindent {\LARGE\bfseries{\textcolor{white}{Twelve even-spaced stars:}}} \vspace{10pt} \begin{center} \begin{tikzpicture} \foreach \k in {0,30,...,330} \node[ shape=star, star points=5, star point ratio=2.5, minimum size=0.8cm, fill=white, draw=white ] at (\k:3.5cm) {}; \end{tikzpicture} \end{center} \vspace{40pt} \noindent {\LARGE\bfseries{\textcolor{white}{Supposed to be thirteen even-spaced stars:}}} \vspace{10pt} \begin{center} \begin{tikzpicture} \foreach \k in {0,27.69,55.38,...,332.28} \node[ shape=star, star points=5, star point ratio=2.5, minimum size=0.8cm, fill=white, draw=white ] at (\k:3.5cm) {}; \end{tikzpicture} \end{center} \end{document} which produces: The first problem (regarding the second set of stars) is that there are only twelve stars (not thirteen). The second problem should be (the way I thought I have estimated it) should be roughly according to the thirteen (original colonies) represented as stars in the original (Betsy Ross) flag (See: Betsy Ross Flag): QUESTION: What am I doing wrong? How may I replicate the star-distribution on Betsy Ross' flag? (Incidentally, I still do not understand how my code did not display thirteen stars for the second figure.) Thank you.

In a manuscript there are two sections, the main part and the application part. For the main we use fourier package and for the application we use phv font with helvetica. The codes interfere with each other then. For example \Biggl(, \Biggr), \begin{cases} ... \end{cases} , \Biggl|, \Biggr| are not working for the fourier case. Also, \hbar is wrongly typed in the application part. Here is the code (given by AI) I am using % Configuration of \mathversion{application} (Helvetica / CM Math) \DeclareMathVersion{application} \SetSymbolFont{operators}{application}{T1}{phv}{m}{n} \SetSymbolFont{letters}{application}{OML}{cmm}{m}{it} \SetSymbolFont{symbols}{application}{OMS}{cmsy}{m}{n} \SetSymbolFont{largesymbols}{application}{OMX}{cmex}{m}{n} \SetMathAlphabet{\mathrm}{application}{T1}{phv}{m}{n} \SetMathAlphabet{\mathbf}{application}{T1}{phv}{b}{n} \SetMathAlphabet{\mathit}{application}{T1}{phv}{m}{it} % Dynamic Math Slot Switcher for Fourier <-> Application (Helvetica/CM) \makeatletter \let\fourier@orig@hbar\hbar % Fourier (normal) specific slots & delimiters \newcommand{\fourier@mathslots}{% \let\hbar\fourier@orig@hbar \global\mathcode`+ = "2280 \global\mathcode`- = "2200 \global\mathcode`= = "3281 \global\mathcode`< = "3282 \global\mathcode`> = "3283 % Delcodes for (, ), [, ], {, } \global\delcode`( = "0283A1 \global\delcode`) = "0293A2 \global\delcode`[ = "05B3A3 \global\delcode`] = "05D3A4 \global\delcode`\{ = "266328 \global\delcode`\} = "267329 % Macros for \lbrace, \rbrace, | \gdef\lbrace{\delimiter"4266328 }% \gdef\rbrace{\delimiter"5267329 }% \gdef\vert{\delimiter"026A30C }% \gdef\vertbar{\delimiter"026A30C }% } % Standard / Helvetica (application) slots & delimiters (CMEX/OMS) \newcommand{\standard@mathslots}{% \gdef\hbar{{\mathchar'26\mkern-9mu h}}% \global\mathcode`+ = "202B \global\mathcode`- = "2200 \global\mathcode`= = "303D \global\mathcode`< = "313C \global\mathcode`> = "313E % Delcodes for (, ), [, ], {, } \global\delcode`( = "028300 \global\delcode`) = "029301 \global\delcode`[ = "05B302 \global\delcode`] = "05D303 \global\delcode`\{ = "266308 \global\delcode`\} = "267309 % Macros for \lbrace, \rbrace, | \gdef\lbrace{\delimiter"4266308 }% \gdef\rbrace{\delimiter"5267309 }% \gdef\vert{\delimiter"026A30C }% \gdef\vertbar{\delimiter"026A30C }% } % Switch math slots when the math version changes \let\orig@mathversion\mathversion \renewcommand{\mathversion}[1]{% \orig@mathversion{#1}% \def\@tempa{#1}% \def\@tempb{normal}% \ifx\@tempa\@tempb \fourier@mathslots \else \standard@mathslots \fi } % Initialize in Fourier / normal mode \fourier@mathslots \makeatother Can you fix it so that two sections are working properly without interefering with each other? thanks.

How to adjust the opacity of the solution background in exam class? \documentclass[12pt]{exam} \usepackage[dvipsnames,x11names,svgnames]{xcolor} \shadedsolutions \colorlet{SolutionColor}{cyan!33} \usepackage{tikz} \usepackage{watermark} %-------------------------------- \watermark{ \begin{tikzpicture}[remember picture,overlay] \node [scale=1.1824,rotate=45,anchor=base,shift={(0em,6em)}] at (current page.center) [text width=1.64\linewidth,rounded corners,align=center] {{\color{pink} \parbox[][][m]{32cm}{ \LARGE{ {\center \hspace{6em}XXXXXXXXXXXXXX YYYYYYYYYYYYYYYY ZZZZZZZZZZZZZZZZ .......}}} }}; \end{tikzpicture} } \printanswers \begin{document} \begin{questions} \question $2+4=$ \begin{solution} $2+4=6$ \end{solution} \question $5+6$ \end{questions} \end{document}

If we run TeX on this example1.tex \hfuzz=\maxdimen \hsize=0pt \hyphenchar\font=`^^ff \hskip0pt error \bye in log file we get Missing character: There is no ^^ff in font cmr10! But if we change \language in example2.tex, this error message is not produced. Why? \language 1 \hfuzz=\maxdimen \hsize=0pt \hyphenchar\font=`^^ff \hskip0pt error \bye EDIT Let us load patterns. Create this my.tex: \input plain \language 1 \patterns {z4zy} \dump Then run tex -ini my to create my.fmt. Then run the example with new format: tex -fmt my example2 The warning in log file still does not appear. Why?

It is needed to implement \zleftrepeat command with \noindent\kern-1.6cm to avoid the offset, but it is not working. The basic code is as follow: \documentclass[12pt]{article} % ========== FORMATO DE PÁGINA: A4 VERTICAL ========== \usepackage[a4paper,portrait,left=0.4cm,right=0.2cm,top=0.2cm,bottom=0.2cm]{geometry} \pagestyle{empty} % ========== PAQUETES ========== \usepackage{tikz} \usetikzlibrary{quotes} \usetikzlibrary{shapes} \usetikzlibrary{fit,positioning} \usetikzlibrary{arrows.meta} \usetikzlibrary{decorations} \usepackage{amsmath} \usepackage{xcolor} \usetikzlibrary{calc} \usepackage{musicography} \usepackage{musixtex} \input musixlyr \input musixjt \xdefinecolor{red-undar}{RGB}{179,35,79} \begin{document} \begin{music} % ========== CONFIGURACIÓN GLOBAL ========== \parindent0mm% \staffbotmarg8\Interligne \font\B=phvb8t at 12pt \font\A=phvb8t at 10pt \A% \setsongraise1{6mm} \setstaffs1{1} \setlines{1}{5} \setclef{1}{\treble} \setclefsymbol{1}{\empty}% \generalmeter{\meterfrac34}% %\nobarnumbers% \systemnumbers% \def\raisebarno{5\internote}% % acerca el número al pentagrama \def\shiftbarno{-5pt}% % posición horizontal \def\writebarno{\eightrm\the\barno\barnoadd}% quita el recuadro, usa texto simple \nostartrule % ancho de sistema = ancho del texto de la página A4 (sin sobreancho) % ========== SISTEMA 1 (6 compases) ========== \startpiece \Notes\usf m\ibl1i0\qb1j\nbbl1\qb1j\tbl1\qb1j\usf m\ibl2i0\qb2{j}\tbl2\qb2{j}\Qqbbl jjjj\en\bar% \Notes\usf m\ibl1i0\qb1j\nbbl1\qb1j\tbl1\qb1j\usf m\ibl2i0\qb2{j}\tbl2\qb2{j}\Qqbbl jjjj\en\bar% \Notes\usf m\ibl1i0\qb1j\nbbl1\qb1j\tbl1\qb1j\usf m\ibl2i0\qb2{j}\tbl2\qb2{j}\Qqbbl jjjj\en\bar% \Notes\usf m\ibl1i0\qb1j\nbbl1\qb1j\tbl1\qb1j\usf m\ibl2i0\qb2{j}\tbl2\qb2{j}\Qqbbl jjjj\en\bar% \noindent\kern-1.6cm\zleftrepeat% \Notes\ccharnote{-5}{\hspace{-0.7cm}\p}\usf p\ql j\Dqbu fj\qu f\en\bar% \Notes\usf p\ql j\Dqbu fj\Dqbu ff\en\bar% \Notes\usf p\ql j\Dqbu fj\qu f\en\bar% \Notes\usf p\ql j\Dqbu fj\Dqbu ff\en\bar% \Notes\usf p\ql j\Dqbu fj\qu f\en\bar% \Notes\usf p\ql j\Dqbu fj\Dqbu ff\en\bar% \Notes\usf p\ql j\Dqbu fj\qu f\en\bar% \Notes\usf p\ql j\Dqbu fj\Dqbu ff\en\bar% \Notes\usf p\ql j\Dqbu fj\qu f\en\bar% \NOtes\stdstemfalse\smallnotesize\islurd{1}{j}\grcu j\en% \Notes\tslur{1}{j}\ql j\qp\qp\en\rightrepeat% \Notes\ccharnote{-19}{\hspace{0.3cm}\mf}\usf m\ibl0i0\qb0j\triolet l\nbbl0\qb0{jj}\tql0j\usf m\ibl1i0\qb1{j}\tbl1\qb1{j}\Qqbbl jjjj\en\bar% \NOtes\stdstemfalse\smallnotesize\islurd{1}{j}\grcu j\en% \Notes\tslur{1}{j}\ql j\qp\qp\en\bar% \NOtes\stdstemfalse\smallnotesize\islurd{1}{j}\grcu j\en% \Notes\tslur{1}{j}\fermataup{k}\ql j\qp\qp\en\setdoubleBAR% \nolyr% \lyricsoff% \endpiece% \end{music} \end{document} The current output is as follow: The desired output is as follow:

If we run TeX on this file \hfuzz=\maxdimen \hsize=0pt \hyphenchar\font=`^^ff \hskip0pt error \bye in log file we get Missing character: There is no ^^ff in font cmr10! But if we load rm-lmr10 font, this error message is not produced. Why? \font\F=rm-lmr10 \F \hfuzz=\maxdimen \hsize=0pt \hyphenchar\font=`^^ff \hskip0pt error \bye Which part of rm-lmr10 makes TeX not to print this message? Is this proper behavior?

Is it possible to set shape border rotate to a new default for a particular shape? For example, say I want to define a shape (which I'll call trapezoid in the MWE) that is essentially a trapezium but it is rotated by 180° by default. For example, \documentclass{standalone} \usepackage{tikz} \usetikzlibrary{shapes.geometric} \pgfdeclareshape{trapezoid}{% \nodeparts{text}% \inheritsavedanchors[from=trapezium]% \inheritbackgroundpath[from=trapezium]% \inheritanchorborder[from=trapezium]% \inheritanchor[from=trapezium]{text}% \inheritanchor[from=trapezium]{center}% \inheritanchor[from=trapezium]{north}% \inheritanchor[from=trapezium]{south}% \inheritanchor[from=trapezium]{east}% \inheritanchor[from=trapezium]{west}% \inheritanchor[from=trapezium]{north west}% \inheritanchor[from=trapezium]{north east}% \inheritanchor[from=trapezium]{south west}% \inheritanchor[from=trapezium]{south east}% \behindbackgroundpath{% \pgfpathmoveto{\lowerleftpoint}% \pgfpathlineto{\upperrightpoint}% }% }% \begin{document} \begin{tikzpicture} \node [draw,trapezium,minimum size=1cm] {}; \node [draw=blue,trapezoid,minimum size=1cm,name=s] at (0,-1.25) {}; \node [draw=orange,trapezoid,minimum size=1cm,shape border rotate=180] at (0,-2.5) {}; % \foreach \anchor/\placement/\color in {north/above/orange,south/below/teal, % east/right/red,west/left/green,50/above/violet} % \draw [color=\color,shift=(s.\anchor)] plot [mark=x] coordinates {(0,0)}; \end{tikzpicture} \end{document} but both the blue and the orange shapes should be the same. Alternatively, the blue one could be narrow-end-on-top, and the orange one rotates 180° more and looks like the black one. Options I have considered: Define a new shape and a new set of keys to go with it that are very similar to trapezium except upside-down (this is the worst option) Define trapezoid as a style that calls another shape (say, decorated trapezium or some such) whose only real purpose is to set another default value of shape border rotate Create an anchor that reads another key (say, trapezoid rotate) that determines what the user wants the new angle to be, then sets shape border rotate to something based on that. I am hoping there is another way, something like issuing \changepgfinitialvalue inside the shape definition so that the initial value changes for that shape (and only that shape). Is there? Clarification: what I want is a shape (I used trapezium here, but it could be something else) that looks similar to an existing one, but has extra things drawn on it, an appendage of some sort, etc., but the base shape is rotated with respect to the original. If there is a way to do this so that the user who calls, say, shape=trapezoid instead of just trapezoid without reverting the orientation, that would be my preference. In other words, inherit everything from a shape, build on it with \beforebackgroundpath, \foregroundpath, and such, and change the default orientation.

My goal is to achieve this: Best that a can do now is: \begin{tabular}{c c c c c} &\Text{Calça Azul} & \text{Calça Preta} & \text{Sapato Azul} & \text{Sapato Preto} \\ \text{Camisa branca} & & & & \\ \text{Camisa vermelha} & & & & \end{tabular} How to get something more close to the goal?

I am preparing some physics exercises about pressure, and I would like to illustrate a rectangular box that can be placed on each of its three different faces. In this way, the same box would have three different base areas, while its dimensions remain unchanged. For example, my box has dimensions: 23 cm, 24 cm, 46 cm I would like to create the three possible orientations of the box with TikZ, so that in each drawing a different face is touching the ground. At the moment, I have this code for one orientation: \documentclass{article} \usepackage[margin=0.5in]{geometry} \usepackage{tikz} \begin{document} \begin{center} \begin{tikzpicture}[x=0.027cm,y=-0.027cm,line width=0.35pt,draw=black!75] \draw (77,123)--(77,199)--(146,231)--(281,163)--(281,110); \draw (146,156)--(146,231); \draw (212,55)--(212,122); \draw (77,123)--(60,84)--(126,117)--(146,156)--cycle; \draw (77,123)--(51,96)--(186,27)--(212,55)--(109,109); \draw (212,55)--(232,16)--(301,48)--(281,87)--cycle; \draw (146,156)--(281,87)--(319,91)--(184,160)--cycle; \draw[<->] (66,126)--(66,198); \draw[<->] (72,210)--(141,242); \draw[<->] (151,242)--(286,173); \node[rotate=-90,inner sep=0pt,font=\small] at (57,160) {23 cm}; \node[rotate=-25,inner sep=0pt,font=\small] at (101,233) {24 cm}; \node[rotate=27,inner sep=0pt,font=\small] at (227,213) {46 cm}; \end{tikzpicture} \end{center} \end{document} Is there a relatively simple way to modify this code (or to define a reusable TikZ command) so that I can obtain the other two orientations of the same box, with the 23 cm, 24 cm, and 46 cm dimensions exchanged accordingly? Ideally, I would like to be able to write something like \boxorientation{23}{24}{46} and obtain the corresponding drawing, or otherwise have a convenient way to generate the three possible orientations. The purpose is to use the drawings in physics exercises about pressure, where the students have to calculate the pressure exerted by the box when it rests on each of its three possible bases.

In their 1962 paper "The Braid Groups," Fox and Neuwirth use a notation similar to \veebar to describe one point being directly on top of another in the plane, as shown below. I was wondering what the best way to reproduce this in LaTeX would be. One option would be \stackrel\vee=, but it doesn't have quite the right spacing. (I wonder how they did it. Obviously this predates LaTeX, but I don't know enough about the way mathematics papers were typeset in the 60s. By the way, the terms "abscissa and ordinate" refer to the x- and y-coordinate respectively.)

Beginner Ipe user here! Every time I accidentally draw things in the wrong order my only method has been to redraw everything (eg. writing labels first and then drawing the filled nodes ultimately hiding the text labels as seen in the attached image). I was wondering if there was a way to make use of layers somehow to make this process simpler. I can see that you can toggle visibility but I could not see a way to change the pre-existing elements' stacking order. Are layers the way to go about it or is there some other tool I should be using for this? Thanks in advance & happy to add more clarification if necessary!

First, consider the code which produces the colored star: \documentclass{article} \usepackage{tikz} \usetikzlibrary{shapes.geometric} \begin{document} \begin{center} \begin{tikzpicture} \node[ shape=star, star points=5, star point ratio=2.5, minimum size=0.8cm, fill=red, draw=red ] {}; \end{tikzpicture} \end{center} \end{document} which produces: Now, consider the code which produces the tikz circle of asterisks: \documentclass{book} \usepackage{tikz} \usetikzlibrary{shapes.geometric} % Required for the star shape \usetikzlibrary{calc} \definecolor{oldgloryblue}{RGB}{10,49,97} \begin{document} \thispagestyle{empty} \begin{center} \begin{tikzpicture} \foreach \k in {0,30,...,360} \node at ($(0,0)+(\k:2)$){*}; \end{tikzpicture} \end{center} \end{document} and which produces However, when I replace the asterisk by `shape=star, star points=5, star point ratio=2.5, minimum size=0.8cm, fill=red, draw=red` I encounter many problems. QUESTION: How may I produce the circular image of `red stars' instead of the circular images of asterisks? Thank you.

I have the following set up for my different elements \documentclass{report} \usepackage[theorems]{tcolorbox} % for producing coloured boxes \tcbuselibrary{theorems} % theorems with tcolorbox \tcbuselibrary{breakable} \tcbuselibrary{skins} \definecolor{myblack}{RGB}{0, 0, 0} \definecolor{mywhite}{RGB}{255, 255, 255} \definecolor{mylightblue}{RGB}{102, 178, 255} \definecolor{mymidblue}{RGB}{0, 128, 255} \definecolor{mydarkblue}{RGB}{0, 0, 204} \definecolor{mylightgreen}{RGB}{128, 255, 0} \definecolor{mymidgreen}{RGB}{102, 204, 0} \definecolor{mydarkgreen}{RGB}{76, 153, 0} \definecolor{mylightred}{RGB}{255, 153, 153} \definecolor{mymidred}{RGB}{255, 102, 102} \definecolor{mydarkred}{RGB}{255, 51, 51} \definecolor{myyellow}{RGB}{255, 255, 0} \definecolor{myorange}{RGB}{255, 204, 153} \definecolor{mydarkpink}{RGB}{255, 102, 178} \definecolor{mymidpink}{RGB}{255, 153, 204} \definecolor{mylightpink}{RGB}{255, 204, 229} \tcbset{commonstyle/.style={ breakable, enhanced, coltitle=myblack, colupper=myblack, toprule=1mm, bottomrule=1mm, leftrule=1mm, rightrule=1mm }, defstyle/.style={ commonstyle, colframe=mydarkblue, colback=mylightblue, colbacktitle=mymidblue}, theostyle/.style={ commonstyle, colframe=mydarkred, colback=mylightred, colbacktitle=mymidred}, exastyle/.style={ commonstyle, colframe=mydarkgreen, colback=mylightgreen, colbacktitle=mymidgreen}, remstyle/.style={ commonstyle, colframe=mydarkpink, colback=mylightpink, colbacktitle=mymidpink} } \newtcbtheorem[number within=section, Crefname={theorem}{theorems}]{theorem}{Theorem}{theostyle}{theo} \newtcbtheorem[use counter from=theorem, Crefname={definition}{definitions}]{definition}{Definition}{defstyle}{def} \newtcbtheorem[use counter from=theorem, Crefname={example}{examples}]{example}{Example}{exastyle}{exa} \newtcbtheorem[use counter from=theorem, Crefname={remark}{remarks}]{remark}{Remark}{remstyle}{rem} \newtcbtheorem[use counter from=theorem, Crefname={corollary}{corollaries}]{corollary}{Corollary}{theostyle}{cor} \newtcbtheorem[use counter from=theorem, Crefname={lemma}{lemmas}]{lemma}{Lemma}{theostyle}{lem} \newtcbtheorem[use counter from=theorem, Crefname={proposition}{propositions}]{proposition}{Proposition}{theostyle}{prop} \newtcbtheorem[use counter from=theorem, Crefname={algorithm}{algorithms}]{algorithm}{Algorithm}{theostyle}{alg} \tcolorboxenvironment{proof}{commonstyle,colframe=mydarkred, colback=myorange, colbacktitle=mymidred} \begin{document} \chapter{Chapter 1} \section{Section 1.1} \begin{theorem}{Title}{1.1.1} ... \end{theorem} \begin{lemma}{Title}{1.1.2} ... \end{lemma} \begin{sublemma}{Title}{1.1.2a} ... \end{sublemma} \begin{corollary}{Title}{1.1.3} ... \end{corollary} \end{document} I want to understand how to define the sublemma tcbtheorem with an \alph counter so that the numbering reads Lemma 1.1.1a, Lemma 1.1.1b, ... Following Theorem/Lemma/... 1.1.1 and so on, resetting every time the original theorem counter increases. I've tried everything under the sun, but I couldn't make it work. I tried setting up a global counter for the theorems, but this kept on breaking with how tcolorbox overwrites the counter definition, etc. Does anyone know how to do it?

I use the tasks environment from the tasks package to make exercises and solutions. If the solutions are long, there is a lot of free space since it seems that individual \tasks do not allow page breaks inside of them. Instead. the \task will start on the next page. I could just use the enumerate environment for these solutions, but some solutions are rather short, so I use the task envornment for these, to have multiple tasks side by side, going from left to right and not from top to bottom first. To have my code consistent, I would like to have the longer solutions in the task environment also. Can \tasks somehow be set up such that they can span over multiple pages? MWE: \documentclass{scrartcl} \usepackage{tasks} \usepackage{lipsum} \begin{document} \begin{tasks} \task \lipsum[1-2] \task \lipsum[1-3] \end{tasks} \end{document}

I am a new Linux Ubuntu user that trying to learn that for my major but I do not know when I add Persian keyboard, It worked fine but when I try to write semi-space (usually write with ctrl + shift + 2 or shift + space) doesn't work at all like it does not know it at all. please If you know this problems solution leave an answer blow tnx

I've been working on a fairly long document which uses quite a few subfiles. It had been compiling fine, but today I added some figures into one of the subfiles. Since then, when I try to compile the document it is like TeXworks gets stuck. The console output shows chapter headings and page numbers as I would expect, and seems to get to the end of the document. Then it says "*", and nothing else happens. It doesn't show any errors. I have also realised that it does create a PDF file in the right folder, but when I try to open that it seems to get stuck on loading (there's a grey background and a full loading bar, but no pages). I'm using MikTeX and TeXworks, set to compile using pdfLaTeX. Since there's no error message it's hard to know what's causing this. Does anyone know what's happening?

There must be something wrong with the following code as it gives no errors but the wrong results. Changing the \getpagerefnumber to \getabspagerefnumber causes a huge number of errors. Please can you correct the syntax. I have deliberately included quite a few named pages in an attempt to trace what is going on. \documentclass{book} \usepackage[a6paper]{geometry} % to get smaller pictures \usepackage{graphicx} \usepackage{xparse} \usepackage{zref-abspage} % Required for \getabspagerefnumber \usepackage{lastpage} \usepackage{refcount} \usepackage{parskip} \ExplSyntaxOn \NewDocumentCommand{\choosebackgrounds}{mmmmmmmmm}% 9 [m]s { \bool_case:n {% {\int_compare_p:n {\value{page}=\getpagerefnumber{named_page_one}}} {\putbackground{#1} 111}% named {\int_compare_p:n {\value{page}=\getpagerefnumber{named_page_two}}} {\putbackground{#2} 222}% named {\int_compare_p:n {\value{page}=\getpagerefnumber{named_page_three}}} {\putbackground{#3}}% named % {\int_compare_p:n {\value{page}=\getpagerefnumber{title_page_one}}} {\putbackground{#5}}% title {\int_compare_p:n {\value{page}=\getpagerefnumber{title_page_two}}} {\putbackground{#6}}% title % {\int_compare_p:n {\value{page}=\getpagerefnumber{named_page_four}}} {\putbackground{#4}}% named % {\int_compare_p:n {\value{page}=\getpagerefnumber{LastPage}}} {\putbackground{#7}}% named % {\int_if_odd_p:n {\value{page}}} {\putbackground{#8}}% others {\int_if_even_p:n {\value{page}}} {\putbackground{#9}}% others } } \ExplSyntaxOff \NewDocumentCommand{\putbackground}{m}{\put(30mm,-90mm){#1}} \AddToHook{shipout/background}{% % \choosebackgrounds% on basis that first condition that is satisfied wins {\Huge named page one}% 1 {\Huge named page two}% 2 {\Huge named page three}% 3 {\Huge named page four}% 4 {\Huge title page one}% 5 {\Huge title page two}% 6 {\Huge LAST PAGE}% 7 {\Huge un-named ODD}% 8 {\Huge un-named EVEN}% 9 } \begin{document} \pagenumbering{arabic}% 1, 2, ... \setcounter{page}{1} \label{page:named_page_one}% Front cover: named page one Generated page No. \thepage % % --------------------------------------------------------------------- % \clearpage \label{page:named_page_two}% Inside front cover: named page two Generated page No. \thepage % ------------------------- Facing inside front cover ------------------ % \clearpage \label{page:named_page_three}% Facing inside front cover: named page three Generated page No. \thepage % ------------------------- Facing inside front cover ------------------ % \clearpage No label reference Just before title - a LEFT-HAND or EVEN page Generated page No. \thepage % ------------------------------ First title page --------------------------------- % {\centering \begin{titlepage}% first page of title- becomes revised page No 1 \begin{center} \label{page:title_page_one}% Title page: ONE Generated page No. \thepage Absolute page No: 4 % ------------------------------------ Second title page --------------------------- % \clearpage \label{page:title_page_two} Title page: TWO Generated page No. \thepage Absolute page No: 5 \end{center} \end{titlepage} } % --------------------------------------- Contents ---------------------------------- % \clearpage \label{page:named_page_four} The start of contents Generated page No. \thepage Absolute page No: 6 % ------------------------------------------------------------------------------------- % \clearpage Preface to this volume Generated page No. \thepage Absolute page No: 7 % ------------------------------------------------------------------------------------- % \mainmatter Some introductory content after mainmatter Generated page No. \thepage Absolute page No: 8 \vspace{6pt} First page of book proper. % -------------------------------------------------------------------------------------- % \clearpage% Another page of the book. Generated page No. \thepage % -------------------------------------------------------------------------------------- % \clearpage% Another page of the book. Generated page No. \thepage % -------------------------------------------------------------------------------------- % \clearpage% Another page of the book. Generated page No. \thepage % -------------------------------------------------------------------------------------- % \clearpage% Penultimate page Generated page No. \thepage % --------------------------------------------------------------------------------------- % \clearpage This is the rear cover% no background required but made visible here \label{page:LastPage} Generated page No. \thepage Absolute page No: 13 ? \end{document}

So I was playing around with latex2sympy2 - a Python library to convert LaTeX to SymPy objects. I tried to run this code: from latex2sympy2 import latex2sympy latex_code = r"\begin{bmatrix} a & b \\ c & d \end{bmatrix}" print(latex2sympy(latex_code)) and ran into this: Exception: I expected something else here \begin{bmatrix} a & b \\ c & d \end{bmatrix} ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~^ It took me a while to figure out that the problem was d. I checked every letter instead of d and it worked correctly, run this so that you can see that yourself: from latex2sympy2 import latex2sympy for i in range(65, 91): if i == 69: continue # every letter except E print(chr(i), latex2sympy(r"\begin{bmatrix} 1 & 2 \\ 3 & %s \end{bmatrix}" % chr(i))) for i in range(97, 123): if i == 100: continue # every letter except d print(chr(i), latex2sympy(r"\begin{bmatrix} 1 & 2 \\ 3 & %s \end{bmatrix}" % chr(i))) # d try: print(latex2sympy(r"\begin{bmatrix} 1 & 2 \\ 3 & d \end{bmatrix}")) except Exception as e: print(f"{type(e).__name__}: {str(e)}") # E try: print(latex2sympy(r"\begin{bmatrix} 1 & 2 \\ 3 & E \end{bmatrix}")) except Exception as e: print(f"{type(e).__name__}: {str(e)}") I'm not good at LaTeX, though, please don't blame me. How do I fix that? I have no clues.

I'm trying to arrange a collection of nodes using \graph, which will be used to define a series of spath3 knot strands. However, the default cartesian placement strategy doesn't work very well for my purposes, as node chains that I intend to "tee off" from other nodes are placed at a constant width. It's possible to get what I want with the following code, but it's obviously rather fragile: \documentclass{article} \usepackage{tikz} \usetikzlibrary{graphs} \begin{document} \begin{tikzpicture} \graph[nodes={draw, as={}}]{ a -> b -> c, {[placement/width=1, placement/depth=1, grow down] b -> d -> f -> g}, {[placement/width=2, placement/depth=2, grow right] f -> p}, }; \end{tikzpicture} \end{document} How can I achieve the same effect by specifying the node rather than the width and depth?

There is a highly popular post from 2014 showcasing Nice scientific pictures show off but a lot has changed with LaTeX over the last 12 years. What is your best science picture to show off now that wasn't possible 12 years ago? Constraints for each answer: The Picture & Code: Show off a beautiful scientific illustration that utilizes features, packages, or engine capabilities (e.g., LuaLaTeX memory handling, modern pgfplots limits, Luametafun) that remove barriers which routinely stopped typical users from doing this 12 years ago (such as hard memory crashes, lack of default ecosystem support, or prohibitive manual workarounds). The Evolution: You must explicitly explain what technological progress or package developmentover the last decade made this picture possible today. AI usage is allowed, but must be acknowledged per community guidelines.

I am writing my Mid-Sem Report to be submitted to my University and they have fixed a particular style of document to be used. I am attaching my code which I am writing. \documentclass[a4paper,12pt]{article} \usepackage{amsmath,amssymb,graphicx,tikz,amsthm} \usetikzlibrary{arrows,matrix} \usepackage[utf8]{inputenc} \usepackage{titlesec} \titlelabel{\thetitle.\quad} \usepackage{setspace} \usepackage{indentfirst} \newtheorem{theorem}{Theorem}[section] \newtheorem{lemma}[theorem]{Lemma} \newtheorem{Proposition}[theorem]{Proposition} \newtheorem{definition}{Definition}[section] \newtheorem{corollary}[theorem]{Corollary} \newtheorem{Con}[theorem]{Conjecture} \newtheorem{Prob}[theorem]{Problem} \newtheorem{Fact}[theorem]{Fact} \newtheorem{Remark}[theorem]{Remark} \newtheorem{Def}[theorem]{Definition} \newtheorem{Example}[theorem]{Example} \newtheorem{Question}[theorem]{Question} \newtheorem{Problem}[theorem]{Problem} %\newtheorem{proof}[theorem]{Proof} \renewcommand{\baselinestretch}{1.1} \usepackage{pifont,txfonts,geometry,hyperref} \newcommand{\bcomma}{,\allowbreak} \newcommand{\R}{\mathbb{R}} \newcommand{\ds}{\displaystyle} %%%%%%%%% Set page size and margins here %%%%%%%%%%%%%%% \setlength{\topmargin}{-0.5in} \setlength{\topskip}{0.275in} % between header and text \setlength{\textheight}{9in} % height of main text \setlength{\textwidth}{6.25in} % width of text \setlength{\oddsidemargin}{0.1in} % odd page left margin \setlength{\evensidemargin}{0.1in} % even page left margin %\theoremstyle{definition} %\newtheorem{definition}{Definition} \renewcommand{\theenumi}{\rm(\alph{enumi})} \renewcommand{\labelenumi}{\theenumi} %CAN REFER ITEMS WITH THE ABOVE TWO LINES \renewcommand{\theenumii}{\rm(\roman{enumii})} \renewcommand{\labelenumii}{\theenumii} \begin{document} %%%%%%%%%%%%%%%%%%%%%% Title page %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% \thispagestyle{empty} \begin{center} \LARGE\textbf{Midterm Report} \end{center} \vspace{1cm} \noindent \textbf{Name: Arghya Das} \vspace{3mm}\\ \noindent \textbf{Roll No: MSI22022} \vspace{3mm}\\ \noindent \textbf{Name of the Supervisor: Prof. Milan Nath} \vspace{2em} \hrule \vspace{1em} \section*{Title: A study on algebraic connectivity and spectral integral variations of graphs.} \section*{Abstract:} Write your abstract within 200 words. \section{Introduction} Throughout this document, all graphs are assumed to be finite and simple, unless otherwise mentioned. Let $G$ be a graph with vertex set $V(G)=\{1,2,\dots,n\}$ and edge set $E(G)=\{e_1, e_2,\dots,e_m\}$. We use the notation $i\sim j$ to mean that the vertices $i$ and $j$ are adjacent. The\textbf{\textit{ adjacency matrix}} of $G$, denoted by $A(G)$, is defined as $A(G)=[a_{ij}]_{n\times n}$, where \\ \\ \indent \indent \indent \indent \indent \indent \indent \indent \indent \indent $a_{ij}=\begin{cases} 1, & \text{if } i \sim j\\ 0, & \text{otherwise.} \end{cases}$ \\ \\ The \textit{\textbf{Laplacian matrix}} of $G$, denoted by $L(G)$, is defined as $L(G) := D(G)-A(G)$, where $D(G)$ is the diagonal matrix with degrees of the vertices of $G$ as diagonal entries. It is well-known that $L(G)$ is symmetric and positive semidefiniite and rank of $L(G)$ is $n-k$ where $k=k(G)$ is the number of connected components in $G$. Since $L(G)$ is symmetric and positive semidefinite so all the eigenvalues of $L(G)$ are real and non-negative. Moreover, $0$ is the smallest eigenvalue of $L(G)$ as for $v=(1 \ \ 1\ \dots \ 1)^T \in \R^n$, \ \ $L(G)v=0v$. \par Suppose that $0=\lambda_1\leq \lambda_2 \leq \cdots$ \section{Preliminaries} \section{Work done} Maximum 03 pages \section{Further study} Maximum 01 page \begin{thebibliography}{33} \bibitem{F1} Castelaz, A.~Commutivity degree of finite groups.~Thesis,~Department of Mathematics,~ Wake Forest University,~North Carolina,~5-8, 2010. \bibitem{C1} Cerf, V.,~Fernandez, E.,~Gostelow, K.,~and~Volausky, S.~ Formal control and low properties of a model of computation. Report ENG 7178, Computer Science Department, University of California, Los Angles, CA,~pp. 81, 1997. \bibitem{E2} Dutta, P.~and~Nath, R.K.~Autocommuting probability of a finite group.~{\em Communications in Algebra},~46(3):961-969, 2018. \end{thebibliography} \end{document} However I didn't like the lambda produced here and I want it changed while rest of the fonts and symbols of the document remain untouched (as I can't change the fonts and symbols very much). I want this lambda to use specifically: I have gone through many Tex exchange answers and AI answers but none of them work. Some of these are: How to make italic greek letter \lambda \usepackage{amsmath,amssymb} \usepackage{unicode-math} \setmathfont{Latin Modern Math} \setmathfont[range=\lambda]{TeX Gyre Termes Math} \DeclareSymbolFont{newtxletters}{OML}{ntxmi}{m}{it} \DeclareMathSymbol{\newtxlambda}{\mathord}{newtxletters}{"15} But either they throw an error or produces the same lambda as in produced before. So any help would be appreciated.

I'm writing a lemma with italics font style where I need enumeration in lowercase Roman numerals. I tried different ways and the best I could do is to use the package enumerate like this: \usepackage{enumerate} \begin{document} \begin{lemma} For any graph G, \begin{enumerate}[(i)] \item L(G) is symmetric. \item L(G) is positive semidefinite. \item etc. \end{enumerate} \end{lemma} \end{document} But the problem I'm facing is the tilts of parentheses are more than that I like. Actually I want like this: Any help would be appreciated.

How to modify this macro to ensure the same spacing between the first mark and the opening delimiter, and between the last mark and the closing delimiter ? \documentclass[border=5mm]{standalone} \usepackage{luatex85} \usepackage{luamplib} \begin{document} \mplibtextextlabel{enable} \begin{mplibcode} beginfig(1); vardef interval(expr a, b, c, d) = interim ahangle := 30; numeric u; u = 0.5cm; path l; l = (0,0) -- (8*u,0); drawarrow l; for x = (a + 0.2) step 0.2 until (b - 0.2): draw (3 down -- 3 up rotated -45) shifted (x * u, 0); endfor label(c, (2*u,0)); label(d, (6*u,0)); label.bot("$a$", (a*u,-5)); label.bot("$b$", (b*u,-5)); label.bot("$-\infty$", (0,-5)); label.bot("$+\infty$", (8*u,-5)); enddef; interval(2, 6, "[", "]"); endfig; \end{mplibcode} \end{document}