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I used to glue the dashes to the parenthesis like shown below with pdflatex. \documentclass{scrartcl} \usepackage{kpfonts-otf} \usepackage[babelshorthands=true]{polyglossia} \setdefaultlanguage{german} \begin{document} This is a "~- not necessarily smart~-- text. \end{document} Running with lualatex yields this result (edited): I cannot find a solution in the fine polyglossia manual. How to do it correctly? Edit: The result should like this: with the important aspect, that both dashes are glued to the parenthesis when it comes to a line break.

ChatGPT told me to use \Corresponds to get the "entspricht" symbol with kpfonts-otf, but what a surprise: It is not known to this font. What do I have to take for this symbol. \documentclass{scrartcl} \usepackage{unicode-math} \removenolimits{\int} \setsansfont{KpSans} \setmainfont{KpRoman} \setmathfont{KpMath-Regular} %\DeclareMathOperator{\entspricht}{\mathrel{\Corresponds}} \begin{document} %\begin{equation} %16 \entspricht 2^4 %\end{equation} \begin{equation} 16 \wedgeq 2^4 \end{equation} \begin{equation} 16 \Corresponds 2^4 \end{equation} \end{document} \endinput The last lines of the log file looks like this Missing character: There is no ≙ (U+2259) in font [KpMath-Regular.otf]:mode=ba se;script=math;language=dflt;mathfontdimen=xetex;! ! Undefined control sequence. l.19 16 \Corresponds 2^4 ? BTW: In former times (up to yesterday when I changed to lualatex) I used % \DeclareMathOperator{\entspricht}{\mathrel{\hat{=}}} with kpfonts and was quite happy with it. With kpfonts-otf the result is more than ugly:

Note that the aim of this is to add a new operator to the l3fp module of the LaTeX3 kernel and therefore internal functions and reserved prefixes are used throughout the code. Please use this code with the due caution. I try to add a function and operator to the l3fp module that extracts an item from a tuple. I started with defining a public function and underlying internal functions that leave the relevant item of a tuple in the internal fp representation in the input stream. Placed into \fp_eval:n, this results in the intended output (one could also imagine adding \fp_to_decimal:n to this, so it returns the relevant number directly): \documentclass{article} \begin{document} \ExplSyntaxOn \makeatletter % public function \cs_new:Npn \fp_tuple_item:nn #1#2 { \exp_args:Nee \__fp_tuple_item:nn { \__fp_parse:n {#2} } { \__fp_parse:n {#1} } } % internal functions \cs_new:Npn \__fp_tuple_item:nn #1#2 { \__fp_tuple_item_aux:ww #1#2 } \cs_new:Npn \__fp_tuple_item_aux:ww #1 \__fp_sep: { \__fp_tuple_item_select_aux:nw { \__fp_to_int:w #1 \__fp_sep: } } \cs_new:Npn \__fp_tuple_item_select_aux:nw #1 \s__fp_tuple \__fp_tuple_chk:w #2 \__fp_sep: { \int_compare:nNnTF {#1} < 0 { \__fp_tuple_item_select_aux:nw { \__fp_int_eval:w \__fp_array_count:n {#2} + 1 + #1 \__fp_int_eval_end: } \s__fp_tuple \__fp_tuple_chk:w {#2} \__fp_sep: } { \__fp_tuple_item_select_auxi:nw {#1} #2 \s__fp_stop } } \cs_new:Npn \__fp_tuple_item_select_auxi:nw #1 { \int_compare:nNnTF {#1} = 1 { \__fp_tuple_item_select_auxii:w } { \__fp_tuple_item_select_auxiii:nw {#1} } } \cs_new:Npn \__fp_tuple_item_select_auxii:w #1 \__fp_sep: #2 \s__fp_stop { #1 \__fp_sep: } \cs_new:Npn \__fp_tuple_item_select_auxiii:nw #1#2 \__fp_sep: { \__fp_tuple_item_select_auxi:nw { \__fp_int_eval:w #1 - 1 \__fp_int_eval_end: } } \makeatother \fp_eval:n { \fp_tuple_item:nn { ( 1 , 2 ) } { 1 } } % returns 1 \fp_eval:n { \fp_tuple_item:nn { 2 * ( 1 , 2 ) } { 2 } } % returns 4 \fp_eval:n { \fp_tuple_item:nn { ( 1 , 2 , 3 ) } { -1 } } % returns 3 \ExplSyntaxOff \end{document} So far, so good, but now I want to define a new function operator that can be used in an fp expression. The syntax should be item(n,t) where n is the index of the item and t is the tuple. I looked at the implementation of various other functions in the l3fp module such as round() or rand() and came up with the following relatively straight-forward defintion: \cs_new:Npn \__fp_parse_word_item:N { \__fp_parse_function:NNN \__fp_item_o:Nw ? } \cs_new:Npn \__fp_item_o:Nw ? #1 @ { \exp_after:wN \__fp_item_o:w #1 @ } \cs_new:Npn \__fp_item_o:w { \exp_after:wN \__fp_tuple_item_aux:ww } However, this results in an error as eventually \__fp_parse_after:ww does not see the expected tokens. I checked the expansion process up to this point using the unravel package and I can see that I get something along the following lines (<fp> being the relevant internal fp representation): \__fp_parse_after:ww \s__fp <fp> \__fp_sep: @ \exp:w \exp_end_continue_f:w \__fp_parse_infix_end:N \c__fp_prec_end_int \s__fp_expr_stop \exp_end: Other functions return something similar but without \c__fp_prec_end_int which is exactly what \fp__parse_after:ww wants whose argument defintion is #1 @ \__fp_parse_infix_end:N \s__fp_expr_stop #2. Now, I am lost at this point. I can see that my implementation yields the correct fp representation, but I am unable to find the reason why \c__fp_prec_end_int (along with \exp:w \exp_end_continue_f:w) is left in the stream and what I should do to remove this. Full MWE: \documentclass{article} \begin{document} \ExplSyntaxOn \makeatletter % public function \cs_new:Npn \fp_tuple_item:nn #1#2 { \exp_args:Nee \__fp_tuple_item:nn { \__fp_parse:n {#2} } { \__fp_parse:n {#1} } } % internal functions \cs_new:Npn \__fp_tuple_item:nn #1#2 { \__fp_tuple_item_aux:ww #1#2 } \cs_new:Npn \__fp_tuple_item_aux:ww #1 \__fp_sep: { \__fp_tuple_item_select_aux:nw { \__fp_to_int:w #1 \__fp_sep: } } \cs_new:Npn \__fp_tuple_item_select_aux:nw #1 \s__fp_tuple \__fp_tuple_chk:w #2 \__fp_sep: { \int_compare:nNnTF {#1} < 0 { \__fp_tuple_item_select_aux:nw { \__fp_int_eval:w \__fp_array_count:n {#2} + 1 + #1 \__fp_int_eval_end: } \s__fp_tuple \__fp_tuple_chk:w {#2} \__fp_sep: } { \__fp_tuple_item_select_auxi:nw {#1} #2 \s__fp_stop } } \cs_new:Npn \__fp_tuple_item_select_auxi:nw #1 { \int_compare:nNnTF {#1} = 1 { \__fp_tuple_item_select_auxii:w } { \__fp_tuple_item_select_auxiii:nw {#1} } } \cs_new:Npn \__fp_tuple_item_select_auxii:w #1 \__fp_sep: #2 \s__fp_stop { #1 \__fp_sep: } \cs_new:Npn \__fp_tuple_item_select_auxiii:nw #1#2 \__fp_sep: { \__fp_tuple_item_select_auxi:nw { \__fp_int_eval:w #1 - 1 \__fp_int_eval_end: } } % operator defintion \cs_new:Npn \__fp_parse_word_item:N { \__fp_parse_function:NNN \__fp_item_o:Nw ? } \cs_new:Npn \__fp_item_o:Nw ? #1 @ { \exp_after:wN \__fp_item_o:w #1 @ } \cs_new:Npn \__fp_item_o:w { \exp_after:wN \__fp_tuple_item_aux:ww } \makeatother \fp_eval:n { item ( 1 , ( 1 , 2 ) ) } \ExplSyntaxOff \end{document}

After installing TexLive2026, whenever I compile Kaobook in TexStudio, I keep getting an error similar to the one in the attachment. I’m new to LaTeX. Where can I download the complete, modified Kaobook file? I’m trying to compile using xelatex with Korean text by using \usepackage{kotex}. How should I configure the settings or the cls file? Is there anyone who can help me?

I am typesetting an Arabic document using XeLaTeX and the polyglossia package. I am trying to build a table using the tabularray package. The Problem: Whenever I apply a background color to a specific row using the bg key (e.g., row{1} = {bg=blue!20}), the Arabic text inside that row completely disappears in the output PDF. The text in the other rows (which do not have a background color) renders perfectly fine. It seems like a layering or grouping issue where the bidi package (loaded by polyglossia) conflicts with tabularray's drawing engine, causing the colored box to either cover the text or push the RTL text out of bounds. I have already tried: Removing font=\bfseries from the row settings. Using manual \textbf{} inside the cells. Wrapping the text in \mbox{}. Using \SetCell{bg=blue!20} instead of row{1}. None of these solved the issue; as long as the background color is present, the text vanishes. Minimum Working Example (MWE): \documentclass{article} \usepackage{xcolor} \usepackage{tabularray} % RTL Setup \usepackage{polyglossia} \setmainlanguage{arabic} \setmainfont{Amiri} % Standard Arabic font for testing \begin{document} \begin{center} \begin{longtblr}{ colspec = {|X[c,m,1.6]|X[c,m,1.4]|X[c,m,1.4]|}, hlines, vlines, row{1} = {bg=blue!20, rowsep=5pt}, % The text in this row disappears rowsep=8pt } \textbf{النهاية} & \textbf{التفسير الهندسي} & \textbf{التمثيل البياني} \\ Text appears here & Text appears here & Text appears here \\ \end{longtblr} \end{center} \end{document}

I'm running an antique MacOS (mojave) with MacTeX 2022 installed. The MWE below compiles successfully with XeLaTeX, but with LuaLaTeX, I get the following message: kpathsea: Running mktexpk --mfmode / --bdpi 600 --mag 1+0/600 --dpi 600 WebOMintsGD mktexpk: don't know how to create bitmap font for WebOMintsGD. mktexpk: perhaps WebOMintsGD is missing from the map file. kpathsea: Appending font creation commands to missfont.log. ! error: (file WebOMintsGD) (type 3): font WebOMintsGD at 600 not found ! ==> Fatal error occurred, no output PDF file produced! What does LuaLaTeX want me to do to make this work? %%%%%%%%%%%%%%%%%%%%%%%% \documentclass{memoir} \usepackage{fontspec} \newfontfamily\wb{WebOMints GD} \pagestyle{empty} \begin{document} \wb ABCDEFGHIJKLMNOPQRSTUVWXYZ abcdefghijklmnopqrstuvwxyz \end{document}

I'm citing a popular online dictionary: \documentclass{article} \usepackage[natbibapa]{apacite} \begin{filecontents}{\jobname.bib} @inbook {MWOganesson, author = {Merriam-Webster}, title = {Oganesson}, book = {Merriam-Webster.com dictionary}, url = {https://www.merriam-webster.com/dictionary/oganesson} } \end{filecontents} \begin{document} The word ``oganesson'' is stressed on the third syllable \citep{MWOganesson}. \bibliographystyle{apacite} \bibliography{\jobname} \end{document} In the output, the title is printed as "Oganesson.." with two periods. Is a workaround known?

I am writing an Arabic document using XeLaTeX and the polyglossia package for RTL (Right-to-Left) typesetting. I have defined a custom tcolorbox environment for exercises, which uses the breakable library. I am placing these boxes inside a multicols*{2} environment. However, the output produces extremely large, unwanted vertical spaces between the boxes, and the boxes do not break properly across the columns as expected. Due to my workflow, I must use the XeLaTeX engine and cannot switch to LuaLaTeX or pdfLaTeX. Here is the code that reproduces the issue: \documentclass[10pt,a4paper]{report} \usepackage{amsfonts,amsmath,amssymb,amsthm,enumitem,fancybox,multicol,xcolor,multirow,rotating,float,graphicx,polynom,pifont,array} \usepackage[most]{tcolorbox} \usepackage{tikz,tkz-tab,pgfplots,tkz-euclide} \pgfplotsset{compat=1.11} \usetikzlibrary{shadows,shapes,calc} \usepackage[top=1.5cm, bottom=1.5cm, left=6mm, right=6mm]{geometry} \definecolor{caa}{cmyk}{.94,0.37,0,0.17} \definecolor{cab}{cmyk}{.07,0,0,0.49} \everymath{\displaystyle} \newtcolorbox[auto counter]{exo}{ enhanced jigsaw, breakable,blanker,coltitle=black,fonttitle=\bfseries\large, title={\shadowbox{{التمرين} {\thetcbcounter}}}} \setlength{\parindent}{0cm} \usepackage{polyglossia} % \setdefaultlanguage[calendar=gregorian,locale=algeria]{arabic} \setotherlanguage{french} \newfontfamily\arabicfont[Script=Arabic,Scale=1.2]{Amiri} \pagestyle{empty} \setlist[enumerate,1] { itemsep=-00.2cm, rightmargin=0.7cm, label=\fcolorbox{white}{gray!5}{\textcolor{black}{\arabic*)}} } \setlist[enumerate,2] { itemsep=-00.2cm, %rightmargin=0.7cm, label=\fcolorbox{white}{gray!5}{\textcolor{black}{\Alph*)}} } \begin{document} \begin{multicols*}{2} \columnseprule=1pt \columnsep=2mm %%%%%%%%%%%%%%%%%%%%%%%%%% % EXO 1 %%%%%%%%%%%%%%%%%%%%%%%%%%% \begin{exo}{} \begin{enumerate}[label=(\Roman*] \item نعتبر النقط $A(1;2)$،$B(3;3)$ و $C(1;-2)$ \begin{enumerate}[label=\arabic*)] \item أكتب المعادلة الديكارتية للدائرة $(D)$ التي مركزها $A$ ونصف قطرها $ 2 $ \item أكتب المعادلة الديكارتية للدائرة $(D')$ التي قطرها $\left[ BC \right]$ \item أكتب معادلة المستقيم $(\Delta )$ محور القطعة المستقيمة $\left[ AB \right]$ \end{enumerate} \item بين إن كانت المعادلات التالية هي معادلة لدائرة يطلب تعيين عناصرها المميزة: \begin{enumerate}[label=\arabic*)] \item ${{x}^{2}}+{{y}^{2}}+2x-6y+1=0$ \item ${{x}^{2}}+{{y}^{2}}+4x+2y+5=0$ \item ${{x}^{2}}+{{y}^{2}}-6x-4y+2=0$ \end{enumerate} \end{enumerate} \end{exo} %%%%%%%%%%%%%%%%%%%%%%%%%% % EXO 2 %%%%%%%%%%%%%%%%%%%%%%%%%%% \begin{exo}{} \begin{enumerate}[label=(\Roman*] \item نعتبر النقط $A(1;2)$،$B(3;3)$ و $C(1;-2)$ \begin{enumerate}[label=\arabic*)] \item أكتب المعادلة الديكارتية للدائرة $(D)$ التي مركزها $A$ ونصف قطرها $ 2 $ \item أكتب المعادلة الديكارتية للدائرة $(D')$ التي قطرها $\left[ BC \right]$ \item أكتب معادلة المستقيم $(\Delta )$ محور القطعة المستقيمة $\left[ AB \right]$ \end{enumerate} \item بين إن كانت المعادلات التالية هي معادلة لدائرة يطلب تعيين عناصرها المميزة: \begin{enumerate}[label=\arabic*)] \item ${{x}^{2}}+{{y}^{2}}+2x-6y+1=0$ \item ${{x}^{2}}+{{y}^{2}}+4x+2y+5=0$ \item ${{x}^{2}}+{{y}^{2}}-6x-4y+2=0$ \end{enumerate} \end{enumerate} \end{exo} %%%%%%%%%%%%%%%%%%%%%%%%%% % EXO 3 %%%%%%%%%%%%%%%%%%%%%%%%%%% \begin{exo}{} $ABC$ مثلث متقايس الأضلاع و النقطة $ {J} $ مرجح الجملة $\left\{ \left( B,4 \right),\left( c,-2 \right) \right\}$ معرفة بالعلاقة: $\overrightarrow{AI}=\frac{4}{3}\overrightarrow{AB}$ \begin{enumerate} \item أنقل الشكل كما هو ثم أنشىء النقطتين $ {I} $ و $ {J} $ \item أثبت أن النقطة $ {I} $ هي مرجح النقطتين $ {A} $ و $ {B} $ مرفقين بمعاملين يطلب تعيينهما \item لتكن $ {G} $ مرجح الجملة \[\left\{ \left( A,-1 \right),\left( B,4 \right),\left( C,-2 \right) \right\}\] \item بين أن المستقيمين $ \left({AJ}\right) $ و$ \left({IC}\right) $ متقاطعان في النقطة $ {G} $ \item عين وأنشىء مجموعة النقط $ {M} $ التي تحقق: \[\left\| -\overrightarrow{MA}+4\overrightarrow{MB}-2\overrightarrow{MC} \right\|=\left\| \overrightarrow{MA}-\overrightarrow{MB} \right\|\] \item المستوي منسوب إلى معلم $\left( o,\overrightarrow{i},\overrightarrow{j} \right)$ لنعتبر أن: $ {A}(-{1},{0}) $ ، ${B}({0};{2}) $ و $ {C}({1},-{1}) $ \begin{enumerate} \item عين إحداثيات النقطة $ {G} $ \item لتكن النقطة $ {H}({2},{6}) $ مرجح النقطتين $ {A} $ و $ {B} $ المرفقتين بالمعاملين $ {a} $ و $ {b} $ على الترتيب عين عددين $ {a} $ و $ {b} $ يحققان ذلك . \end{enumerate} \end{enumerate} \end{exo} %%%%%%%%%%%%%%%%%%%%%%%%%% % EXO 4 %%%%%%%%%%%%%%%%%%%%%%%%%%% \begin{exo}{} حتوي كيس على ثلاث كرات خضراء وكرتين حمراوين وواحدة بيضاء، الكرات لا نميز بينهما عند اللمس، نسحب عشوائيا من الكيس كرتين على التوالي مع إرجاع الكرة المسحوبة إلى الكيس ثم في حالة السحب على التوالي دون ارجاع الكرة المسحوبة \medskip \begin{enumerate} \item شكل شجرة لهذه التجربة \item احسب احتمال الحصول على : \begin{enumerate} \item $ A $ " كرتين خضراوين " \item $ B $ " كرة بيضاء بالضبط فقط " \item $ C $ "كرة بيضاء على الأقل " \end{enumerate} \item ليكن $ {X} $ المتغير العشوائي الذي يرفق بكل سحب عدد الكرات الخضراء المتبقية في الكيس بعد السحب \begin{enumerate} \item حدد قيم المتغير العشوائي $ {X} $ \item احسب قانون احتمال المتغير العشوائي $ {X} $ \item احسب الأمل الرياضي \end{enumerate} \end{enumerate} \end{exo} %%%%%%%%%%%%%%%%%%%%%%%%%% % EXO 5 %%%%%%%%%%%%%%%%%%%%%%%%%%% \begin{exo}{} \begin{enumerate} \item أحسب كلا من $ \dfrac{2013\pi}{4} $ و $ \dfrac{1434\pi}{4} $ \item أثبت أن من اجل كل $ x $ من $ \mathbb{R} $ حيث $ \cos x \neq 0 $ فإن $ 1 + \tan^2 x = \dfrac{1}{\cos^2 x} $ ( نذكر أن $ \tan x = \dfrac{\sin x}{\cos x} $) \item أحسب قيمة $ \cos x $ إذا علمت ان : $ 0<x<\dfrac{\pi}{2} $ و $ \tan x = \dfrac{4}{3} $ \item من أجل كل عدد حقيقي $ x $، نضع : \[ g(x) = \sin\left(\pi -x \right) +2\sin\left( \dfrac{\pi}{2} -x \right) + \sin(\pi + x) - \cos(-x) \] \begin{enumerate} \item اثبت ان $ g(x) = \cos(x) $ من اجل كل $ x $ من $ \mathbb{R} $ \item حل في المجال $ \left[ 0;\pi\right] $ المعادلتين $ g(x) = \dfrac{\sqrt{3}}{2}، g(x)=-\dfrac{1}{2} $ \item مثل الصورتين الحلين على الدائرة المثلثية \item ستنتج مجموعة حلول المتراجحة : $ -\dfrac{1}{2}\leq g(x) \leq \dfrac{\sqrt{3}}{2} $ في المجال $ \left[ 0;\pi\right] $ \end{enumerate} \end{enumerate} \end{exo} \begin{exo}{} $(I$ لتكن الدالة $f$ المعرفة على مجموعة $D$ من $\mathbb{R}$ بــ : $f(x)=\sqrt{\dfrac{x+3}{x+2}}$ \begin{enumerate} \item بين أن $D=]-\infty;-3]\cup ]-2;+\infty [$. \item بين أن $f=g\circ h$ حيث $g$ هي الدالة جذر تربيعي و $h$ دالة يطلب تعيينها ثم عين مجموعة تعريفها $D_h$. \item تحقق أنه من أجل كل عدد حقيقي $x$ من $D_h$ فإن $h(x)=1+\dfrac{1}{x+2}$. \item إشرح طريقة رسم المنحنى $(C_h)$ الممثل للدالة $h$ في معلم متعامد و متجانس $(O;\vec{i};\vec{j})$. \item بين أن النقطة $\Omega(-2;1)$ مركز تناظر المنحنى $(C_h)$. \item عين إتجاه تغير الدالة $f$ عل كل من المجالين $]-\infty;-3]$ و $]-2;+\infty [$ \end{enumerate} $(II$ نعتبر الدالتين $h_1$ و $h_2$ حيث $h_1=|h(x)|$ و $h_2(x)=h(-|x|)$. \begin{enumerate} \item إشرح طريقة رسم $(C_{h_{1}})$ ثم ارسمه في نفس المعلم السابق. \item عين $D_{h_{2}}$ \item اثبت أن الدالة $h_2$ دالة زوجية. \item أكتب $h_2(x)$ بدون رمز القيمة المطلقة. \item إشرح طريقة رسم $(C_{h_{2}})$ منحنى الدالة $h_2$ إتطلاقا من $(C_h)$. \end{enumerate} \end{exo} % \begin{exo}{} في المستوي المنسوب إلى معلم متعامد و متجانس $(O;\vec{i};\vec{j})$ ليكن $(C_f)$ و $(C_g)$ التمثيلان البيانيان للدالتين $f$ و $g$ كما هو موضح في البيان المقابل. \begin{enumerate} \item عين $D_{g\circ f}$. \item عين كل من $(g\circ f)(-1)$، $(f\circ g)(0)$ و $(g\circ f \circ g)(-1)$. \item حل بيانيا المعادلتين : $(g\circ f)(x)=-1$ و $(f\circ g)(x)=-1$. \item حل بيانيا المتراجحتين : $(g\circ f)(x)>- 1$ و $(f\circ g)(x)<-1$. \end{enumerate} \begin{center} \pgfdeclarelayer{background} \pgfsetlayers{background,main} \begin{tikzpicture}[>=stealth] \begin{axis}[width=10cm,axis equal image, axis lines=middle, xmin=-4,xmax=4, ymin=-4,ymax=4, grid=major, major grid style={thick,black!30}, tick style={thick}, axis line style={thick}, xlabel style={below=1mm}, ylabel style={left}, xlabel={$x$}, ylabel={$y$}, ytick={-4,...,4}, xtick={-4,...,4}, ticklabel style={font=\tiny}, enlargelimits={abs=5mm} ] \draw (-3,0) .. controls (-2.2362976110374655,0.022349953705373557 ) and (-1.7871145139449278,-2.003752526797132 ) .. (-1,-2) .. controls (-0.21288548605507218,-1.9962474732028679 ) and (0.7263994123388461,0.710460230102451 ) .. (1,1) .. controls (1.273600587661154,1.289539769897549 ) and (2.5,2.5 ) .. (3,3); \node[pin={-100:$\color{blue}{(\mathcal{C}_{f})}$}] at (axis cs:{-3.0, -2.0}) {}; \draw[blue] (-3,-2) .. controls (-2.5,-2 ) and (-2.217183436693102,-1.1722859428173302 ) .. (-2,-1) .. controls (-1.782816563306898,-0.8277140571826698 ) and (-1.0607758888591223,-0.41727605621498143 ) .. (-1,0) .. controls (-0.9392241111408777,0.41727605621498143 ) and (-0.2962089150845904,3.0137182385982237 ) .. (0,3) .. controls (0.2962089150845904,2.9862817614017763 ) and (0.6977281508223012,1.2169858502280775 ) .. (1,1) .. controls (1.3022718491776988,0.7830141497719225 ) and (1.653436868040466,0.347290917559549 ) .. (2,0) .. controls (2.3465631319595337,-0.347290917559549 ) and (2.723830631324811,-0.9715871122015161 ) .. (3,-1); \node[pin={100:${(\mathcal{C}_{g})}$}] at (axis cs:{3.0, 3.0}) {}; \end{axis} \begin{pgfonlayer}{background} \draw[drop shadow,draw,fill=white] ([yshift=2pt,xshift=-8pt]current bounding box.north west) rectangle ([xshift=2pt,yshift=-8pt]current bounding box.south east); \end{pgfonlayer} \end{tikzpicture} \end{center} \end{exo} \begin{exo}{} $f$ دالة معرفة على و $\mathbb{R}-\{4\}$ بــ : $f(x)=a+\dfrac{b}{x-4}$ حيث $a$ و $b$ عددان حقيقيان $(C_f)$ نمثيليها البياني في المستوي المنسوب إلى معلم متعامد و متجانس $(O, \overrightarrow{i}; \overrightarrow{j})$، كما هو موضح في البيان أسفله . \begin{enumerate} \item عين شعاع الإنسحاب الذي يسمح بالإنتقال من منحنى الدالة مقلوب إلى المنحنى $(C_f)$. \item استنتج عبارة الدالة $f$. \item شكل جدول تغيرات الدالة $f$. \item خمن بيانيا إحداثيتي مركز تناظر المنحنى $(C_f)$ ثم تأكد جبريا. \item حل بيانيا المتراجحة $f(x)\geq 0$. \item لتكن الدالة $g$ المعرفة على $\mathbb{R}-\{4\}$ بــ : $g(x)=\left| \dfrac{x-3}{x-4}\right| $ \end{enumerate} \begin{enumerate} \item أكتب $g(x)$ بدون رمز القيمة المطلقة. \item إشرح كيفية إنشاء $(C_g)$ إنطلاقا من $(C_f)$ ثم أنشئه. \item باستعمال إتجاه تغير مركب دالتين، أدرس إتجاه تغير الدالة $h$ المعرفة على $\mathbb{R}-\{4\}$ بــ : $h(x)=[f(x)]^{2}$ \end{enumerate} \begin{center} \pgfdeclarelayer{background} \pgfsetlayers{background,main} \begin{tikzpicture}[>=stealth] \begin{axis}[width=9cm,axis equal image, axis lines=middle, xmin=-1,xmax=6, ymin=-3,ymax=4, grid=major, major grid style={thick,black!30}, tick style={thick}, axis line style={thick}, xlabel style={below=1mm}, ylabel style={left}, xlabel={$x$}, ylabel={$y$}, ytick={-3,...,4}, xtick={-1,...,6}, ticklabel style={font=\tiny}, enlargelimits={abs=5mm} ] \addplot[very thick,,smooth,red,domain=4.1:6.5]{((x-3)/(x-4))}; \addplot[very thick,,smooth,red,domain=-1.0:3.9]{((x-3)/(x-4))}; \node[pin={100:$\color{red}{(\mathcal{C}_{f})}$}] at (axis cs:{2.0, 0.5}) {}; \end{axis} \begin{pgfonlayer}{background} \draw[drop shadow,draw,fill=white] ([yshift=2pt,xshift=-8pt]current bounding box.north west) rectangle ([xshift=2pt,yshift=-8pt]current bounding box.south east); \end{pgfonlayer} \end{tikzpicture} \end{center} \end{exo} \end{multicols*} \end{document} Note: I would like to point out that this is not an isolated incident; this issue occurs consistently across all my documents whenever I use this specific combination. Questions: Is there a known conflict between tcolorbox (breakable), multicol, and polyglossia (RTL) under XeLaTeX? How can I force the vertical spacing to be completely normal without these large gaps? Any assistance or workarounds would be deeply appreciated!

I have \usepackage{epigraph} in the preamble and write: \documentclass{article} \usepackage{geometry} \usepackage{epigraph} \begin{document} \epigraph{ Visibility and identity are fundamental.\\ Step-identicality makes propositions from antepositions,\\ truth from visibility,\\ and sets from visions. }{} \end{document} But this produces: but I notice that it produces an epigraph under TexStudio which is different from the one I quoted above --- which was produced under OverLeaf. Nevertheless, in both cases there were line breaks which call for a shift of the epigraph to the left. How may I shift the epigraph to the left by the length of "antepositions" so that the epigraph produces the four lines correctly---without affecting the other epigraphs in the document?

[continuation of this closed question from today] I would like to have the limits above and below the integral, not on the right side. Using pdflatex I realized this with the shown options for amsmath. What do I have to do when using lualatex? \documentclass{scrartcl} %\usepackage[intlimits,sumlimits]{amsmath} % used w/ pdflatex \usepackage{unicode-math} %\setsansfont{KpSans} %\setmainfont{KpRoman} %\setmathfont{KpMath-Regular} \begin{document} \begin{equation} E = \int_0^x m d c \end{equation} \end{document} With the \removenolimits macro the limits are on the right place (for me on displayed equations). When I compare the results with pdflatex & kpfonts with lualatex & kpfonts-otf I notice two points: (1) The slanted integral sign looks better (for me). But this is surely the decision of the designer. That's ok for me. (2) The distance between the integral sign and the integrand is far too long. Of course I can modify the \int macro, but maybe there is a better way?!

I'm using setlength\itemsep{..} to change the space between subitems of a customized list. The problem is that the last "subitem" is too close to the second "main item" (see picture). This is quite ugly and unbalanced. Is there a way to automatically increase the spacing (other than setlength\itemsep{..} or \vspace) that would fit in this case? \documentclass{article} \usepackage{enumitem} \newlist{questions}{enumerate}{3} \setlist[questions,1]{font=\bfseries, label = Exercise~\arabic*~:, ref = \arabic*, align = left, wide=0cm} \setlist[questions,2]{label=\bfseries \arabic*),align = right, leftmargin=1.2cm} \begin{document} \begin{questions} \item Question? \begin{questions} \item Subquestion 1 \item Subquestion2: nice spacing \end{questions} \item More Questions? \begin{questions} \item Subquestion 1 \item Subquestion2 \end{questions} \end{questions} \vspace{2cm} \begin{questions} \item Question? \begin{questions}\setlength\itemsep{3em} \item Subquestion 1 \item Subquestion2 : bad spacing \end{questions} \item More Questions? \begin{questions} \item Subquestion 1 \item Subquestion2 \end{questions} \end{questions} \end{document}

I would like to have the limits above and below the integral, not on the right side. Using pdflatex I realized this with the shown options for amsmath. What do I have to do when using lualatex? \documentclass{scrartcl} \usepackage{fontspec} %\usepackage[intlimits,sumlimits]{amsmath} \usepackage{unicode-math} %\setsansfont{KpSans} %\setmainfont{KpRoman} %\setmathfont{KpMath-Regular} \begin{document} \begin{equation} E = \int_0^x m d c \end{equation} \end{document}

I'm trying to write a set of course notes with LaTeX's accessibility tagging on, but I want to change up the chapter and sections headings. The titlesec package is incompatible, so I'm using the \EditInstance command, based on the answers to this previously asked question: Space between top of text area and chapter heading using \EditInstance formating (ruled headformat) I copy-pasted MWE#2 from that answer into my LaTeX editor, re-copied below for completeness. I'm compiling with TexLive 2026's version of lua-latex, which reports itself as ' LuaHBTeX, Version 1.24.0 (TeX Live 2026) ', all packages are up-to-date in tlmgr. The issue is that I get several errors of the form "LaTeX template: Unknown template key 'after-sep'." (I also get the same error for before-sep and decls, as well as "LaTeX template: The instance 'hang' of type 'headformat' is unknown.") I'd like to make this MWE work on my system (so I can modify it to my needs), but I can't for the life of me figure out what is going on. I haven't been able to find any good documentation online about the \EditInstance command, I'm basically just going off of what I can learn from Stack Exchange questions. Any help is appreciated! % Source - https://tex.stackexchange.com/q/760989 % Posted by polaren % Retrieved 2026-08-10, License - CC BY-SA 4.0 \DocumentMetadata{ lang = sv, pdfversion = 2.0, pdfstandard = ua-2, tagging = on, } \documentclass[11pt,a4paper,twoside,final]{report} \usepackage[margin=25mm,top=24mm,bottom=24mm,nomarginpar,nohead,footskip=11mm]{geometry} \usepackage{showframe}\renewcommand\ShowFrameLinethickness{0.05mm} \usepackage[document]{ragged2e} % Needed for compilation. \usepackage{hyperref} % Needed to pass VeraPDF. \hypersetup{ pdftitle={MWE}, pdfauthor={polaren}, pdfsubject={First question to LaTeX Stack Exchange.}, } \EditInstance{heading}{chapter}{ number-format=\makebox[12mm][l]{\theheading.}, number-decls=\sffamily\fontsize{14pt}{16pt}\selectfont, title-decls=\sffamily\fontsize{14pt}{16pt}\selectfont, after-sep=0mm, before-sep=0mm, start-code=\clearpage\vspace*{-10.75mm}\rule{\textwidth}{0.1mm}\newline\vspace*{-18mm}, final-code=\vspace*{-5mm}\rule{\textwidth}{0.1mm}\newline\vspace*{0mm}, headformat-instance=hang, decls=\raggedright\parindent 0pt\rmfamily } \setlength{\parskip}{6pt plus 1pt minus 1pt} %\setlength{\parskip}{0pt} \usepackage{kantlipsum} \begin{document} \chapter*{Unnumbered Chapter} Test. \chapter{Title of Chapter} \kant[1] \end{document}

This is a follow-up question, based on the solutions found in Is There a Simpler Way to Use Lettrines in a Verse Environment without Invoking a Subroutine? In an attempt to help a friend compose a book of her poems, I have tried to take advantage of the lessons above, in particular the last one using the lettrine method. However when I change the poem (seemingly without any other change), I get the two first lines severely indented and the output is not visually satisfactory. I could not explain the reason for this and even less find a correction. \documentclass[a4paper,10pt]{article} \usepackage{lettrine} \usepackage{verse} \begin{document} \poemtitle{Complete solution via {\em lettrine} methods} \begin{verse}[8cm] \lettrine[lhang=1.5,nindent=0em]{M}{aking} a famine where abundance lies,\\> Thy self thy foe, to thy sweet self too cruel.\\ Thou that art now the world's fresh ornament, \\ And only herald to the gaudy spring, \\ Within thine own bud buriest thy content, \end{verse} \bigskip \poemtitle {The Sea Bell} \begin{verse}[8cm] \lettrine[lhang=1.5,nindent=0em]{I}{walked} by the sea,\\> and there came to me,\\ as a star-beam on the wet sand,\\ a white shell like a sea-bell;\\ trembling it lay\\ in my wet hand.\\ In my fingers shaken I heard waken\\ a ding within, by a harbour bar\\ a buoy swinging, a call ringing\\ over endless seas,\\ faint now and far\ldots \end{verse} \end{document

I have a situation where for a couple of sections I do have subsections in the toc but for the remaining two I don't. Below, an example of how the Outline looks like: Now, as you can see, section 1 and 3 align, whereas 2 and 4 does not. Would there be a way to horizontally align section 4 to section 2 in the toc? MWE \documentclass{beamer} \usetheme{Boadilla} \usepackage{calc} \useoutertheme[width=0pt,height=.5in]{sidebar} \newlength\MyColSep \setlength\MyColSep{.1in} \newlength\MyColWd \setlength\MyColWd{0.5\textwidth-\MyColSep} \AtBeginSection[]{ \begin{frame}{Outline} \begin{columns}[T] \begin{column}{.5\textwidth} \setlength{\parskip}{2ex} \tableofcontents[sections={1-2},currentsection,sectionstyle=show/shaded,subsectionstyle=show/shaded] \end{column} \begin{column}{.5\textwidth} \setlength{\parskip}{2ex} \tableofcontents[sections={3-4},currentsection,sectionstyle=show/shaded,subsectionstyle=show/shaded] \end{column} \end{columns} \end{frame} } \AtBeginSubsection[] { \begin{frame} \frametitle{Outline} \begin{columns}[T] \begin{column}{\MyColWd} \setlength{\parskip}{2ex} \tableofcontents[sections={1-2},currentsection,currentsubsection,subsectionstyle=show/shaded] \end{column} \begin{column}{\MyColWd} \setlength{\parskip}{2ex} \tableofcontents[sections={3-4},currentsection,currentsubsection,subsectionstyle=show/shaded] \end{column} \end{columns} \end{frame} } \begin{document} \section{SECTION 1} \subsection{a subsection 1} \subsection{a subsection 2} \subsection{a subsection 3} \section{SECTION 2} \subsection{a subsection 1} \subsection{a subsection 2} \subsection{a subsection 3} \section{SECTION 3} \section{SECTION 4} \end{document}

I am trying to reproduce a 3D figure from a mathematics book in LaTeX using TikZ/PGFPlots. The figure shows two surfaces and their intersection. The two surfaces are given by x^2 + xy - y - 3z = 0 and 2x^2 + 3xy - 2y - 3z = 0. I plotted both surfaces directly from their equations and also added their intersection curve. However, the shape and especially the intersection curve in my output look quite different from the figure in the book, even though I am using the same equations. I am not sure whether the difference is caused by the viewing angle, the plotting ranges, the parametrization of the intersection curve, or something else. Here is my current code: \documentclass[border=5pt]{standalone} \usepackage{pgfplots} \usepackage{tikz} \pgfplotsset{compat=1.18} \begin{document} \begin{tikzpicture} \begin{axis}[ view={120}{25}, axis lines=none, xmin=-2.5, xmax=2.5, ymin=-2.5, ymax=2.5, zmin=-5, zmax=5, width=11cm, height=8cm, ticks=none, ] %================================================ % GREEN SURFACE % 2x^2 + 3xy - 2y - 3z = 0 %================================================ \addplot3[ surf, shader=interp, colormap={greenmap}{ color(0cm)=(green!15); color(1cm)=(green!35) }, colormap name=greenmap, domain=-2:2, y domain=-2:2, samples=35, samples y=35, opacity=0.65, ] { (2*x^2 + 3*x*y - 2*y)/3 }; %================================================ % BLUE SURFACE % x^2 + xy - y - 3z = 0 %================================================ \addplot3[ surf, shader=interp, colormap={bluemap}{ color(0cm)=(blue!15); color(1cm)=(blue!35) }, colormap name=bluemap, domain=-2.2:2.2, y domain=-2.2:2.2, samples=30, samples y=30, opacity=0.55, ] { (x^2 + x*y - y)/3 }; %================================================ % INTERSECTION CURVE % gamma(t) = % ( t, -t^2/(2t-1), t^3/(3(2t-1)) ) %================================================ \addplot3[ very thick, red, samples=100, domain=-2.2:0.35, variable=\t, ] ( {\t}, {-\t^2/(2*\t-1)}, {\t^3/(3*(2*\t-1))} ); \addplot3[ very thick, red, samples=50, domain=0.65:2.2, variable=\t, ] ( {\t}, {-\t^2/(2*\t-1)}, {\t^3/(3*(2*\t-1))} ); \end{axis} \end{tikzpicture} \end{document} The book's figure has a noticeably different orientation and shape for the two surfaces and their intersection. The book's figure looks like this: My current output looks like this: Could someone please explain what is causing this difference and how I can modify my PGFPlots code to obtain a figure that looks like the one in the book? In particular, I would like to know whether I should change the view angles, the plotting domains, or the parametrization of the intersection curve.

I would like to know if there is both a correct and "nice" way to use punctuation in systems of equations. I have tried \documentclass{article} \usepackage{amsmath,array} \usepackage{systeme} \begin{document} This looks correct but ugly $$ \systeme{x+y=7, x-y = 3}\,. $$ What about $$ \systeme{5x+2y=7\, , 5x-2y= 3\,. } $$ \end{document} The first solution is what I would expect to be correct but it's quite ugly. The second solution does not display the comma after the first equation. Is there a rule for punctuation after a system? If yes, how to do it with this command?

I have an arbitrary function which outputs a 1D parametric triple in Asymptote. I want to find the Frenet basis of it at a point without resorting to coding derivatives for every individual function. My goal is to have a function which gives me the approximated Frenet basis of any triple-producing 1D function at a specific input. import three; import graph3; unitsize(3cm); triple curve(real t) { real t1 = 3.14 * t; return ( cos(t), sin(t), t ); } path3 f = graph(curve, 0, 2*pi, n=20); draw(f); /* I am attempting to make a function which accepts an arbitrary triple function, and an arbitrary parameter value. It's goal is to produce the matrix containing the position vector, the tangent vector, the normal vector, and the binormal vector - the so called Frenet basis. How can I do this for an arbitrary function. My goal is to not have to write individual matrix functions for every parametric curve. I'd much rather just input the curve's function and a parameter-value and be given the orthonormalized Frenet basis. */ real[][] T(triple function, real param) { triple df(real t) { return (1/0.04)*(function(t+0.02)-function(t-0.02)) } return {{df(param)},{},{},{}} }; I was able to achieve it in Lua, since my software enables verbose input. \documentclass[tikz, border=1cm]{standalone} \usepackage{lua-tikz3dtools} \begin{document} \begin{tikzpicture} \useasboundingbox[scale=0.5] (-5,-5) rectangle (5,5); \ltdtsetobject[ name=objs, object={ return { view = Matrix.zyzrotation(Vector:new{7*pi/6,pi/6,pi/2}), alpha = function(t) return Vector:new{sin(t)+2*sin(2*t),cos(t)-2*cos(2*t),-sin(3*t),1} end, frenet = function(surf, param) local tangent = function(s, p) return s(p + 0.02):hsub(s(p - 0.02)):hscale(1 / 0.04):hnormalize() end local normal = function(s, p) local tang = function(t) return tangent(s, t):hnormalize() end return tangent(tang, p) end local T = tangent(surf, param):hnormalize() local N = normal(surf, param):hnormalize() local B = T:hcross(N):hnormalize() local P = surf(param) local RE = Matrix:new{T, N, B, P} % currently projective, needs to be affine (at this time, at leat) RE[1][4] = 0 RE[2][4] = 0 RE[3][4] = 0 return RE end } } ] \ltdtappendlight[v={return Vector:new{1,1,1,1}}] \iffalse \ltdtappendcurve[ uparams={return Vector:new{0,tau,100}}, v={ return objs.alpha(u) :multiply(objs.view) }, draw options={return "draw, line cap=round"} ] \fi \ltdtappendsurface[ uparams={return Vector:new{0,tau,200}}, vparams={return Vector:new{0,tau,10}}, v={ return Vector:new{0, cos(v)/5, sin(v)/5, 1} :multiply(objs.frenet(objs.alpha, u)) :multiply(objs.view) }, fill options={return "fill=ltdtbrightness"} ] \ltdtdisplaysimplices \end{tikzpicture} \end{document} I also did it ad-hocly in tikz... https://chat.stackexchange.com/transcript/message/69138959#69138959

I have a problem with the headings of my arabic (right to left) file... "In the following file header code, the logic should work like this: Sections: Sections appearing on the same page should be printed on the left side of the header inside brackets [], separated by commas (,). Any unfinished section continuing onto the current page must also be included with the current page's sections in the header, preserving their order. Subsections: The same principle applies to subsections, which are also placed on the left side of the header." % ========================================================= % 12. الرأسية والتذييل ودعم النجمة (*) للعناوين أوتوماتيكياً % ========================================================= \usepackage{fancyhdr} \usepackage{extramarks} \usepackage{expl3} \patchcmd{\chapter}{\thispagestyle{plain}}{\thispagestyle{empty}}{}{} \patchcmd{\part}{\thispagestyle{plain}}{\thispagestyle{empty}}{}{} % --------------------------------------------------------- % المحرك الذكي المطور (التمييز التلقائي بين أعلى ومطب الصفحة) % --------------------------------------------------------- \ExplSyntaxOn \seq_new:N \g_my_sec_seq \seq_new:N \g_my_subsec_seq \seq_new:N \l_my_top_seq \seq_new:N \l_my_last_seq \seq_new:N \l_my_res_seq \seq_new:N \l_my_split_seq \int_new:N \l_my_top_len_int \int_new:N \l_my_last_len_int \int_new:N \l_my_start_idx_int \dim_new:N \g_my_pbefore_dim \dim_new:N \g_my_pafter_dim \tl_new:N \l_my_tmp_item_tl \tl_new:N \l_my_clean_title_tl \tl_new:N \l_my_tag_tl \tl_new:N \l_my_first_new_tl \tl_new:N \l_my_tmp_sec_tl \tl_new:N \l_my_tmp_sub_tl \cs_generate_variant:Nn \my_process_marks:nn { VV } % دالة استخراج العنوان بدون الرمز \cs_new_protected:Npn \my_get_title:nN #1#2 { \seq_set_split:Nnn \l_my_split_seq { ::: } {#1} \tl_set:Nx #2 { \seq_item:Nn \l_my_split_seq { 1 } } } \cs_generate_variant:Nn \my_get_title:nN { VN } % دالة استخراج رمز الموضع (T لأعلى الصفحة، M لمنتصف الصفحة) \cs_new_protected:Npn \my_get_tag:nN #1#2 { \seq_set_split:Nnn \l_my_split_seq { ::: } {#1} \tl_set:Nx #2 { \seq_item:Nn \l_my_split_seq { 2 } } } \cs_generate_variant:Nn \my_get_tag:nN { VN } % تسجيل ارتفاع الصفحة قبل إضافة العنوان \cs_new_protected:Npn \my_mark_before: { \dim_gset:Nn \g_my_pbefore_dim { \pagetotal } } % معالجة موضع الـ Section بعد إضافته (بدون أي تعديل إطلاقاً) \cs_new_protected:Npn \my_add_section_after:n #1 { \dim_gset:Nn \g_my_pafter_dim { \pagetotal } \tl_clear:N \l_my_tag_tl \dim_compare:nTF { \g_my_pbefore_dim > \topskip + 5pt } { \dim_compare:nTF { \g_my_pafter_dim >= \g_my_pbefore_dim } { \tl_set:Nn \l_my_tag_tl { M } } { \tl_set:Nn \l_my_tag_tl { T } } } { \tl_set:Nn \l_my_tag_tl { T } } \seq_gput_right:Nx \g_my_sec_seq { #1:::\l_my_tag_tl } \my_update_marks: } % معالجة موضع الـ Subsection بعد إضافته \cs_new_protected:Npn \my_add_subsection_after:n #1 { \dim_gset:Nn \g_my_pafter_dim { \pagetotal } \tl_clear:N \l_my_tag_tl \dim_compare:nTF { \g_my_pbefore_dim > \topskip + 5pt } { \dim_compare:nTF { \g_my_pafter_dim >= \g_my_pbefore_dim } { \tl_set:Nn \l_my_tag_tl { M } } { \tl_set:Nn \l_my_tag_tl { T } } } { \tl_set:Nn \l_my_tag_tl { T } } \seq_gput_right:Nx \g_my_subsec_seq { #1:::\l_my_tag_tl } \my_update_marks: } % تحديث علامات extramarks \cs_new_protected:Npn \my_update_marks: { \tl_set:Nx \l_my_tmp_sec_tl { \seq_use:Nn \g_my_sec_seq { @@@ } } \tl_set:Nx \l_my_tmp_sub_tl { \seq_use:Nn \g_my_subsec_seq { @@@ } } \extramarks{\l_my_tmp_sec_tl}{\l_my_tmp_sub_tl} } % تصفير ذاكرة الفصل \cs_new_protected:Npn \my_reset_chapter: { \seq_gclear:N \g_my_sec_seq \seq_gclear:N \g_my_subsec_seq \extramarks{}{} } % الخوارزمية الخاصة بـ Sections (بدون أي تعديل) \cs_new_protected:Npn \my_process_marks:nn #1#2 { \seq_clear:N \l_my_top_seq \seq_clear:N \l_my_last_seq \seq_clear:N \l_my_res_seq \tl_if_empty:nF {#1} { \seq_set_split:Nnn \l_my_top_seq { @@@ } {#1} } \tl_if_empty:nF {#2} { \seq_set_split:Nnn \l_my_last_seq { @@@ } {#2} } \int_set:Nn \l_my_top_len_int { \seq_count:N \l_my_top_seq } \int_set:Nn \l_my_last_len_int { \seq_count:N \l_my_last_seq } \int_compare:nF { \l_my_last_len_int = 0 } { \int_compare:nTF { \l_my_last_len_int = \l_my_top_len_int } { \tl_set:Nx \l_my_tmp_item_tl { \seq_item:Nn \l_my_last_seq { \l_my_last_len_int } } \my_get_title:VN \l_my_tmp_item_tl \l_my_clean_title_tl \seq_put_right:NV \l_my_res_seq \l_my_clean_title_tl } { \tl_set:Nx \l_my_first_new_tl { \seq_item:Nn \l_my_last_seq { \l_my_top_len_int + 1 } } \my_get_tag:VN \l_my_first_new_tl \l_my_tag_tl \str_if_eq:nnTF { \l_my_tag_tl } { M } { \int_compare:nTF { \l_my_top_len_int > 0 } { \int_set:Nn \l_my_start_idx_int { \l_my_top_len_int } } { \int_set:Nn \l_my_start_idx_int { 1 } } } { \int_set:Nn \l_my_start_idx_int { \l_my_top_len_int + 1 } } \int_step_inline:nnn { \l_my_start_idx_int } { \l_my_last_len_int } { \tl_set:Nx \l_my_tmp_item_tl { \seq_item:Nn \l_my_last_seq { ##1 } } \my_get_title:VN \l_my_tmp_item_tl \l_my_clean_title_tl \seq_put_right:NV \l_my_res_seq \l_my_clean_title_tl } } } \seq_if_empty:NF \l_my_res_seq { [~\seq_use:Nn \l_my_res_seq { ~،~ }~] } } % --------------------------------------------------------- % الخوارزمية الخاصة والمضمونة لـ Subsections % --------------------------------------------------------- \cs_new_protected:Npn \my_process_subsections_marks:nn #1#2 { \seq_clear:N \l_my_top_seq \seq_clear:N \l_my_last_seq \seq_clear:N \l_my_res_seq \tl_if_empty:nF {#1} { \seq_set_split:Nnn \l_my_top_seq { @@@ } {#1} } \tl_if_empty:nF {#2} { \seq_set_split:Nnn \l_my_last_seq { @@@ } {#2} } \int_set:Nn \l_my_top_len_int { \seq_count:N \l_my_top_seq } \int_set:Nn \l_my_last_len_int { \seq_count:N \l_my_last_seq } \int_compare:nF { \l_my_last_len_int = 0 } { % 1. في حالة عدم وجود أي subsection جديد في الصفحة الحالية \int_compare:nTF { \l_my_last_len_int = \l_my_top_len_int } { % عرض الـ subsection الممتد الأخير من الصفحات السابقة \tl_set:Nx \l_my_tmp_item_tl { \seq_item:Nn \l_my_last_seq { \l_my_last_len_int } } \my_get_title:VN \l_my_tmp_item_tl \l_my_clean_title_tl \seq_put_right:NV \l_my_res_seq \l_my_clean_title_tl } { % 2. وجود subsections جديدة في الصفحة الحالية % إذا كان هناك subsection سابق ممتد من الصفحة السابقة، نبدأ منه دائماً \int_compare:nTF { \l_my_top_len_int > 0 } { \int_set:Nn \l_my_start_idx_int { \l_my_top_len_int } } { \int_set:Nn \l_my_start_idx_int { 1 } } % تجميع العنوان الممتد + العناوين الجديدة الظاهرة في الصفحة \int_step_inline:nnn { \l_my_start_idx_int } { \l_my_last_len_int } { \tl_set:Nx \l_my_tmp_item_tl { \seq_item:Nn \l_my_last_seq { ##1 } } \my_get_title:VN \l_my_tmp_item_tl \l_my_clean_title_tl \seq_put_right:NV \l_my_res_seq \l_my_clean_title_tl } } } \seq_if_empty:NF \l_my_res_seq { [~\seq_use:Nn \l_my_res_seq { ~،~ }~] } } \cs_generate_variant:Nn \my_process_subsections_marks:nn { VV } % ربط دوال العرض \cs_new_protected:Npn \my_render_sections: { \tl_set:Nx \l_my_tmp_sec_tl { \topleftxmark } \tl_set:Nx \l_my_tmp_sub_tl { \lastleftxmark } \my_process_marks:VV \l_my_tmp_sec_tl \l_my_tmp_sub_tl } \cs_new_protected:Npn \my_render_subsections: { \tl_set:Nx \l_my_tmp_sec_tl { \toprightxmark } \tl_set:Nx \l_my_tmp_sub_tl { \lastrightxmark } \my_process_subsections_marks:VV \l_my_tmp_sec_tl \l_my_tmp_sub_tl } % تصدير الدوال \cs_gset_eq:NN \renderSections \my_render_sections: \cs_gset_eq:NN \renderSubSections \my_render_subsections: \cs_gset_eq:NN \myMarkBefore \my_mark_before: \cs_gset_eq:NN \addSectionAfter \my_add_section_after:n \cs_gset_eq:NN \addSubsectionAfter \my_add_subsection_after:n \cs_gset_eq:NN \resetHeaderChapter \my_reset_chapter: \ExplSyntaxOff \makeatletter % إعادة تعريف \section و \section* (بدون أي تعديل) \let\oldsection\section \RenewDocumentCommand{\section}{s o m}{% \myMarkBefore \IfBooleanTF{#1} {% عند استخدام \section* \oldsection*{#3}% \addcontentsline{toc}{section}{#3}% } {% حالة \section المرقم \IfValueTF{#2} {\oldsection[#2]{#3}} {\oldsection{#3}}% }% \addSectionAfter{#3}% } % إعادة تعريف \subsection و \subsection* \let\oldsubsection\subsection \RenewDocumentCommand{\subsection}{s o m}{% \myMarkBefore \IfBooleanTF{#1} {% عند استخدام \subsection* \oldsubsection*{#3}% \addcontentsline{toc}{subsection}{#3}% } {% حالة \subsection المرقم \IfValueTF{#2} {\oldsubsection[#2]{#3}} {\oldsubsection{#3}}% }% \addSubsectionAfter{#3}% } % تصفير الذاكرة عند بداية كل فصل جديد (\chapter) \AddToHook{cmd/chapter/before}{% \clearpage \resetHeaderChapter } \makeatother \pagestyle{fancy} \fancyhf{} % اليسار للـ Section واليمين للـ Subsection \fancyhead[L]{\small\bfseries\renderSections} \fancyhead[R]{\small\renderSubSections} \fancyfoot[C]{الأستاذ: عماد عقوني} \fancyfoot[LE,RO]{\thepage} \renewcommand{\headrulewidth}{1pt} \renewcommand{\footrulewidth}{1pt} \fancypagestyle{plain}{% \fancyhf{} \fancyfoot[C]{الأستاذ: عماد عقوني} \fancyfoot[LE,RO]{\thepage} \renewcommand{\headrulewidth}{0pt} \renewcommand{\footrulewidth}{1pt} } \fancypagestyle{tocstyle}{% \fancyhf{} \fancyfoot[C]{(\abjad{page})} \renewcommand{\headrulewidth}{0pt} \renewcommand{\footrulewidth}{0pt} }

I am trying to recreate the following mathematical figure in LaTeX/TikZ. The figure shows the one-sheet hyperboloid x^2 + y^2 - z^2 = 1 together with the plane 2x + z = 1. Their intersection is the red curve shown on the hyperboloid. After quite a lot of effort, I have managed to draw the one-sheet hyperboloid reasonably well in TikZ. However, I am having difficulty with the two remaining parts: How can I draw the transparent red plane 2x + z = 1 behind/in front of the hyperboloid, as shown in the reference image? How can I draw the red intersection curve between the plane and the hyperboloid so that it lies correctly on the surface? I would like the final figure to look as close as possible to the reference image, including the perspective, transparency of the plane, and the red intersection curve. Here is the code I currently have for the hyperboloid: \documentclass[border=5pt]{standalone} \usepackage{pgfplots} \usepackage{tikz} \pgfplotsset{compat=1.18} \begin{document} \begin{tikzpicture}[>=stealth] \begin{axis}[ view={120}{22}, axis lines=none, xmin=-3.3, xmax=3.3, ymin=-3.3, ymax=3.3, zmin=-2.0, zmax=2.0, xtick=\empty, ytick=\empty, ztick=\empty, clip=false, ] %------------------------------------------------ % Red point at the origin %------------------------------------------------ \addplot3[ only marks, mark=*, mark size=2.5pt, draw=red, fill=red, ] coordinates {(0,0,0)}; %------------------------------------------------ % Smooth one-sheet hyperboloid %------------------------------------------------ \addplot3[ surf, shader=interp, draw=blue!55!black, opacity=0.65, samples=45, samples y=80, domain=-2.2:2.2, y domain=0:360, z buffer=sort, ] ( {sqrt(1+x^2)*cos(y)}, {sqrt(1+x^2)*sin(y)}, {x} ); %------------------------------------------------ % POSITIVE x-axis %------------------------------------------------ \draw[ ->, black, thick ] (axis cs:0,0,0) -- (axis cs:5.0,0,0) node[right] {$x$}; %------------------------------------------------ % NEGATIVE x-axis -- dashed %------------------------------------------------ \draw[ dashed, black, thick ] (axis cs:0,0,0) -- (axis cs:-2.0,0,0); %------------------------------------------------ % POSITIVE y-axis %------------------------------------------------ \draw[ ->, black, thick ] (axis cs:0,0,0) -- (axis cs:0,4.0,0) node[above left] {$y$}; %------------------------------------------------ % NEGATIVE y-axis -- dashed %------------------------------------------------ \draw[ dashed, black, thick ] (axis cs:0,0,0) -- (axis cs:0,-1.0,0); %------------------------------------------------ % POSITIVE z-axis %------------------------------------------------ \draw[ ->, black, thick ] (axis cs:0,0,0) -- (axis cs:0,0,3.0) node[above] {$z$}; %------------------------------------------------ % NEGATIVE z-axis -- dashed %------------------------------------------------ \draw[ dashed, black, thick ] (axis cs:0,0,0) -- (axis cs:0,0,-2.0); %------------------------------------------------ % Origin %------------------------------------------------ \node[ below right, inner sep=1pt ] at (axis cs:0,0,0) {$0$}; %------------------------------------------------ % Equation %------------------------------------------------ \node[ blue!75!black, font=\large ] at (axis cs:2.0,-0.5,1.1) {$x^2+y^2-z^2=1$}; \end{axis} \end{tikzpicture} \end{document} I would be very grateful for any suggestions on how to add the plane and, especially, the intersection curve correctly. Thank you!

I'm trying to format an algorithm using algorithm2e and hyperref. I would like to achieve that the algorithm's name is printed in sans-serif font (in the algorithm caption and whenever it is referenced via \ref). Minimal (non) working example: \documentclass{article} \usepackage[algoruled]{algorithm2e} \usepackage{hyperref} \begin{document} Below, we present Algorithm~\ref{alg:myalg}. \begin{algorithm} \SetAlgoLined \SetAlgoRefName{MyAlg} \If{$x >0$}{ \KwRet{$x$}} \caption{A test algorithm} \label{alg:myalg} \end{algorithm} \end{document} What I have tried: If I use something like \SetAlgoRefName{\sffamily MyAlg} and add \SetAlCapFnt{\normalfont} in the example above, the document will compile with multiple errors, but the result looks correct: Using algorithm2e commands like \SetAlCapFnt or \SetAlCapNameSty also did not work for me, as they seem to set the font not just for the name of the algorithm, but for larger parts of the title. Redefining one of the internal commands of algorithm2e (see below), I managed to get the caption correct, but this does not work for the links created via \ref. \renewcommand{\algocf@captionref}{% \renewcommand{\fnum@algocf}[1]{\AlCapSty{\AlCapFnt\algorithmcfname\nobreakspace\sffamily\algocf@algocfref}}% \addtocounter{algocf}{-1}% \caption do a refstepcounter, so we restore the precedent value \let\old@thealgocf=\thealgocf\renewcommand{\thealgocf}{{\relsize{\algocf@refrelsize}\algocf@algocfref}}% \gdef\@currentlabel{\sffamily\algocf@algocfref}% let the label use the new ref }%

What I need to achieve is: A rectangle behind the first two letters of the chapter title, spanning up to the paper border (full bleeding over the margin) Change color of the first two letters of the chapter title. I have managed to do this with this specific chapter, but when I repeat the code with different words it gets all bugged, because my method is fine tuned to this word only. I used tikz for no special reason, maybe tcolorbox would be easier. How do I make it so it will work for every chapter without needing to readjust each time? \documentclass{memoir} \usepackage[% left=1.5in, right=1in, top=23.245mm, bottom=3cm ]{geometry} \usepackage{fontspec} \usepackage{moresize} % Configure Raleway: Map \textbf to the 'ExtraBold' font file \setmainfont{Raleway}[ UprightFont = *-Regular, ItalicFont = *-RegularItalic, BoldFont = *-ExtraBold, % \textbf uses Extra-Bold BoldItalicFont = *-ExtraBoldItalic % \textbf{\textit{...}} uses Extra-Bold Italic ] \usepackage{calc} \usepackage{tikz} \usetikzlibrary{positioning,calc} \usetikzlibrary{tikzmark, backgrounds} \usepackage{xcolor} \usepackage[explicit]{titlesec} \usepackage{xstring} \definecolor{cinza}{HTML}{918f90} \titlespacing*{\chapter}{0pt}{-70.5pt}{20pt} % Syntax: \titleformat{cmd}[shape]{format}{label}{sep}{before} \titleformat{\chapter}[display]% {\fontsize{42.5}{48}\selectfont\bfseries} % Format: 40pt, negrito {} % LABEL: Removes "Chapter 1" {0pt} % Separation: 0pt since no label {% \StrLeft{#1}{1}[\first]% Extract first letter \StrLeft{#1}{2}[\firsttwo]% Extract first two letters % % Print the first two letters (White) {\color{white}\MakeUppercase{\first}\StrGobbleLeft{\firsttwo}{1}}% % % CRITICAL FIX: Save the rest into \rest, then print \rest in cinza \StrGobbleLeft{#1}{2}[\rest]% {\color{cinza}\rest}% } \begin{document} \tikzmark{A}\tikzmark{B}\chapter{Apresentação} \AddToHookNext{shipout/background}{% \begin{tikzpicture}[remember picture,overlay] \begin{scope}[on background layer] % Define coordinates \coordinate (nA) at ([xshift=4.1em, yshift=-1.63cm]pic cs:A) ; \coordinate (sB) at ([xshift=9.1em]{pic cs:B} |- {current page.north}); % Draw the rectangle (it will now be behind text) \draw[fill=cinza, draw=none] (nA) rectangle (sB); \end{scope} \end{tikzpicture} } \end{document}

I have a document which calls a .tex file that contains a standalone TikZ image. Within that image, I cite several references in a rotated node. I have the MWE here: main.tex: \documentclass{article} \usepackage{tikz} \usepackage{standalone} \usepackage{hyperref} \begin{document} \input{Chapter1} \bibliographystyle{IEEEtran} \bibliography{references} \end{document} and Chapter 1.tex: \documentclass{standalone} \usepackage{hyperref} \usepackage{tikz} \begin{document} \begin{tikzpicture} \node[color=black,rotate=17] at (3.25,-2.35) {\tiny\cite{Test1,Test2,Test3,Test4,Test5}}; \end{tikzpicture} \end{document} Most answers online deal with hyperref to an image that's entirely rotated, in my case this is one node amongst many, and the picture is not rotated. I did not suppress the hitboxes in hyperref (by using \usepackage[breaklinks]{hyperref}) for demonstration purposes, but the problem (obviously) persists for both cases. Here's a screenshot of the resulting image, and its hitboxes: The issue is not only that the box does not rotate (which isn't a massive problem), it's more that it does not align vertically, especially the further along the node you go. Changing the citation to {\tiny\cite{Test1,Test2,Test3,Test4}\cite{Test5}} also does not adjust the box vertically: This may be a long shot, but is there a way to better align the hitbox with the node?

I want to create an environment that, when I use \begin{name}, will show me the commands I want to fill out, like what happens with the figure environment for example. I've tried using the \newenvironment command but I think I'm doing something incorrectly because when I use the environment I created, it just shows up empty. Edit for clarification: I want to create a macro similar to the figure environment, like, when we use the \begin{figure} the following code shows up: \begin{figure} \centering \includegraphics[width=0.5\linewidth]{} \caption{Caption} \label{fig:placeholder} \end{figure} I want to create a macro that does something similar, showing this code: \begin{tcolorbox}[tabularx=Y|Y|Y, title=Título da Tabela, center title] \textbf{} & \textbf{} & \textbf{} \\ \hline & & \\ \hline & & \\ \hline & & \\ \hline & & \\ \hline \end{tcolorbox} The issue I'm having is that, when I use the \newenvironment command, it creates the environment, but none of the content shows up. Does that make sense? Is that something that can be done?

It is needed to implement a command in Musixtex to do: showclefs like command in Musixtex, the basic code is as follow: \documentclass[% border={2pt -11pt 90pt 8pt},% left bottom right top %border=8pt varwidth]{standalone}% Ejemplo 26 \usepackage{tikz} \usetikzlibrary{positioning} \usepackage{musicography} \usepackage{musixtex} \input musixlyr \usepackage{amsmath} \usepackage{xcolor} \xdefinecolor{red-undar}{RGB}{179,35,79} \xdefinecolor{naranja}{RGB}{246,146,30} \xdefinecolor{conchevino}{RGB}{179,35,79} \xdefinecolor{plomoOscuro}{RGB}{52,52,52} \begin{document} \begin{music} \hsize=1.25\linewidth% \resetlyrics \setlyrics{AcordesB}{\B I \B II \B I \B II \B I \B IV \B IV6 \B II I\raisebox{0.5ex}{\bfseries\musFig[l]{{7} {\noFig}}} \B I \B VII\raisebox{-.1ex}{\bfseries\musFig[l]{{5} {6}}} \B I6 \B VII\raisebox{-.1ex}{\bfseries\musFig[l]{{3} {4}}} \B I6}% \setlyrics{AcordesX}{_ _ _ _ _ _ _ _} \setlyrics{AcordesY}{_ _ _ _ _ _ _ _} \setlyrics{AcordesZ}{_ _ _ _ _ _ _ _} \setlyrics{AcordesA}{\B 8J \B 5J \B 3M \B 3m \B 6M \B 6m \B 5 _} %\setsongraise{1}{1.5cm} %\setsongraise{2}{2.5cm} \lyrraisemulti{1}{2}{a -1.9cm} \font\A=phvb8t at 10pt% added for letter type. \font\B=phvb8t at 13pt% added for letter type. \parindent0mm \sepbarrules \generalsignature{0} %\generalmeter{\meterfrac{2}2} \instrumentnumber{1} \interstaff{10}%espacio entre pentagramas del piano \setclef{1}{61}%Clave de Do en 1ra linea \setstaffs1{2}% \nobarnumbers% \startpiece% \A\assignlyricsmulti{1}{2}{AcordesA}%,AcordesX,AcordesY,AcordesB} %\A\assignlyricsmulti{1}{1}{AcordesB}%,AcordesX,AcordesY,AcordesB} \Notes\hqsk\wh{J}\zcharnote{31}{\hspace{-3.5cm}\begin{tikzpicture} \node (point) at (0,0)[text width=26mm,align=center, fill=naranja!10, inner sep=2pt, draw=naranja, line width=1.5pt] {\textcolor{red-undar}{\B\textbf{Permitido 8J}}}; \end{tikzpicture}}|\hqsk\wh{j}\en\doublebar% \setclef{1}{61}\changeclefs% \Notes\wh{J}\zcharnote{31}{\hspace{-3.75cm}\begin{tikzpicture} \node (point) at (0,0)[text width=26mm,align=center, fill=naranja!10, inner sep=2pt, draw=naranja, line width=1.5pt] {\textcolor{red-undar}{\B\textbf{Permitido 5J}}}; \end{tikzpicture}}|\wh{g}\en\doublebar% \Notes\wh{J}\zcharnote{31}{\hspace{-3.75cm}\begin{tikzpicture} \node (point) at (0,0)[text width=26mm,align=center, fill=naranja!10, inner sep=2pt, draw=naranja, line width=1.5pt] {\textcolor{red-undar}{\B\textbf{Permitido 3M}}}; \end{tikzpicture}}|\wh{l}\en% \alaligne% \Notes\wh{a}\zcharnote{31}{\hspace{-3.75cm}\begin{tikzpicture} \node (point) at (0,0)[text width=26mm,align=center, fill=naranja!10, inner sep=2pt, draw=naranja, line width=1.5pt] {\textcolor{red-undar}{\B\textbf{Permitido 3m}}}; \end{tikzpicture}}|\wh{j}\en\doublebar% %\setclef18\zchangeclefs % apply empty clef (no space) \setclef{1}{63}\changeclefs% \Notes\wh{M}\zcharnote{31}{\hspace{-3.75cm}\begin{tikzpicture} \node (point) at (0,0)[text width=26mm,align=center, fill=naranja!10, inner sep=2pt, draw=naranja, line width=1.5pt] {\textcolor{red-undar}{\B\textbf{Permitido 6M}}}; \end{tikzpicture}}|\wh{d}\en\doublebar% \Notes\wh{L}\zcharnote{31}{\hspace{-3.75cm}\begin{tikzpicture} \node (point) at (0,0)[text width=26mm,align=center, fill=naranja!10, inner sep=2pt, draw=naranja, line width=1.5pt] {\textcolor{red-undar}{\B\textbf{Permitido 6m}}}; \end{tikzpicture}}|\wh{c}\en\setdoubleBAR% \nolyr% \lyricsoff% \endpiece \end{music} \end{document} the current output is as follow: The desired output is as follow:

I have a table to which I'd like to add a curved arrow (with an arrowhead at one end) running outside the table. The line will originate at the upper left portion of a table and end with the arrow pointing at the lower left portion. Another similar arrow will be outside the lower right side of the table and end pointing at the upper right side. I'd like some text to follow the curve of the arrows on each side of the table. The text for the left arrow will say: "Gives rise to the irascible". The text on the right will say: "Resolves in the concupiscible". Here's a MWE I've compiled with LuaLaTeX. \documentclass[12pt]{memoir} \addtolength\tabcolsep{.5in} \renewcommand\arraystretch{1.5} \begin{document} \begin{center} \begin{tabular}{c|c} \hline\hline {\scshape Good}& {\scshape Evil}\\\hline\hline\\[-9pt] love & hate \\\hline desire & avoid \\\hline joy & sad \\\hline\hline\\[-9pt] hope & bold \\\hline despair & fear \\\hline\hline\\[-9pt] & anger \end{tabular} \end{center} \end{document}

I want to write a robust code to write equations solving with vertical bar. I started with the last answer of this. My MWE is copied below. The problem is that the code is not robust (see picture: e.g. the length of the bar is fixed if you add more lines, but maybe some other issues that I have not spotted yet). At best, I would like a command \resolutionstep{...}{...} which would reproduce the picture adapting automatically the line of the equation, so something like: \begin{equation/array} \resolutionstep{3x+2{1}{-2} \resolutionstep{3x}{-1}{\div 3} \resolutionstep{x}{-\frac 13}{} \end{equation/array} Does any one know a good package/code to improve this? Thanks! \documentclass{article} \usepackage{showframe} \renewcommand{\ShowFrameLinethickness}{0.3pt} \usepackage{eqparbox} \usepackage{amsmath,array} \begin{document} blablabla \begin{alignat}{2} \qquad2x+2 &= 7x+3 &\hspace{6em}\smash{\rule[-5\baselineskip]{0.5pt}{6\baselineskip}} \qquad-2 & \\ 2x &= 7x+1 & -7 x & \\ -5x &= 1 &\div(-5) & \\ -5x &= 1 &\div(-5) & \\ -5x &= 1 &\div(-5) & \\ -5x &= 1 &\div(-5) & \\ x &= \boxed{-\frac{1}{5}} & & \end{alignat} \end{document}

My code are: \documentclass{article} \usepackage{array} \usepackage{tabularray} \UseTblrLibrary{booktabs} \begin{document} \NewColumnType{W}[1]{>{\raggedright\hangindent=1em\arraybackslash}Q[wd=#1]}% %\SetTblrInner{rowsep=0pt,row{1} = {l,b}} \SetTblrInner{rows={abovesep=0pt,belowsep=0pt},row{1} = {l,b}} \heavyrulewidth=0.5pt \lightrulewidth=0.5pt \cmidrulewidth=0.5pt \belowrulesep=14pt \belowbottomsep=14pt \aboverulesep=14pt \abovetopsep=10pt \cmidrulesep=\doublerulesep \cmidrulekern=.5em %\begin{tblr}{@{}XW{20pc}@{}} Test for tblr \begin{tblr}{colspec = {@{}XW{20pc}@{}}, row{1} = {l,b}} \toprule \SetCell[c=1]{l} Variable & \SetCell[c=1]{l} Sources\break Bottom\break test\\ \midrule \SetCell[c=2]{c} \textit{Supply variables}\\ Entry of new nonprofits & The influence of industry structure on the countries innovation capacity has been examined under three types of agglomeration externalities\\ Nonprofit employees & The influence of industry structure on the countries innovation capacity has been examined under three types of agglomeration externalities\\ Nonprofit financials & The influence of industry structure on the countries innovation capacity has been examined under three types of agglomeration externalities\\ \bottomrule \end{tblr} \end{document} already I gave some large value of above and below space for all rules (e.g., \toprule, etc.) but nothing was affected, how can I fix the space (need to fix 6pt white space for all rules)

I have the following code: \documentclass{article} \usepackage{fontspec} \setmonofont{cmun}[ Extension = .otf, UprightFont = *btl, BoldFont = *tb, ItalicFont = *bto, BoldItalicFont = *tx, HyphenChar = None] \begin{document} Hello \texttt{+} world \texttt{-} and everyone! Hello \texttt{\char92 CJKsout+} world \texttt{\char92 CJKsout-} and everyone! \end{document} It gives the unexpected baseline of + and -... Any suggestions? Edited The original case was I want to illustrate two commands: \CJKsout+ \CJKsout- both in xeCJKfntef package. If they are put together, that was in bad looking, if you don't mind to read Chinese, you could see here.

I am trying to create a latex layout for a cookbox, that I want to make. I have trouble however, trying to create 2 textboxes right next to each other as you can see. In my layout I create 2 minipages next to each other and the headlines of them look fine, however the text does not quite match what I want. First of all: the lines of the left box do not break, they break when the text reaches the very end of the page. Secondly, the text of the left box starts way below the title, right under the list of the right box? And thirdly, I defined "Zubereitung" which means preparation as #8 and "Zuaten" (ingredients) as #9, in my file for the recipe I put the instructions in #8 just like in the layout but it appears under the wrong one? I could just change the headlines, however I try to understand why that happens. Please help, it is driving me crazy, thanks!! I thought about trying parbox instead of minipage but I have also read, that you can not use enumerate in parbox? How can I make the 2 boxes "Zubereitung" (preparation) and Zutaten "ingredients" look clean next to each other?? \usepackage[a4paper,margin=2.2cm]{geometry} \usepackage{graphicx} \usepackage{xcolor} \usepackage{fontawesome5} \usepackage{parskip} \usepackage{tcolorbox} \usepackage{titlesec} % Keine Kapitelnummern \titleformat{\chapter}[display] {\Huge\bfseries} {} {0pt} {\Huge} % Kopf- und Fußzeilen ausschalten \pagestyle{plain} \definecolor{recipegreen}{RGB}{39,90,48} %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% \newcommand{\recipe}[9]{% \typeout{TEST TEST TEST} \clearpage \thispagestyle{empty} %========================================================== % Oberer Teil %========================================================== \noindent \begin{minipage}[t]{0.58\textwidth} \vspace{0pt} \includegraphics[ width=\linewidth, height=0.50\textheight, keepaspectratio ]{#2} \end{minipage} \hfill \begin{minipage}[t]{0.37\textwidth} \vspace{0pt} {\Huge\bfseries\color{recipegreen} #1} \vspace{1cm} {\large\faClock\quad #3} \vspace{0.4cm} {\large\faFire\quad #4} \vspace{0.4cm} {\large\faUserFriends\quad #5} \vspace{0.4cm} {\large\faGlobe\quad #6} \vspace{1cm} \begin{tcolorbox}[ colback=gray!8, colframe=gray!20, boxrule=0.3pt, arc=2mm] #7 \end{tcolorbox} \end{minipage} \vspace{1cm} %========================================================== % Unterer Teil %========================================================== \noindent \begin{minipage}[t]{0.58\textwidth} {\Large\bfseries Zubereitung} \vspace{0.5cm} #8 \end{minipage}\hfill \begin{minipage}[t]{0.37\textwidth} {\Large\bfseries Zutaten} \vspace{0.5cm} #9 \end{minipage} } \recipe {Shakshuka} {rezepte/shakshuka.jpg} {10 Minuten} {20 Minuten} {2 Personen} {Naher Osten} {Ein Frühstück das aus den mittleren Osten stammt. Es basiert auf einer gewürzten Tomaten-Paprika Basis mit gekochten Eiern.} { \begin{enumerate} \item schneiden daus idasdasdadas das das das ads das dassad \item kochen \item essen \end{enumerate} } { \begin{itemize} \item 1 Paprika das adsad s das das das das das das das ads sda das das dasd asd as da dsa dasd das das das dasd asd as dasd \item 3 Tomaten \item 5 Eier \end{itemize} }